Write equations representing the following processes: (a) The electron affinity of \(\mathrm{S}^{-}\) (b) The third ionization energy of titanium (c) The electron affinity of \(\mathrm{Mg}^{2+}\) (d) The ionization energy of \(\mathrm{O}^{2-}\)

Short Answer

Expert verified
The equations representing the processes are: (a) \(\mathrm{S}^{-}(g) + e^{-} \rightarrow \mathrm{S}^{2-}(g)\) (b) \(\mathrm{Ti}^{2+}(g) \rightarrow \mathrm{Ti}^{3+}(g) + e^{-}\) (c) \(\mathrm{Mg}^{2+}(g) + e^{-} \rightarrow \mathrm{Mg}^{+}(g)\) (d) \(\mathrm{O}^{2-}(g) \rightarrow \mathrm{O}^{-}(g) + e^{-}\)

Step by step solution

01

Write equation for the electron affinity of \(\mathrm{S}^{-}\)

Electron Affinity of \(\mathrm{S}^{-}\) means that an electron is added to a \(\mathrm{S}^{-}\) ion. Thus, the equation would be \(\mathrm{S}^{-}(g) + e^{-} \rightarrow \mathrm{S}^{2-}(g)\)
02

Write equation for the third ionization energy of titanium

The third ionization energy of titanium means removing a third electron from a titanium ion that has already lost two electrons. Therefore, the equation would be \(\mathrm{Ti}^{2+}(g) \rightarrow \mathrm{Ti}^{3+}(g) + e^{-}\)
03

Write equation for the electron affinity of \(\mathrm{Mg}^{2+}\)

The electron affinity of \(\mathrm{Mg}^{2+}\) implies an electron is added to a \(\mathrm{Mg}^{2+}\) ion. So, the equation would be \(\mathrm{Mg}^{2+}(g) + e^{-} \rightarrow \mathrm{Mg}^{+}(g)\)
04

Write equation for the ionization energy of \(\mathrm{O}^{2-}\)

This refers to the energy required to remove an electron from an \(\mathrm{O}^{2-}\) ion. Hence, the equation will look like \(\mathrm{O}^{2-}(g) \rightarrow \mathrm{O}^{-}(g) + e^{-}\)

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