Explain why the electron affinity of nitrogen is approximately zero, while the elements on either side, carbon and oxygen, have substantial positive electron affinities.

Short Answer

Expert verified
The electron affinity of Nitrogen is nearly zero because it has a stable, half-filled electron configuration in its outer shell which would be disturbed by the addition of another electron. Carbon and Oxygen, which do not have this half-filled configuration, can accommodate an extra electron in the same orbital, resulting in a release of energy, and hence, have a positive electron affinity.

Step by step solution

01

Understand electron affinity

Electron affinity is the amount of energy released when an electron is added to a neutral atom. Atoms with a high electron affinity release energy when they gain electrons, whereas those with a low electron affinity do not release or may even need to absorb energy to accommodate an extra electron.
02

Recognize electron configuration in these elements

Carbon, in its ground state, has the electron configuration of 1s2, 2s2, 2p2. Nitrogen, in its ground state, has the electron configuration of 1s2, 2s2, 2p3. Finally, Oxygen has the electron configuration of 1s2, 2s2, 2p4. Understanding these configurations will lay the foundation for understanding their electron affinity.
03

Nitrogen's Special Case

Nitrogen has five electrons in its outer shell. This makes it half-filled and very stable due to its symmetry. If an electron was to be added, it would occupy a different 'orbital' in the same shell, still keeping it in the p-block, and would disturb the stable half-filled electron configuration. Due to this, it may need to absorb energy to accommodate the new electron, and hence has approximately zero electron affinity.
04

Compare with Carbon and Oxygen

On the other hand, Carbon and Oxygen do not have a half-filled electron configuration. Hence, they can still accommodate a new electron in the same orbital which would release energy, leading to a higher electron affinity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Understanding the electron configuration of an atom is crucial in explaining its chemical behavior, including electron affinity. The electron configuration details how electrons are distributed in an atom's orbitals. Electrons fill orbitals in a way that minimizes the energy of the atom, starting with the lowest energy levels.

Let’s take nitrogen as an example. It has an electron configuration of 1s2 2s2 2p3, which fills the 2p orbitals exactly to half. This half-filled state is known for its stability because it offers a favorable balance of electron repulsion and orbital occupation. When an added electron would disturb this stability, the atom may exhibit less desire to capture the electron, explaining nitrogen’s low electron affinity.

How does this relate to chemical stability? Atoms adopt electron configurations that confer stability. A fully or half-filled set of orbitals represents a particularly stable configuration. In contrast, other elements like carbon (1s2 2s2 2p2) and oxygen (1s2 2s2 2p4) have orbitals that are not half or fully filled, making them more inclined to accept an additional electron to move towards a more stable configuration, resulting in a release of energy – evidence of higher electron affinity.

This intricacy in electron distribution is integral in predicting how an atom will interact in chemical processes.
Periodic Trends
Periodic trends play a fundamental role in understanding why different elements exhibit the electron affinities they do. As you move across a period from left to right on the periodic table, the effective nuclear charge increases as protons are added to the nucleus, leading to a tighter hold on the valence electrons. This generally causes an increase in electron affinity, with some notable exceptions.

Nitrogen is a quintessential exception. Despite nitrogen being situated between carbon and oxygen in the periodic table, it does not have a higher electron affinity. This is because of its electron configuration, where the added electron would break the half-filled stability.

The periodic table patterns, however, are not absolute and can be influenced by atomic structure nuances. For instance, the added stability of a half-filled p-orbital in nitrogen overrides the expected trend. While understanding periodic trends offers a great starting point, it's the underlying atomic structure that ultimately dictates an atom's electron affinity.
Chemical Stability
Chemical stability is an attribute that describes an atom's resistance to change in its electron configuration. Elements strive for stability, often achieved through a full or half-filled valence shell, which in turn influences their chemical properties and reactions.

Nitrogen’s half-filled 2p orbital configuration provides it with considerable stability. Adding another electron would mean introducing electron-electron repulsions in a previously stable p-orbital, thus reducing stability. As a result, nitrogen's electron affinity is close to zero because the system requires additional energy to overcome the electron-electron repulsions and force the extra electron into a less favorable position. In contrast, elements that are not in such stable configurations, like carbon and oxygen, gain additional stability upon the addition of an electron and thus release energy.

Why is stability favored? Chemically stable configurations are less reactive and more resistant to forming compounds, which is why noble gases with complete valence shells are largely unreactive. An element’s pursuit of stability is a driving force in chemical reactions and is the underlying reason why atoms have varying affinities for additional electrons.

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Most popular questions from this chapter

(a) Define electron affinity. (b) Electron affinity measurements are made with gaseous atoms. Why? (c) Ionization energy is always a positive quantity, whereas electron affinity may be either positive or negative. Explain.

Explain why, for isoelectronic ions, the anions are larger than the cations.

The ionization energies of sodium (in \(\mathrm{kJ} / \mathrm{mol}\) ), starting with the first and ending with the eleventh, are 495.9,4560,6900,9540,13,400,16,600,20,120 \(25,490,28,930,141,360,170,000 .\) Plot the \(\log\) of ionization energy ( \(y\) axis) versus the number of ionization \((x\) axis \() ;\) for example, log 495.9 is plotted versus 1 (labeled \(I E_{1}\), the first ionization energy), \(\log 4560\) is plotted versus 2 (labeled \(I E_{2}\), the second ionization energy), and so on. (a) Label \(I E_{1}\) through \(I E_{11}\) with the electrons in orbitals such as \(1 s, 2 s, 2 p\) and \(3 s .\) (b) What can you deduce about electron shells from the breaks in the curve?

Arrange the following species in isoelectronic pairs: \(\mathrm{O}^{+}, \mathrm{Ar}, \mathrm{S}^{2-}, \mathrm{Ne}, \mathrm{Zn}, \mathrm{Cs}^{+}, \mathrm{N}^{3-}, \mathrm{As}^{3+}, \mathrm{N}, \mathrm{Xe}\)

A technique called photoelectron spectroscopy is used to measure the ionization energy of atoms. A sample is irradiated with UV light, and electrons are ejected from the valence shell. The kinetic energies of the ejected electrons are measured. Because the energy of the UV photon and the kinetic energy of the ejected electron are known, we can write $$ h \nu=I E+\frac{1}{2} m u^{2} $$ where \(\nu\) is the frequency of the UV light, and \(m\) and \(u\) are the mass and velocity of the electron, respectively. In one experiment the kinetic energy of the ejected electron from potassium is found to be \(5.34 \times 10^{-19} \mathrm{~J}\) using a UV source of wavelength \(162 \mathrm{nm} .\) Calculate the ionization energy of potassium. How can you be sure that this ionization energy corresponds to the electron in the valence shell (that is, the most loosely held electron)?

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