Arrange the following \(0.10 M\) solutions in order from most acidic to most basic. See Appendix 5 for \(K_{\mathrm{a}}\) and \(K_{\mathrm{b}}\) values. \(\mathrm{CaBr}_{2}, \quad \mathrm{KNO}_{2}, \quad \mathrm{HClO}_{4}, \quad \mathrm{HNO}_{2}, \quad \mathrm{HONH}_{3} \mathrm{ClO}_{4}\).

Short Answer

Expert verified
The order of the given solutions from most acidic to most basic is: \(\mathrm{HClO}_4\), \(\mathrm{HNO}_2\), \(\mathrm{HONH}_3 \mathrm{ClO}_4\), \(\mathrm{CaBr}_2\), \(\mathrm{KNO}_2\).

Step by step solution

01

Identify acidic and basic compounds

We have to identify the acidic and basic nature of each compound: 1. CaBr2: Neutral 2. KNO2: Basic 3. HClO4: Acidic (strong acid) 4. HNO2: Acidic (weak acid) 5. HONH3ClO4: Acidic (weak base + strong acid)
02

Comparing acidic strengths

We need to compare the acidic strengths of HClO4, HNO2, and HONH3ClO4. We know that HClO4 is a strong acid, so it will have the lowest pH compared to the weak acidic solutions. Comparison of weak acids HNO2 and HONH3ClO4 can be done based on the Ka values: - HNO2: Ka = \(5.1 \times 10^{-4}\) - HONH3ClO4: Ka (NH4+) = \(5.6 \times 10^{-10}\) HNO2 has a higher Ka value (larger acidic dissociation constant); thus, it is more acidic than HONH3ClO4.
03

Comparing basic strengths

Now, we will compare the basic strengths of KNO2 and CaBr2. Since CaBr2 is neutral and KNO2 is a basic solution, KNO2 will be more basic.
04

Arrange solutions

Arrange the solutions from most acidic to most basic based on the comparisons of their acidic and basic strengths: 1. HClO4 (strong acid) 2. HNO2 (weak acid with higher Ka) 3. HONH3ClO4 (weak acid with lower Ka) 4. CaBr2 (neutral) 5. KNO2 (basic) Therefore, the order from most acidic to most basic is: \(\mathrm{HClO}_4\), \(\mathrm{HNO}_2\), \(\mathrm{HONH}_3 \mathrm{ClO}_4\), \(\mathrm{CaBr}_2\), \(\mathrm{KNO}_2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Identify the Lewis acid and the Lewis base in each of the following reactions. a. \(\mathrm{Fe}^{3+}(a q)+6 \mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}(a q)\) b. \(\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{CN}^{-}(a q) \rightleftharpoons \mathrm{HCN}(a q)+\mathrm{OH}^{-}(a q)\) c. \(\mathrm{HgI}_{2}(s)+2 \mathrm{I}^{-}(a q) \rightleftharpoons \mathrm{HgI}_{4}{ }^{2-}(a q)\)

A typical vitamin C tablet (containing pure ascorbic acid, \(\mathrm{H}_{2} \mathrm{C}_{6} \mathrm{H}_{6} \mathrm{O}_{6}\) ) weighs 500 . mg. One vitamin C tablet is dissolved in enough water to make \(200.0 \mathrm{~mL}\) of solution. Calculate the \(\mathrm{pH}\) of this solution. Ascorbic acid is a diprotic acid.

Calculate the concentration of all species present and the \(\mathrm{pH}\) of a \(0.020 M \mathrm{HF}\) solution.

Quinine \(\left(\mathrm{C}_{20} \mathrm{H}_{24} \mathrm{~N}_{2} \mathrm{O}_{2}\right)\) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine, \(\mathrm{p} K_{\mathrm{b}_{1}}=5.1\) and \(\mathrm{p} K_{\mathrm{b}_{2}}=9.7\left(\mathrm{p} K_{\mathrm{b}}=-\log K_{\mathrm{b}}\right) .\) Only \(1 \mathrm{~g}\) quinine will dissolve in \(1900.0 \mathrm{~mL}\) of solution. Calculate the \(\mathrm{pH}\) of a saturated aqueous solution of quinine. Consider only the reaction \(\mathrm{Q}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{QH}^{+}+\mathrm{OH}^{-}\) described by \(\mathrm{p} K_{\mathrm{b}_{1}}\), where \(\mathrm{Q}=\) quinine.

Identify the Lewis acid and the Lewis base in each of the following reactions. a. \(\mathrm{B}(\mathrm{OH})_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{B}(\mathrm{OH})_{4}^{-}(a q)+\mathrm{H}^{+}(a q)\) b. \(\mathrm{Ag}^{+}(a q)+2 \mathrm{NH}_{3}(a q) \rightleftharpoons \mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}^{+}(a q)\) c. \(\mathrm{BF}_{3}(g)+\mathrm{F}^{-}(a q) \rightleftharpoons \mathrm{BF}_{4}^{-}(a q)\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free