Will \(0.10 M\) solutions of the following salts be acidic, basic, or neutral? See Appendix 5 for \(K_{\mathrm{a}}\) values. a. ammonium bicarbonate b. sodium dihydrogen phosphate c. sodium hydrogen phosphate d. ammonium dihydrogen phosphate e. ammonium formate

Short Answer

Expert verified
a. Ammonium bicarbonate: slightly basic, since NH4+ and HCO3- both can act as weak acids, but HCO3- can also act as a weak base with a larger \(K_{\mathrm{b}}\) value. b. Sodium dihydrogen phosphate: acidic, as H2PO4- is a weak acid and Na+ does not affect acidity/basicity. c. Sodium hydrogen phosphate: slightly basic, since HPO4^2- is the conjugate base of a weak acid and Na+ does not affect acidity/basicity. d. Ammonium dihydrogen phosphate: acidic, because both NH4+ and H2PO4- are weak acids with similar \(K_{\mathrm{a}}\) values. e. Ammonium formate: basic, since NH4+ is a weak acid and HCOO- is the conjugate base of a weak acid, having a larger \(K_{\mathrm{a}}\) value than NH4+.

Step by step solution

01

Identifying the Anions and Cations

In this step, we will identify the anions and cations for each salt and look up the \(K_{\mathrm{a}}\) values in Appendix 5. a. ammonium bicarbonate: NH4+ (cation) and HCO3- (anion) b. sodium dihydrogen phosphate: Na+ (cation) and H2PO4- (anion) c. sodium hydrogen phosphate: Na+ (cation) and HPO4^2- (anion) d. ammonium dihydrogen phosphate: NH4+ (cation) and H2PO4- (anion) e. ammonium formate: NH4+ (cation) and HCOO- (anion)
02

Determining the Acid/Base Character of Each Ion

In this step, we will decide the acid/base character of each ion, using their \(K_{\mathrm{a}}\) or \(K_{\mathrm{b}}\) values as appropriate. Recall that \(K_{\mathrm{a}}\) and \(K_{\mathrm{b}}\) are related by \(K_{\mathrm{a}}\times K_{\mathrm{b}}=K_{\mathrm{w}}=10^{-14}\). (a) NH4+ is a weak acid with \(K_{\mathrm{a}}\approx5.6\times10^{-10}\). HCO3- is an amphoteric ion (it can act as an acid or a base); it has the acidic dissociation constant \(K_{\mathrm{a1}}\approx4.8\times10^{-11}\) and its conjugate base, CO3^2-, has \(K_{\mathrm{b}}\approx 2.1\times10^{-4}\). (b) Na+ is a neutral ion and does not affect acidity and basicity directly. H2PO4- is a weak acid with \(K_{\mathrm{a}}\approx6.2\times10^{-8}\). (c) Na+ is a neutral ion. HPO4^2- is the conjugate base of a weak acid (H2PO4-) with \(K_{\mathrm{b}}\approx 2.4\times10^{-13}\). (d) NH4+ is a weak acid with \(K_{\mathrm{a}}\approx5.6\times10^{-10}\). H2PO4- is a weak acid with \(K_{\mathrm{a}}\approx6.2\times10^{-8}\). (e) NH4+ is a weak acid with \(K_{\mathrm{a}}\approx5.6\times10^{-10}\). HCOO- is the conjugate base of a weak acid, formic acid, and has \(K_{\mathrm{a}}\approx1.77\times10^{-4}\).
03

Comparing the Acid/Base Characters of the Salts

In this step, we will compare the acidity and basicity of the anions and cations, and classify the resulting salt solutions as acidic, basic, or neutral. a. NH4+ and HCO3- both can act as weak acids, but HCO3- can also act as a weak base. Given that the \(K_{\mathrm{a}}\) value of NH4+ is larger than the \(K_{\mathrm{a1}}\) value of HCO3- and the \(K_{\mathrm{b}}\) value of HCO3- is much larger than the \(K_{\mathrm{a}}\) value of NH4+, the overall solution may be slightly basic. b. Na+ does not affect acidity/basicity. H2PO4- is a weak acid and will contribute protons to the solution, making it acidic. c. Na+ does not affect acidity/basicity. HPO4^2- is the conjugate base of a weak acid and will create an equilibrium for accepting protons, making the overall solution slightly basic. d. Both NH4+ and H2PO4- are weak acids with \(K_{\mathrm{a}}\) values close to each other, so their acidic characters will add up, making the overall solution acidic. e. NH4+ is a weak acid and HCOO- is the conjugate base of a weak acid, having a \(K_{\mathrm{a}}\) much larger than that of NH4+. Therefore, the basic character of HCOO- will dominate, and the overall solution will be basic. So, the final answer is: a. basic b. acidic c. basic d. acidic e. basic

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Most popular questions from this chapter

Calculate the \(\mathrm{pH}\) of an aqueous solution containing \(1.0 \times 10^{-2} M\) \(\mathrm{HCl}, 1.0 \times 10^{-2} \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\), and \(1.0 \times 10^{-2} \mathrm{M} \mathrm{HCN}\).

Arrange the following \(0.10 M\) solutions in order of most acidic to most basic. \(\mathrm{KOH}, \quad \mathrm{KNO}_{3}, \quad \mathrm{KCN}, \quad \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{HCl}\).

A sample containing \(0.0500 \mathrm{~mol} \mathrm{Fe}_{2}\left(\mathrm{SO}_{4}\right)_{3}\) is dissolved in enough water to make \(1.00 \mathrm{~L}\) of solution. This solution contains hydrated \(\mathrm{SO}_{4}{ }^{2-}\) and \(\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}{ }^{3+}\) ions. The latter behaves as an acid: $$\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}(a q) \rightleftharpoons \mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{OH}^{2+}(a q)+\mathrm{H}^{+}(a q)$$ a. Calculate the expected osmotic pressure of this solution at \(25^{\circ} \mathrm{C}\) if the above dissociation is negligible. b. The actual osmotic pressure of the solution is \(6.73\) atm at \(25^{\circ} \mathrm{C}\). Calculate \(K_{\mathrm{a}}\) for the dissociation reaction of \(\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}\). (To do this calculation, you must assume that none of the ions goes through the semipermeable membrane. Actually, this is not a great assumption for the tiny \(\mathrm{H}^{+}\) ion.)

An acid HX is \(25 \%\) dissociated in water. If the equilibrium concentration of \(\mathrm{HX}\) is \(0.30 \mathrm{M}\), calculate the \(K_{\mathrm{a}}\) value for \(\mathrm{HX}\).

Identify the Lewis acid and the Lewis base in each of the following reactions. a. \(\mathrm{Fe}^{3+}(a q)+6 \mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}(a q)\) b. \(\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{CN}^{-}(a q) \rightleftharpoons \mathrm{HCN}(a q)+\mathrm{OH}^{-}(a q)\) c. \(\mathrm{HgI}_{2}(s)+2 \mathrm{I}^{-}(a q) \rightleftharpoons \mathrm{HgI}_{4}{ }^{2-}(a q)\)

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