Define stability from both a kinetic and thermodynamic perspective. Give examples to show the differences in these concepts.

Short Answer

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Kinetic stability refers to the rate at which a substance reacts or transforms, influenced by the activation energy. For example, diamond is kinetically more stable than graphite due to the high activation energy required for its transformation. Thermodynamic stability relates to a substance's overall energy state and favorability, such as in the exothermic reaction forming water from hydrogen and oxygen gases. While kinetic stability focuses on reaction rates and activation energy, thermodynamic stability is concerned with the overall potential energy and preferred state under specific conditions.

Step by step solution

01

Define Kinetic Stability

Kinetic stability refers to the rate at which a substance undergoes a chemical reaction or transformation. A compound with high kinetic stability is relatively unreactive and takes a longer time to transform or react under a certain set of conditions compared to a less kinetically stable compound. Kinetic stability is strongly influenced by the activation energy (Ea) required for a reaction to occur; a higher activation energy results in slower reaction rates and higher kinetic stability.
02

Example of Kinetic Stability

An example of kinetic stability is the difference between diamond and graphite. Both diamond and graphite are allotropes of carbon, but diamond is kinetically more stable than graphite at room temperature and pressure. This is because the transformation of diamond to graphite requires a high activation energy, which is not readily available at these conditions. Therefore, diamond remains relatively unreactive and stable, despite being thermodynamically less stable than graphite.
03

Define Thermodynamic Stability

Thermodynamic stability refers to the overall position of a substance in its energy landscape, in terms of its potential energy, enthalpy, or Gibbs free energy. A thermodynamically stable substance is one that has reached its lowest potential energy state (most favorable) under a given set of conditions, such as temperature and pressure. This state corresponds to the minimum of the substance's energy landscape, which represents the point where the substance is most stable and its properties are less likely to change.
04

Example of Thermodynamic Stability

A classic example to illustrate thermodynamic stability is the reaction between hydrogen gas (H₂) and oxygen gas (O₂) to produce water (H₂O). The reaction is exothermic and releases energy, indicating that water is at a lower potential energy state compared to the reactants (hydrogen and oxygen). Since the objective of any system is to reach the lowest possible energy state, water is considered thermodynamically more stable than the mixture of hydrogen and oxygen gases.
05

Differences between Kinetic and Thermodynamic Stability

Kinetic stability focuses on the rate of a reaction and the activation energy required for the reaction to occur, while thermodynamic stability is concerned with the overall energy state and favorability of a substance. For instance, a kinetically stable substance may not necessarily be thermodynamically stable, like the diamond example. The molecule is kinetically stable due to high activation energy, but it is actually less stable than graphite from a thermodynamic perspective. In summary, kinetic stability is related to the reaction rate and the activation energy barrier, while thermodynamic stability is related to the overall potential energy of a substance and its preference to exist in a certain state under specific conditions.

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Most popular questions from this chapter

Write the rate laws for the following elementary reactions. a. \(\mathrm{CH}_{3} \mathrm{NC}(g) \rightarrow \mathrm{CH}_{3} \mathrm{CN}(g)\) b. \(\mathrm{O}_{3}(g)+\mathrm{NO}(g) \rightarrow \mathrm{O}_{2}(g)+\mathrm{NO}_{2}(g)\) c. \(\mathrm{O}_{3}(g) \rightarrow \mathrm{O}_{2}(g)+\mathrm{O}(g)\) d. \(\mathrm{O}_{3}(g)+\mathrm{O}(g) \rightarrow 2 \mathrm{O}_{2}(g)\)

The activation energy for the reaction $$ \mathrm{NO}_{2}(g)+\mathrm{CO}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{CO}_{2}(g) $$ is \(125 \mathrm{~kJ} / \mathrm{mol}\), and \(\Delta E\) for the reaction is \(-216 \mathrm{~kJ} / \mathrm{mol}\). What is the activation energy for the reverse reaction \(\left[\mathrm{NO}(g)+\mathrm{CO}_{2}(g) \longrightarrow\right.\) \(\left.\mathrm{NO}_{2}(g)+\mathrm{CO}(g)\right] ?\)

For enzyme-catalyzed reactions that follow the mechanism $$ \begin{array}{l} \mathrm{E}+\mathrm{S} \rightleftharpoons \mathrm{E} \cdot \mathrm{S} \\ \mathrm{E} \cdot \mathrm{S} \rightleftharpoons \mathrm{E}+\mathrm{P} \end{array} $$ a graph of the rate as a function of \([\mathrm{S}]\), the concentration of the substrate, has the following appearance: Note that at higher substrate concentrations the rate no longer changes with [S]. Suggest a reason for this.

One reason suggested for the instability of long chains of silicon atoms is that the decomposition involves the transition state shown below: The activation energy for such a process is \(210 \mathrm{~kJ} / \mathrm{mol}\), which is less than either the \(\mathrm{Si}-\mathrm{Si}\) or the \(\mathrm{Si}-\mathrm{H}\) bond energy. Why would a similar mechanism not be expected to play a very important role in the decomposition of long chains of carbon atoms as seen in organic compounds?

What are the units for each of the following if the concentrations are expressed in moles per liter and the time in seconds? a. rate of a chemical reaction b. rate constant for a zero-order rate law c. rate constant for a first-order rate law d. rate constant for a second-order rate law e. rate constant for a third-order rate law

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