Most transition metal ions are colored. For example, a solution of \(\mathrm{CuSO}_{4}\) is blue. How would you show that the blue color is due to the hydrated \(\mathrm{Cu}^{2+}\) ions and not the \(\mathrm{SO}_{4}^{2-}\) ions?

Short Answer

Expert verified
The color test shows that the blue color of \(\mathrm{CuSO}_{4}\) solution is due to the \(\mathrm{Cu}^{2+}\) ions. This is because a solution of another compound containing \(\mathrm{SO}_{4}^{2-}\) ions but not \(\mathrm{Cu}^{2+}\) ions, such as \(\mathrm{Na}_{2}\mathrm{SO}_{4}\), is colorless.

Step by step solution

01

Identify a Similar Compound

Identify a compound containing \(\mathrm{SO}_{4}^{2-}\) ions but not \(\mathrm{Cu}^{2+}\) ions. For instance, \(\mathrm{Na}_{2}\mathrm{SO}_{4}\) could be a good example, as it contains \(\mathrm{SO}_{4}^{2-}\) ions but includes \(\mathrm{Na}^{+}\) instead of \(\mathrm{Cu}^{2+}\).
02

Test the Solution of the Similar Compound

Dissolve the chosen compound, in this case \(\mathrm{Na}_{2}\mathrm{SO}_{4}\), in water and observe the color of the solution. If the \(\mathrm{SO}_{4}^{2-}\) ions were contributing to color, this solution would also be colored.
03

Compare the colors

Compare the color of the \(\mathrm{Na}_{2}\mathrm{SO}_{4}\) solution with the color of the \(\mathrm{CuSO}_{4}\) solution. If the \(\mathrm{Na}_{2}\mathrm{SO}_{4}\) solution is colorless, that indicates the \(\mathrm{SO}_{4}^{2-}\) ions are not responsible for the blue color in \(\mathrm{CuSO}_{4}\), implying it's the \(\mathrm{Cu}^{2+}\) ions that cause it.

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