Chapter 9: Problem 89
Draw reasonable resonance structures for the following ions: (a) \(\mathrm{HSO}_{4}^{-},\) (b) \(\mathrm{PO}_{4}^{3-},\) (c) \(\mathrm{HSO}_{3}^{-}\) (d) \(\mathrm{SO}_{3}^{2-}\). (Hint: See comment on Example \(\left.9.11 .\right)\)
Short Answer
Expert verified
The resonance structures of the ions are obtained by drawing multiple Lewis structures, where the position of pi electrons varies among different configurations.
Step by step solution
01
Drawing the Basic Lewis Structure of the Given Ions
First, draw the basic Lewis structures for all four given ions. The ion \(\mathrm{HSO}_{4}^{-}\) is drawn by placing the Sulfur atom in the center, surrounded by 4 Oxygen atoms, with one of the oxygens also bonded to the Hydrogen atom. The ion \(\mathrm{PO}_{4}^{3-}\) is drawn by placing the Phosphorus atom at the center, surrounded by 4 Oxygen atoms. The ion \(\mathrm{HSO}_{3}^{-}\) is drawn by putting the Sulfur atom in the center, surrounded by 3 Oxygen atoms, with one of the oxygens also bonded to the Hydrogen atom. The ion \(\mathrm{SO}_{3}^{2-}\) is drawn by putting the Sulfur atom in the middle, surrounded by 3 Oxygen atoms.
02
Identifying the Pi Electrons for Resonance
Once the basic Lewis structures have been drawn for the ions, identify the pi electrons that can delocalize across the atoms of these ions. The locations of these electrons can then be alternated to create various resonance structures.
03
Drawing the Resonance Structures
Draw the resonance structures by shifting the pi electrons among the identified locations on each ion. For each ion, there will be multiple resonance structures. For instance, with \(\mathrm{HSO}_{4}^{-}\), the double bond between the sulfur and one of the oxygen atoms can shift to any one of the other three oxygens. The double bonds in the other ions can similarly shift between the central atom and the surrounding atoms.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Lewis Structures
Lewis structures are diagrams that show the distribution of valence electrons around atoms within a molecule. They serve as a visual representation of the molecular structure that helps in predicting the shape, reactivity, and properties of the molecule. A correct Lewis structure is crucial for understanding the molecule's bonding and its potential resonance structures. When drawing Lewis structures, one must account for electrons pairs surrounding the atoms, which can be in the form of bonding pairs (shared by two atoms) or lone pairs (belong to a single atom). Importantly, Lewis structures should adhere to the octet rule, meaning that most atoms strive to have eight electrons in their valence shell.
In the exercise for ions such as \(\mathrm{HSO}_4^-\), \(\mathrm{PO}_4^{3-}\), and \(\mathrm{HSO}_3^-\), we first sketch the Lewis structure considering these principles. This step sets a foundation for exploring possible resonance structures by showing us where the valence electrons are situated and how they are shared among the atoms.
In the exercise for ions such as \(\mathrm{HSO}_4^-\), \(\mathrm{PO}_4^{3-}\), and \(\mathrm{HSO}_3^-\), we first sketch the Lewis structure considering these principles. This step sets a foundation for exploring possible resonance structures by showing us where the valence electrons are situated and how they are shared among the atoms.
Pi Electrons
Pi (π) electrons are located in pi bonds, which are formed by the sideways overlap of p orbitals on adjacent atoms. These electrons are often found in double and triple bonds and are highly mobile compared to electrons in single (sigma) bonds. Pi electrons can be delocalized across a molecule when there are resonance structures, making these molecules more stable due to the distribution of electron density.
In our exercise for polyatomic ions like \(\mathrm{HSO}_4^-\) and \(\mathrm{SO}_3^{2-}\), pi electrons are central to understanding their resonance structures. During resonance, pi electrons are not locked into one position but can be shuffled between different atoms, giving rise to equivalent structures that contribute to the overall description of the molecule.
In our exercise for polyatomic ions like \(\mathrm{HSO}_4^-\) and \(\mathrm{SO}_3^{2-}\), pi electrons are central to understanding their resonance structures. During resonance, pi electrons are not locked into one position but can be shuffled between different atoms, giving rise to equivalent structures that contribute to the overall description of the molecule.
Electron Delocalization
Electron delocalization is a phenomenon where electrons, particularly pi electrons, are shared among multiple atoms in a molecule rather than being localized between a single pair of atoms. This delocalization occurs within a conjugated system or within ions where several resonance structures can be drawn.
Delocalization is significant because it increases the stabilization of the molecule or ion, lowering its potential energy. The classic example is benzene, where the pi electrons are not confined to a particular carbon-carbon bond but are spread evenly across the ring structure. In the context of the ions from the exercise—like the sulfate or sulfite ions—the possibility to draw multiple resonance structures illustrates this electron delocalization over the sulfur and oxygen atoms.
Delocalization is significant because it increases the stabilization of the molecule or ion, lowering its potential energy. The classic example is benzene, where the pi electrons are not confined to a particular carbon-carbon bond but are spread evenly across the ring structure. In the context of the ions from the exercise—like the sulfate or sulfite ions—the possibility to draw multiple resonance structures illustrates this electron delocalization over the sulfur and oxygen atoms.