Chapter 2: Problem 18

The value of equilibrium constant for a reversible reaction is \(3 \times 10^{-2}\). If the reaction quotient for the same reaction is \(5 \times 10^{-3}\), predict the direction of equilibrium reaction.

Short Answer

Expert verified

Answer: The equilibrium reaction proceeds in the forward direction.

Step by step solution

1. Determine the given values of the equilibrium constant and reaction quotient

We are given that the equilibrium constant (K) is \(3 \times 10^{-2}\) and the reaction quotient (Q) is \(5 \times 10^{-3}\).

2. Compare the reaction quotient (Q) with the equilibrium constant (K)

We need to determine if Q is less than (Q < K), greater than (Q > K), or equal to (Q = K) the equilibrium constant K. \(5 \times 10^{-3} < 3 \times 10^{-2}\)

3. Predict the direction of the equilibrium reaction

Since our comparison shows Q < K, the reaction proceeds in the forward direction.

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The value of equilibrium constant for a reversible reaction is \(3 \times 10^{-2}\). If the reaction quotient for the same reaction is \(5 \times 10^{-3}\), predict the direction of equilibrium reaction.

Short Answer

Step by step solution

1. Determine the given values of the equilibrium constant and reaction quotient

2. Compare the reaction quotient (Q) with the equilibrium constant (K)

3. Predict the direction of the equilibrium reaction

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