Match each of the elements on the right with its description on the left: (a) A pale yellow gas that reacts with water. (b) A soft metal that reacts with water to produce hydrogen. (c) A metalloid that is hard and has a high melting point. (d) A colorless, odorless gas. (e) A metal that is more reactive than iron, but does not corrode in air. Nitrogen \(\left(\mathrm{N}_{2}\right)\) Boron (B) Aluminum (Al) Fluorine \(\left(\mathrm{F}_{2}\right)\) Sodium (Na)

Short Answer

Expert verified
(a) Fluorine \(\left(\mathrm{F}_{2}\right)\), (b) Sodium (Na), (c) Boron (B), (d) Nitrogen \(\left(\mathrm{N}_{2}\right)\), (e) Aluminum (Al).

Step by step solution

01

Match elements with properties

Firstly, let's go through each element one by one and match its properties with the descriptions given. \n\n- Nitrogen \(\left(\mathrm{N}_{2}\right)\): This is a colourless, odourless gas, so it matches with description (d).\n- Boron (B): Boron is a metalloid, hard and has a high melting point, so it matches with description (c). \n- Aluminum (Al): This is a metal that is more reactive than iron but does not corrode in air. It matches description (e).\n- Fluorine \(\left(\mathrm{F}_{2}\right)\): Fluorine is a pale yellow gas that reacts with water, so it matches with description (a). \n- Sodium (Na): This is a soft metal that reacts with water to produce hydrogen. This matches with description (b).
02

Final Matching

Now, let's finalize the matches as per our analysis: \n\n(a) Fluorine \(\left(\mathrm{F}_{2}\right)\) \n(b) Sodium (Na) \n(c) Boron (B) \n(d) Nitrogen \(\left(\mathrm{N}_{2}\right)\)\n(e) Aluminum (Al).

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