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Chapter 6: Problem 26

Write the equation for the action of a dilute acid on a metal oxide.

Short Answer

Expert verified
Answer: The balanced equation for the reaction between sulfuric acid and copper(II) oxide is H₂SO₄ (aq) + CuO (s) -> CuSO₄ (aq) + H₂O (l).

Step by step solution

01

Write down the general equation for the reaction of an acid with a metal oxide

Recall that the general reaction for the reaction of an acid with a metal oxide can be written as: Acid + Metal Oxide -> Salt + Water
02

Choose an example

We will choose a specific acid and metal oxide to write a balanced equation. Let's use sulfuric acid (H₂SO₄) and copper(II) oxide (CuO) as the reactants.
03

Write the equation in terms of the chosen reactants

Using the chosen reactants, write down the equation for the reaction between sulfuric acid and copper(II) oxide: H₂SO₄ (aq) + CuO (s) -> CuSO₄ (aq) + H₂O (l)
04

Balance the equation

Check that the equation is balanced in terms of atoms on both sides. In this case, it is already balanced: H₂SO₄ (aq) + CuO (s) -> CuSO₄ (aq) + H₂O (l) So, this balanced equation represents the reaction between a dilute acid (sulfuric acid) and a metal oxide (copper(II) oxide) to produce a salt (copper(II) sulfate) and water.

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