When two atoms collide, some of their kinetic energy may be converted into electronic energy in one or both atoms. If the average kinetic energy is about equal to the energy for some allowed electronic transition, an appreciable number of atoms can absorb enough energy through an inelastic collision to be raised to an excited electronic state. (a) Calculate the average kinetic energy per atom in a gas sample at \(298 \mathrm{~K}\). (b) Calculate the energy difference between the \(n=1\) and \(n=2\) levels in hydrogen. (c) At what temperature is it possible to excite a hydrogen atom from the \(n=1\) level to \(n=2\) level by collision? [The average kinetic energy of 1 mole of an ideal gas is \(\left.\left(\frac{3}{2}\right) R T .\right]\)

Short Answer

Expert verified
The average kinetic energy per atom at 298 K is approximately \(6.207 * 10^{-21}\) J. The energy difference between the n=1 and n=2 levels is approximately \(1.89 * 10^{-19}\) J. The temperature required for excitation from n=1 to n=2 by collision is approximately \(9.147 * 10^{4}\) K.

Step by step solution

01

Calculate the Average Kinetic Energy per Atom

You can start doing this by utilizing the provided formula for the average kinetic energy of 1 mole of an ideal gas \(\left.\left(\frac{3}{2}\right) R T .\right]\). Here R is the universal gas constant (8.314 J/mol.K), and T is the temperature in Kelvin. By inserting the given values into the formula \(K =\left.\left(\frac{3}{2}\right) R T = \left.\left(\frac{3}{2}\right) * 8.314 * 298 .\right]\) you can calculate the average kinetic energy. However, this is the energy for 1 mole of atoms. To find the energy per atom, you need to divide this result by Avogadro's number \(6.022 * 10^{23}\).
02

Calculate the Energy Difference between Electron Energy Levels

The energy difference \(E\) between the n=1 and n=2 levels in hydrogen is calculated by using the formula \(E = 13.6 (1/1^2 - 1/2^2)\). The energy obtained will be in electron volts (eV). To match the units with those used for kinetic energy, you'll need to convert this result to joules using the fact that 1 eV = \(1.6 * 10^{-19}\) J.
03

Determine the Temperature for Excitation via Collision

The temperature at which a hydrogen atom can be excited from the n=1 level to n=2 by collision is the temperature at which the average kinetic energy per atom equals the energy difference between the two levels. By setting these two values equal and solving for T in the formula for kinetic energy, you can find the required temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Kinetic Energy Calculation
Understanding the average kinetic energy of atoms in a gas can provide insight into their thermal motion and potential to cause various physical phenomena. When we talk about average kinetic energy in the context of gas molecules, it is the energy possessed by the molecules due to their motion. The formula to calculate the average kinetic energy of one mole of an ideal gas is \[ K = \left(\frac{3}{2}\right) RT \] where \(R\) is the universal gas constant (8.314 J/mol.K), and \(T\) is the temperature in Kelvin. After finding the average kinetic energy for a mole, to calculate the energy per atom, the result is divided by Avogadro's number (\(6.022 \times 10^{23}\)), since a mole contains that many atoms.

To improve understanding, keep in mind that this calculation assumes ideal gas behavior and ignores interactions between atoms, which is a reasonable approximation at high temperatures and low pressures.
Electron Energy Level Transitions
Electrons in atoms occupy specific energy levels. When an electron transitions between these energy levels, it either absorbs or emits energy. These energy level transitions can be quantified using the Bohr model for the hydrogen atom. The energy difference between the \(n=1\) and \(n=2\) levels is given by \[ E = -13.6 \left(\frac{1}{1^2} - \frac{1}{2^2}\right) eV \] because electrons in lower energy states (closer to the nucleus) have more negative energy. In order to compare this energy difference with kinetic energy, it needs to be converted to joules, as the energy is originally given in electronvolts (eV). The conversion is done using the fact that 1 eV = \(1.6 \times 10^{-19}\) J. This information allows us to predict spectral lines in hydrogen and gain understanding of processes such as absorption and emission of light, as well as other quantum mechanical phenomena.

