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Chapter 1: Problem 55

Convert the following Celsius temperatures to Kelvin and to Fahrenheit degrees. a. the temperature of someone with a fever, \(39.2^{\circ} \mathrm{C}\) b. a cold wintery day, \(-25^{\circ} \mathrm{C}\) c. the lowest possible temperature, \(-273^{\circ} \mathrm{C}\) d. the melting-point temperature of sodium chloride, \(801^{\circ} \mathrm{C}\)

Short Answer

Expert verified
a. Fever Temperature: 312.35 K and 102.56 °F b. Cold Wintery Day Temperature: 248.15 K and -13 °F c. Lowest Possible Temperature: 0.15 K and -459.4 °F d. Melting-point Temperature of Sodium Chloride: 1074.15 K and 1473.8 °F

Step by step solution

01

a. Fever Temperature

Given Celsius temperature: \(39.2^{\circ} \mathrm{C}\) Celsius to Kelvin: K = C + 273.15 K = 39.2 + 273.15 K = 312.35 K Celsius to Fahrenheit: F = (9/5 * C) + 32 F = (9/5 * 39.2) + 32 F = 102.56 °F Therefore, the fever temperature is 312.35 K and 102.56 °F.
02

b. Cold Wintery Day Temperature

Given Celsius temperature: \(-25^{\circ} \mathrm{C}\) Celsius to Kelvin: K = C + 273.15 K = -25 + 273.15 K = 248.15 K Celsius to Fahrenheit: F = (9/5 * C) + 32 F = (9/5 * -25) + 32 F = -13 °F Therefore, the cold wintery day temperature is 248.15 K and -13 °F.
03

c. Lowest Possible Temperature

Given Celsius temperature: \(-273^{\circ} \mathrm{C}\) Celsius to Kelvin: K = C + 273.15 K = -273 + 273.15 K = 0.15 K Celsius to Fahrenheit: F = (9/5 * C) + 32 F = (9/5 * -273) + 32 F = -459.4 °F Therefore, the lowest possible temperature is 0.15 K and -459.4 °F.
04

d. Melting-point Temperature of Sodium Chloride

Given Celsius temperature: \(801^{\circ} \mathrm{C}\) Celsius to Kelvin: K = C + 273.15 K = 801 + 273.15 K = 1074.15 K Celsius to Fahrenheit: F = (9/5 * C) + 32 F = (9/5 * 801) + 32 F = 1473.8 °F Therefore, the melting-point temperature of sodium chloride is 1074.15 K and 1473.8 °F.

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