Give the values of the four quantum numbers of an electron in the following orbitals: (a) \(3 s,\) (b) \(4 p\), (c) \(3 d\).

Short Answer

Expert verified
Quantum numbers for (a) 3s are n=3, l=0, ml=0, ms=+1/2, for (b) 4p are n=4, l=1, ml=-1 to +1, ms=+1/2, and for (c) 3d are n=3, l=2, ml=-2 to +2, ms=+1/2.

Step by step solution

01

Determine Quantum Numbers for 3s

For any s orbital, the azimuthal quantum number (l) = 0, and the magnetic quantum number (ml) = 0. The spin quantum number (ms) can be either +1/2 or -1/2, typically we just choose +1/2 unless specified otherwise. Hence, the four quantum numbers for the 3s orbital are: n=3, l=0, ml=0, ms=+1/2.
02

Determine Quantum Numbers for 4p

For any p orbital, the azimuthal quantum number (l) = 1. The magnetic quantum number (ml) can be -l to +l, hence ml can be -1, 0, or +1. The spin quantum number (ms) can be either +1/2 or -1/2, typically we just choose +1/2 unless specified otherwise. Hence, the four quantum numbers for the 4p orbital are: n=4, l=1, ml can be any between -1 and +1, ms=+1/2.
03

Determine Quantum Numbers for 3d

For any d orbital, the azimuthal quantum number (l) = 2. The magnetic quantum number (ml) can be -l to +l, hence ml can be -2, -1, 0, +1, or +2. The spin quantum number (ms) can be either +1/2 or -1/2, typically we just choose +1/2 unless specified otherwise. Hence, the four quantum numbers for the 3d orbital are: n=3, l=2, ml can be any between -2 and +2, ms=+1/2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Understanding the arrangement of electrons in an atom is key to chemistry and physics. This arrangement, known as electron configuration, describes the distribution of electrons among various atomic orbitals. Electrons fill orbitals starting with the lowest energy level before moving to higher levels, following principles such as the Pauli exclusion principle and Hund's rule.

For example, the 3s orbital is part of the third energy level (n=3) and is an 's' type orbital (l=0), where 's' stands for sharp. The 4p orbital represents the fourth energy level with a 'p' type orbital (l=1), where 'p' denotes the principal. The 3d orbital refers to the third energy level with a 'd' type orbital (l=2), where 'd' means diffuse. These labels help describe the energy and shape of the orbitals where electrons are likely to be found.
Atomic Orbitals
Atoms are not just simple balls with electrons moving randomly around them; rather, electrons exist in specific areas called atomic orbitals. These orbitals are like clouds around the nucleus where an electron is likely to be found. Each orbital has a unique shape and energy associated with it, dictated by quantum numbers.

There are different types of orbitals - s, p, d, and f. These letters indicate the shape and complexity of the electron cloud. The s orbital is spherical, p orbitals are dumbbell-shaped, d orbitals are clover-shaped, and f orbitals are even more complex. The understanding of these shapes is important for grasping why certain elements behave the way they do in chemical reactions.
Azimuthal Quantum Number
Deepening our dive into quantum mechanics, we encounter the azimuthal quantum number, denoted as l. It is responsible for determining the shape of an atomic orbital and contributes to the energy level of that orbital within a given principal energy level. The value of l ranges from 0 to n - 1, where n is the principal quantum number.

For s orbitals, l is always 0; for p orbitals, l is 1; for d orbitals, l becomes 2, and so on. The azimuthal quantum number is crucial because it helps explain why there are different shapes within the electron clouds, leading to the various orbital types we see in atoms.
Magnetic Quantum Number
When discussing orbitals, the magnetic quantum number, represented as ml, comes into play. This quantum number specifies the orientation of the orbital in space. For each value of the azimuthal quantum number l, ml takes on values ranging from -l to +l, including zero. This means that for s orbitals with l of 0, there is only one possible value of ml - zero. However, for p orbitals with an l of 1, ml can be -1, 0, or +1, signifying three different orientations in space.

The concept of the magnetic quantum number is essential as it helps to determine the number of orbitals in a given subshell and their arrangement in an atom. This information is not only important for chemists but also for many technologies, such as MRI machines, which rely on our understanding of magnetic quantum properties.

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Most popular questions from this chapter

Write the ground-state electron configurations for the following elements: \(\mathrm{B}, \mathrm{V}, \mathrm{Ni}, \mathrm{As}, \mathrm{I},\) Au.

(a) An electron in the ground state of the hydrogen atom moves at an average speed of \(5 \times 10^{6} \mathrm{~m} / \mathrm{s} .\) If the speed is known to an uncertainty of 1 percent, what is the uncertainty in knowing its position? Given that the radius of the hydrogen atom in the ground state is \(5.29 \times 10^{-11} \mathrm{~m},\) comment on your result. The mass of an electron is \(9.1094 \times 10^{-31} \mathrm{~kg}\) (b) A 3.2-g Ping-Pong ball moving at 50 mph has a momentum of \(0.073 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s} .\) If the uncertainty in measuring the momentum is \(1.0 \times 10^{-7}\) of the momentum, calculate the uncertainty in the Ping-Pong ball's position.

Consider the following energy levels of a hypothetical atom: \(E_{4}\) \(-1.0 \times 10^{-19} \mathrm{~J}\) \(E_{3}\) \(--5.0 \times 10^{-19} \mathrm{~J}\) \(E_{2}\) \(--10 \times 10^{-19} \mathrm{~J}\) \(E_{1}\) \(-15 \times 10^{-19} \mathrm{~J}\) (a) What is the wavelength of the photon needed to excite an electron from \(E_{1}\) to \(E_{4} ?\) (b) What is the energy (in joules) a photon must have in order to excite an electron from \(E_{2}\) to \(E_{3} ?\) (c) When an electron drops from the \(E_{3}\) level to the \(E_{1}\) level, the atom is said to undergo emission. Calculate the wavelength of the photon emitted in this process.

$$ \begin{array}{lccccc} \lambda(\mathrm{nm}) & 405 & 435.8 & 480 & 520 & 577.7 \\ \hline \mathrm{KE}(\mathrm{J}) & 2.360 \times & 2.029 \times & 1.643 \times & 1.417 \times & 1.067 \times \\ & 10^{-19} & 10^{-19} & 10^{-19} & 10^{-19} & 10^{-19} \end{array} $$ A ruby laser produces radiation of wavelength \(633 \mathrm{nm}\) in pulses whose duration is \(1.00 \times 10^{-9} \mathrm{~s}\). (a) If the laser produces \(0.376 \mathrm{~J}\) of energy per pulse, how many photons are produced in each pulse? (b) Calculate the power (in watts) delivered by the laser per pulse. \((1 \mathrm{~W}=1 \mathrm{~J} / \mathrm{s})\)

Determine the maximum number of electrons that can be found in each of the following subshells: \(3 s\), \(3 d, 4 p, 4 f, 5 f\)

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