Write the formulas and names of the hydrides of the following second-period elements: \(\mathrm{Li}, \mathrm{C}, \mathrm{N}, \mathrm{O}, \mathrm{F}\) Predict their reactions with water.

Short Answer

Expert verified
The hydrides of Li, C, N, O, and F are \(\mathrm{LiH}\), \(\mathrm{CH4}\), \(\mathrm{NH3}\), \(\mathrm{H2O}\), \(\mathrm{HF}\) respectively. Lithium hydride reacts with water to produce lithium hydroxide and hydrogen gas. Methane generally does not react with water unless under high temperature/pressure and the presence of a catalyst, in which case it produces carbon dioxide and hydrogen gas. Ammonia reacts with water to form ammonium and hydroxide ions. Water does not react with itself under standard conditions. Hydrogen fluoride reacts with water to produce a strongly acidic solution of hydrofluoric acid.

Step by step solution

01

Identify the Elements and Write their Hydrides

First of all, identify these elements - lithium (Li), carbon(C), nitrogen (N), oxygen(O), and fluorine (F). Their respective hydrides are: lithium hydride (\(\mathrm{LiH}\)), methane (\(\mathrm{CH4}\)), ammonia (\(\mathrm{NH3}\)), water (\(\mathrm{H2O}\)), and hydrogen fluoride (\(\mathrm{HF}\)).
02

Predicting Their Reactions with Water

Lithium hydride reacts with water to produce hydrogen gas and lithium hydroxide (alkaline). The reaction is: \(\mathrm{LiH} + \mathrm{H2O} \rightarrow \mathrm{LiOH} + \mathrm{H2}\) \n Methane has limited reaction with water. In the presence of a catalyst, it can react with steam to produce carbon dioxide and hydrogen gas, represented by \(\mathrm{CH4} + \mathrm{H2O} \rightarrow \mathrm{CO2}+ 3\mathrm{H2}\). But as noted this only under high temperature and pressure and the presence of a catalyst. Under room temperature with water, there's essentially no reaction. \n Ammonia will react with water to form ammonium ion and hydroxide ion, a weakly basic solution. So: \(\mathrm{NH3} + \mathrm{H2O} \rightleftharpoons \mathrm{NH4+} + \mathrm{OH^-}\) \n Water, of course, will not react with itself under room conditions. \n Hydrogen fluoride will readily dissolve in water to give a solution of hydrofluoric acid, which is strongly acidic. \(\mathrm{HF} + \mathrm{H2O} \rightarrow \mathrm{H3O+} + \mathrm{F^-}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free