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Chapter 10: Problem 66

An aluminum antimonide solid-state laser emits light with a wavelength of \(730 . \mathrm{nm}\). Calculate the band gap in joules.

Short Answer

Expert verified
The band gap energy of the aluminum antimonide solid-state laser that emits light at 730 nm wavelength is approximately \(2.72 \times 10^{-19}\) joules.

Step by step solution

01

Write down the given information and necessary constants

Wavelength of the emitted light, λ = 730 nm = \(7.3 \times 10^{-7}\) m (convert nm to m) Planck's constant, h = \(6.626 \times 10^{-34}\) Js Speed of light in vacuum, c = \(3 \times 10^8\) m/s Our goal is to calculate the bandgap in joules.
02

Calculate the energy of a photon (E)

We will first find the energy of a photon (E) using the formula: \(E = \dfrac{hc}{\lambda}\) Where E is the energy of the photon, h is the Planck's constant, c is the speed of light in vacuum, and λ is the wavelength of the emitted light.
03

Plug in the values and calculate the energy

Now we can plug in the values we have to find the energy: \(E = \dfrac{(6.626 \times 10^{-34} \text{ Js}) \times (3 \times 10^8 \text{ m/s})}{(7.3 \times 10^{-7} \text{ m})}\) Upon calculation, we get: \(E = 2.72 \times 10^{-19}\) J
04

Conclusion

The band gap energy of the aluminum antimonide solid-state laser that emits light at 730 nm wavelength is approximately \(2.72 \times 10^{-19}\) joules.

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Most popular questions from this chapter

MnO has either the \(\mathrm{NaCl}\) type structure or the \(\mathrm{CsCl}\) type structure (see Exercise 67). The edge length of the \(\mathrm{MnO}\) unit cell is \(4.47 \times 10^{-8} \mathrm{~cm}\) and the density of \(\mathrm{MnO}\) is \(5.28 \mathrm{~g} / \mathrm{cm}^{3}\) a. Does \(\mathrm{Mn} \mathrm{O}\) crystallize in the \(\mathrm{NaCl}\) or the \(\mathrm{CsCl}\) type structure? b. Assuming that the ionic radius of oxygen is \(140 . \mathrm{pm}\), estimate the ionic radius of manganese.

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