Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 1: Problem 16

You are driving \(65 \mathrm{mi} / \mathrm{h}\) and take your eyes off the road for "just a second." What distance (in feet) do you travel in this time?

Short Answer

Expert verified
The vehicle travels approximately 95.333 feet when the driver takes his/her eyes off the road for a second.

Step by step solution

01

Convert speed from mi/h to ft/s

To convert the speed from miles per hour (mi/h) to feet per second (ft/s), we need to multiply it by a conversion factor. We know that 1 mile = 5280 feet and 1 hour = 3600 seconds. Therefore, our conversion factor is \(\frac{5280 \mathrm{ft}}{1 \mathrm{mi}} × \frac{1 \mathrm{hr}}{3600 \mathrm{s}}\). Now, we'll multiply the given speed (65 mi/h) by this conversion factor: \(65 \frac{\mathrm{mi}}{\mathrm{h}} × \frac{5280 \mathrm{ft}}{1 \mathrm{mi}} × \frac{1 \mathrm{hr}}{3600 \mathrm{s}}\).
02

Simplify the expression

After multiplying, we need to simplify the expression: \(65 \frac{\cancel{\mathrm{mi}}}{\cancel{\mathrm{h}}} × \frac{5280 \mathrm{ft}}{\cancel{1 \mathrm{mi}}} × \frac{\cancel{1 \mathrm{hr}}}{3600 \mathrm{s}}\). Now the units are canceled out, and we have: \(65 × \frac{5280}{3600} \frac{\mathrm{ft}}{\mathrm{s}}\).
03

Calculate the speed in ft/s

Now we can perform the multiplication to find the speed in feet per second: \(65 × \frac{5280}{3600} ≈ 95.333 \frac{\mathrm{ft}}{\mathrm{s}}\). So, the speed of the vehicle in feet per second is approximately 95.333 ft/s.
04

Calculate the distance traveled in 1 second

Since we have the speed in ft/s and the time (1 second), we can now calculate the distance traveled by multiplying speed by time: Distance = Speed × Time Distance ≈ 95.333 ft/s × 1 s Distance ≈ 95.333 ft
05

Final answer

The vehicle travels approximately 95.333 feet when the driver takes his/her eyes off the road for a second.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Precious metals and gems are measured in troy weights in the English system: \(\begin{aligned} 24 \text { grains } &=1 \text { pennyweight (exact) } \\ 20 \text { pennyweight } &=1 \text { troy ounce (exact) } \\ 12 \text { troy ounces } &=1 \text { troy pound (exact) } \\ 1 \text { grain } &=0.0648 \text { gram } \\ 1 \text { carat } &=0.200 \mathrm{gram} \end{aligned}\) a. The most common English unit of mass is the pound avoirdupois. What is one troy pound in kilograms and in pounds? b. What is the mass of a troy ounce of gold in grams and in carats? c. The density of gold is \(19.3 \mathrm{~g} / \mathrm{cm}^{3} .\) What is the volume of a troy pound of gold?

The density of osmium (the densest metal) is \(22.57 \mathrm{~g} / \mathrm{cm}^{3} .\) If a \(1.00-\mathrm{kg}\) rectangular block of osmium has two dimensions of \(4.00 \mathrm{~cm} \times 4.00 \mathrm{~cm}\), calculate the third dimension of the block.

You have a \(1.0-\mathrm{cm}^{3}\) sample of lead and a \(1.0-\mathrm{cm}^{3}\) sample of glass. You drop each in separate beakers of water. How do the volumes of water displaced by each sample compare? Explain.

How many significant figures are in each of the following? a. 100 e. \(0.0048\) b. \(1.0 \times 10^{2}\) f. \(0.00480\) c. \(1.00 \times 10^{3}\) g. \(4.80 \times 10^{-3}\) d. 100 . h. \(4.800 \times 10^{-3}\)

The density of osmium is reported by one source to be \(22610 \mathrm{~kg} /\) \(\mathrm{m}^{3}\). What is this density in \(\mathrm{g} / \mathrm{cm}^{3}\) ? What is the mass of a block of osmium measuring \(10.0 \mathrm{~cm} \times 8.0 \mathrm{~cm} \times 9.0 \mathrm{~cm} ?\)
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Chemistry Branches

Read Explanation

The Earths Atmosphere

Read Explanation

Chemical Analysis

Read Explanation

Chemical Reactions

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free