To facilitate comprehension, providing visual aids of energy level diagrams may help to illustrate how these transitions manifest in an atomic spectrum.
Excitation Temperature of Hydrogen Atom
The excitation temperature of a hydrogen atom is the temperature at which it has enough thermal kinetic energy to undergo a transition from its ground state (\(n=1\)) to an excited state (\(n=2\)). This transition occurs when the atom collides with another atom or particle, transferring kinetic energy to the electron, enabling it to jump to the higher energy level. The condition for this excitation through collision is that the average kinetic energy of the gas atoms must be comparable to the energy required for the electron transition. As solved in the exercise, equating the average kinetic energy per atom with the energy need for the \(n=1\) to \(n=2\) transition allows for the calculation of the necessary temperature.

Incorporating different methods of visualizing or simulating the process can enhance understanding, such as animations showing a thermal collision leading to electron excitation. Remember, the exact temperature calculated is a theoretical value for an ideal gas and actual conditions may vary due to various physical factors.
Inelastic Collision in Atoms
An inelastic collision between atoms is a type of collision where part of the kinetic energy is not conserved as kinetic energy but is transformed into other forms of energy, such as electronic energy, resulting in the excitation of electrons. In the context of our exercise, when two hydrogen atoms collide, if the kinetic energy is similar to the energy difference between the electron energy levels, the collision can result in an electron transition from a lower to a higher energy level.

These inelastic collisions are fundamental to understanding how atoms interact and influence each other in a gas. They play a key role in phenomena such as absorption and emission spectra in gases, and the concept also extends to other fields like particle physics and material sciences. Clear and simple explanations, possibly coupled with an interactive model, can reinforce the principle that not all collisions result in the conservation of kinetic energy, highlighting the diversity in atomic interactions.

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Most popular questions from this chapter

In a photoelectric experiment a student uses a light source whose frequency is greater than that needed to eject electrons from a certain metal. However, after continuously shining the light on the same area of the metal for a long period of time the student notices that the maximum kinetic energy of ejected electrons begins to decrease, even though the frequency of the light is held constant. How would you account for this behavior?

Calculate the energies needed to remove an electron from the \(n=1\) state and the \(n=5\) state in the \(\mathrm{Li}^{2+}\) ion. What is the wavelength (in \(\mathrm{nm}\) ) of the emitted photon in a transition from \(n=5\) to \(n=1 ?\) The Rydberg constant for hydrogen like ions is \((2.18 \times\) \(\left.10^{-18} \mathrm{~J}\right) Z^{2},\) where \(Z\) is the atomic number.

Indicate which of the following sets of quantum numbers in an atom are unacceptable and explain why: \((a)\left(1,0, \frac{1}{2}, \frac{1}{2}\right),(b)\left(3,0,0,+\frac{1}{2}\right),(c)\left(2,2,1,+\frac{1}{2}\right)\) (d) \(\left(4,3,-2,+\frac{1}{2}\right),\) (e) (3,2,1,1)

The UV light that is responsible for tanning the skin falls in the 320 - to 400 -nm region. Calculate the total energy (in joules) absorbed by a person exposed to this radiation for \(2.0 \mathrm{~h}\), given that there are \(2.0 \times 10^{16}\) photons hitting Earth's surface per square centimeter per second over a 80-nm (320 nm to \(400 \mathrm{nm}\) ) range and that the exposed body area is \(0.45 \mathrm{~m}^{2}\). Assume that only half of the radiation is absorbed and the other half is reflected by the body. (Hint: Use an average wavelength of \(360 \mathrm{nm}\) in calculating the energy of a photon.

Why do the \(3 s, 3 p,\) and \(3 d\) orbitals have the same energy in a hydrogen atom but different energies in a many-electron atom?

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