Consider two ionic compounds A and B. A has a larger lattice energy than B. Which of the two compounds is more stable?

Short Answer

Expert verified
Compound A is more stable as it has a higher lattice energy than compound B.

Step by step solution

01

Understanding of Lattice Energy

Lattice energy is a measure of the energy required to separate one mole of an ionic solid into its constituent ions in gaseous form. This energy gives an indication of how strong the forces are between the ions in the ionic lattice. The greater this energy, the stronger the forces and the more tightly the ions are held together.
02

Linking Lattice Energy and Stability

Stability of an ionic compound is directly related to its lattice energy. High lattice energy means the ions are held together strongly, making it difficult to separate them. This implies that these compounds will be highly stable and will not readily decompose.
03

Identifying the More Stable Compound

Given that compound A and B are ionic in nature and compound A has a greater lattice energy than B, it means that A's ions are held more tightly in the lattice structure. Therefore, it's safe to conclude that compound A is more stable than compound B due to its higher lattice energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Compounds
When studying chemistry, one particular type of chemical species often encountered are ionic compounds. These are formed when atoms of different elements transfer electrons between them, leading to the creation of positively charged ions (cations) and negatively charged ions (anions). This electron transfer typically occurs between metals and non-metals. Metals tend to lose electrons and form cations, while non-metals tend to gain electrons to form anions.

The resulting electrostatic attraction between these oppositely charged ions creates a bond known as an ionic bond. This bonding leads to the formation of a structured array of ions known as an ionic lattice, which endows the ionic compound with a range of specific properties including high melting and boiling points, and the ability to conduct electricity when melted or dissolved in water. Due to these properties, ionic compounds are useful in various applications, ranging from household salts like sodium chloride to the magnesium used in firework sparkles.
Chemical Stability
The term chemical stability refers to the propensity of a substance to maintain its chemical composition and not react or change over time under specified conditions. It is a vital concept in chemistry as it dictates how a substance will behave when subjected to environmental factors such as temperature, pressure, or the presence of other chemicals.

A chemically stable compound resists decomposing or reacting, which is a desirable attribute for materials used in construction, pharmaceuticals, and food additives, where longevity and predictability are crucial. Factors that contribute to chemical stability include the strength of the bonds within a molecule and the energy required to break them. Ionic compounds are typically considered stable because the ionic bonds are relatively strong due to the high lattice energy, effectively resisting spontaneous breakdown.
Ionic Lattice
In the context of ionic compounds, an ionic lattice is a highly ordered three-dimensional structure consisting of alternating positive and negative ions arranged in a repeating pattern. This lattice formation is the physical manifestation of the ionic bonds that occur as a result of the electrostatic forces of attraction between the ions.

The stability and physical characteristics of an ionic compound are heavily influenced by the lattice energy of the ionic lattice. The lattice energy must be overcome to break the lattice apart and melt the compound or dissolve it in a solvent. A higher lattice energy indicates a more robust lattice, which in turn imparts greater melting points, boiling points, and overall stability to the compound. Understanding the concept of lattice energy is critical for analyzing not only the stability but also the solubility and hardness of various ionic compounds.

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Most popular questions from this chapter

Consider the dissolution of an ionic compound such as potassium fluoride in water. Break the process into the following steps: separation of the cations and anions in the vapor phase and the hydration of the ions in the aqueous medium. Discuss the energy changes associated with each step. How does the heat of solution of \(\mathrm{KF}\) depend on the relative magnitudes of these two quantities? On what law is the relationship based?

On what law is the first law of thermodynamics based? Explain the sign conventions in the equation \(\Delta U=q+w\)

Which of the following does not have \(\Delta H_{\mathrm{f}}^{\circ}=0\) at \(25^{\circ} \mathrm{C} ?\) \(\begin{array}{lllll}\text { He }(g) & \text { Fe }(s) & \text { Cl }(g) & \text { S }_{8}(s) & \text { O }_{2}(g) & \text { Br }_{2}(l)\end{array}\)

What is meant by the standard enthalpy of a reaction?

lime is a term that includes calcium oxide (CaO, also called quicklime) and calcium hydroxide \(\left[\mathrm{Ca}(\mathrm{OH})_{2},\right.\) also called slaked lime \(] .\) It is used in the steel industry to remove acidic impurities, in airpollution control to remove acidic oxides such as \(\mathrm{SO}_{2}\), and in water treatment. Quicklime is made industrially by heating limestone \(\left(\mathrm{CaCO}_{3}\right)\) above \(2000^{\circ} \mathrm{C}:\) $$ \begin{array}{r} \mathrm{CaCO}_{3}(s) \longrightarrow \mathrm{CaO}(s)+\mathrm{CO}_{2}(g) \\ \Delta H^{\circ}=177.8 \mathrm{~kJ} / \mathrm{mol} \end{array} $$ Slaked lime is produced by treating quicklime with water: $$ \begin{array}{r} \mathrm{CaO}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{Ca}(\mathrm{OH})_{2}(s) \\ \Delta H^{\circ}=-65.2 \mathrm{~kJ} / \mathrm{mol} \end{array} $$ The exothermic reaction of quicklime with water and the rather small specific heats of both quicklime \(\left(0.946 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)\) and slaked lime \(\left(1.20 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)\) make it hazardous to store and transport lime in vessels made of wood. Wooden sailing ships carrying lime would occasionally catch fire when water leaked into the hold. (a) If a \(500-\mathrm{g}\) sample of water reacts with an equimolar amount of \(\mathrm{CaO}\) (both at an initial temperature of \(25^{\circ} \mathrm{C}\) ), what is the final temperature of the product, \(\mathrm{Ca}(\mathrm{OH})_{2} ?\) Assume that the product absorbs all of the heat released in the reaction. (b) Given that the standard enthalpies of formation of \(\mathrm{CaO}\) and \(\mathrm{H}_{2} \mathrm{O}\) are \(-635.6 \mathrm{~kJ} / \mathrm{mol}\) and \(-285.8 \mathrm{~kJ} / \mathrm{mol}\) respectively, calculate the standard enthalpy of formation of \(\mathrm{Ca}(\mathrm{OH})_{2}\)

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