Consider the general reaction $$ \mathrm{aA}+\mathrm{bB} \longrightarrow \mathrm{cC} $$ and the following average rate data over some time period \(\Delta t\) : $$ \begin{aligned} -\frac{\Delta \mathrm{A}}{\Delta t} &=0.0080 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \\ -\frac{\Delta \mathrm{B}}{\Delta t} &=0.0120 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \\ \frac{\Delta \mathrm{C}}{\Delta t} &=0.0160 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \end{aligned} $$ Determine a set of possible coefficients to balance this general reaction.

Short Answer

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The given average rate data for changes in concentration of reactants A, B, and product C can be used to find the relationships between the coefficients a, b, and c in the general reaction \(\mathrm{aA}+\mathrm{bB}\longrightarrow \mathrm{cC}\). Based on the rate data, we find that B is changing 1.5 times as fast as A and C is changing 2 times as fast as A. One set of possible coefficients is a = 2, b = 3, and c = 4, resulting in the balanced reaction \(2\mathrm{A} + 3\mathrm{B} \longrightarrow 4\mathrm{C}\). However, there might be other possible combinations fitting the rate data as long as the ratios between a, b, and c are maintained.

Step by step solution

01

Write down the given rate data

We are given the average rate data for changes in concentration of reactants A, B, and product C over a certain time period: \[ \begin{aligned} -\frac{\Delta \mathrm{A}}{\Delta t} &=0.0080 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \\ -\frac{\Delta \mathrm{B}}{\Delta t} &=0.0120 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \\ \frac{\Delta \mathrm{C}}{\Delta t} &=0.0160 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s} \end{aligned} \]
02

Find the relationship between the rates

To find the relationship between the change in concentrations of A, B, and C, we can first divide the rate of change of B by the rate of change of A and then the rate of change of C by the rate of change of A: \[ \frac{-\frac{\Delta \mathrm{B}}{\Delta t}}{-\frac{\Delta \mathrm{A}}{\Delta t}} =\frac{0.0120}{0.0080} = 1.5 \] \[ \frac{\frac{\Delta \mathrm{C}}{\Delta t}}{-\frac{\Delta \mathrm{A}}{\Delta t}} =\frac{0.0160}{0.0080} = 2 \] This tells us that B is changing 1.5 times as fast as A, while C is changing 2 times as fast as A.
03

Determine a set of possible coefficients

Now, we use the relationships we found in Step 2 to balance the reaction: \[ \mathrm{aA} + \mathrm{bB} \longrightarrow \mathrm{cC} \] Since B is changing 1.5 times as fast as A, the coefficient b can be expressed as 1.5a. Similarly, since C is changing 2 times as fast as A, the coefficient c can be expressed as 2a. To find a set of possible coefficients, we can use multiples of these ratios. For example, we can set a = 2, which results in: \[ \mathrm{aA} = 2\mathrm{A} \] \[ \mathrm{bB} = 1.5(2) = 3\mathrm{B} \] \[ \mathrm{cC} = 2(2) = 4\mathrm{C} \] So one set of possible coefficients is a = 2, b = 3, and c = 4. And the balanced reaction would be: \[ 2\mathrm{A} + 3\mathrm{B} \longrightarrow 4\mathrm{C} \] However, there might be other possible combinations fitting the rate data. The most important part is to maintain the ratios between a, b, and c.

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Most popular questions from this chapter

A first-order reaction has rate constants of \(4.6 \times 10^{-2} \mathrm{~s}^{-1}\) and \(8.1 \times 10^{-2} \mathrm{~s}^{-1}\) at \(0^{\circ} \mathrm{C}\) and \(20 .{ }^{\circ} \mathrm{C}\), respectively. What is the value of the activation energy?

Each of the statements given below is false. Explain why. a. The activation energy of a reaction depends on the overall energy change \((\Delta E)\) for the reaction. b. The rate law for a reaction can be deduced from examination of the overall balanced equation for the reaction. c. Most reactions occur by one-step mechanisms.

Consider the hypothetical reaction $$ \mathrm{A}+\mathrm{B}+2 \mathrm{C} \longrightarrow 2 \mathrm{D}+3 \mathrm{E} $$ where the rate law is $$ \text { Rate }=-\frac{\Delta[\mathrm{A}]}{\Delta t}=k[\mathrm{~A}][\mathrm{B}]^{2} $$ An experiment is carried out where \([\mathrm{A}]_{0}=1.0 \times 10^{-2} M\), \([\mathrm{B}]_{0}=3.0 \mathrm{M}\), and \([\mathrm{C}]_{0}=2.0 \mathrm{M} .\) The reaction is started, and after \(8.0\) seconds, the concentration of \(\mathrm{A}\) is \(3.8 \times 10^{-3} \mathrm{M}\). a. Calculate the value of \(k\) for this reaction. b. Calculate the half-life for this experiment. c. Calculate the concentration of A after \(13.0\) seconds. d. Calculate the concentration of \(\mathrm{C}\) after \(13.0\) seconds.

Chemists commonly use a rule of thumb that an increase of \(10 \mathrm{~K}\) in temperature doubles the rate of a reaction. What must the activation energy be for this statement to be true for a temperature increase from 25 to \(35^{\circ} \mathrm{C}\) ?

Would the slope of a \(\ln (k)\) versus \(1 / T(\mathrm{~K})\) plot for a catalyzed reaction be more or less negative than the slope of the \(\ln (k)\) versus \(1 / T(\mathrm{~K})\) plot for the uncatalyzed reaction? Explain. Assume both rate laws are first-order overall.

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