In general, ionization energy increases from left to right across a given period. Aluminum, however, has a lower ionization energy than magnesium. Explain.

Short Answer

Expert verified
Aluminum has a lower ionization energy than magnesium despite being to the right of it on the periodic table due to the electron configuration. The outermost electron of Al resides in a 3p subshell which is farther from the nucleus and slightly shielded by the filled 3s^2 subshell compared to Mg's outer electrons. Consequently, less energy is required to remove this electron, resulting in a lower ionization energy for Al compared to Mg.

Step by step solution

01

Understanding the Positions of Aluminum and Magnesium

First, identify the positions of aluminum (Al) and magnesium (Mg) on the periodic table. Aluminum is in group 13 and magnesium is in group 2. Both are in the same period (period 3).
02

Looking into Electron Configuration

Determine the electron configurations for both Al and Mg. For magnesium (Mg), it is [Ne]3s^2 while for aluminum (Al), it is [Ne]3s^23p1. Magnesium's outer electrons are in the 3s subshell while aluminum's outer electron is in the 3p subshell.
03

Understanding the Effect of Electron Configuration on Ionization Energy

Understand that ionization energy is the amount of energy required to remove the outermost electron from an atom. From the electron configurations, magnesium's outer electrons are in the 3s subshell which is closer to the nucleus and therefore more tightly bound than the 3p subshell (where Al's outer electron resides). In addition, Al's 3p electron is also slightly shielded by the filled 3s^2 subshell. This means it requires less energy to remove the outermost electron from aluminum than from magnesium.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

The Periodic Table and Ionization Energy
The periodic table is a systematic arrangement of elements, ordered by their atomic numbers, electron configurations, and recurring chemical properties. Elements are placed in rows by increasing atomic number in a new row, also known as a period, when the outer electron shell is filled. Within each period, the ionization energy— the energy required to remove an electron from a gaseous atom or ion—typically increases as one moves from left to right. This trend is due to the increasing positive charge of the nucleus, which more strongly attracts the negatively charged electrons.

However, there are exceptions to this rule, such as the case with aluminum and magnesium. While magnesium has a higher ionization energy compared to aluminum, despite being to its left, it can be better understood by considering not just the position on the periodic table, but also the underlying electron configuration and the resulting atomic structure, which affect the force holding electrons in the atom.
Electron Configuration and its Influence on Ionization Energy
Electrons in an atom are found in regions called orbitals, and the pattern in which these orbitals are filled is known as the electron configuration. It significantly influences an atom's chemical behavior and properties, including ionization energy. For instance, magnesium's electron configuration is \[\text{[Ne]}3s^2\], meaning it has two electrons in the 3s subshell following the noble gas neon's configuration. On the other hand, aluminum, with an electron configuration of \[\text{[Ne]}3s^23p1\], has an additional electron in the 3p subshell. Electrons in the p subshell are generally farther from the nucleus and more shielded by electrons in the s subshell, which makes them easier to remove—hence, requiring less ionization energy.

In Al's case, the single 3p electron experiences a higher level of shielding by the filled 3s subshell as well as being naturally slightly further from the nucleus compared to Mg's 3s electrons, which explains Al's lower ionization energy.
Atomic Structure's Role in Ionization Energy
The atomic structure denotes the distribution of electrons around the nucleus and the forces between them and the nucleus. It shapes the atom's characteristics, such as ionization energy. The closer an electron is to the nucleus, the stronger the electrostatic forces that bind it, implying a higher ionization energy required to remove the electron.

For magnesium, the 3s electrons are closer to the nucleus and experience a stronger pull from it compared to aluminum's 3p electron. Although both elements are in the same period, the different types of orbitals in which the outermost electrons reside affect their atomic structures. The 3s subshell is more penetrating, meaning its electrons can get closer to the nucleus, compared to the 3p subshell, whose electrons are generally held less tightly. Thus, the differences in the atomic structures of Mg and Al explain why, despite periodic trends, there is a decrease in ionization energy from magnesium to aluminum.

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Most popular questions from this chapter

Write a balanced equation that predicts the reaction of rubidium (Rb) with (a) \(\mathrm{H}_{2} \mathrm{O}(l)\) (b) \(\mathrm{Cl}_{2}(g)\) (c) \(\mathrm{H}_{2}(g)\)

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List all the common ions of representative elements and transition metals that are isoelectronic with Ar.

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