The ground-state electron configurations listed here are incorrect. Explain what mistakes have been made in each and write the correct electron configurations. Al: \(1 s^{2} 2 s^{2} 2 p^{4} 3 s^{2} 3 p^{3}\) \(\mathrm{B}: 1 s^{2} 2 s^{2} 2 p^{5}\) \(\mathrm{F}: 1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6}\)

Short Answer

Expert verified
The correct electron configurations are: Aluminium: \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{1}\), Boron: \(1 s^{2} 2 s^{2} 2 p^{1}\), Fluorine: \(1 s^{2} 2 s^{2} 2 p^{6}\).

Step by step solution

01

Correcting the Configuration for Aluminium

For Aluminium (Al), it's given as \(1 s^{2} 2 s^{2} 2 p^{4} 3 s^{2} 3 p^{3}\). However, if you check the periodic table, you'll find that Aluminium has an atomic number of 13, which means it has 13 electrons. The given configuration adds up to \(2+2+4+2+3=13\) electrons. Therefore, the initial count is correct but the placement of the electrons in \(2 p^{4}\) is not accurate. The configuration should be \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{1}\) following the rule that p-orbitals can at maximum hold 6 electrons.
02

Correcting the Configuration for Boron

For Boron (B), the configuration provided is \(1 s^{2} 2 s^{2} 2 p^{5}\). Boron has an atomic number of 5 indicating 5 electrons. The given configuration adds up to 9 electrons which is incorrect. The correct electron configuration for Boron is \(1 s^{2} 2 s^{2} 2 p^{1}\).
03

Correcting the Configuration for Fluorine

Lastly, the presented configuration for Fluorine(F) is \(1 s^{2} 2 s^{2} 2 p^{6}\). Fluorine has an atomic number of 9 and the given configuration satisfies this with a total of \(2+2+5=9\) electrons. Therefore, the configuration for Fluorine is correct and no changes are required.

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