Derive an expression for the relationship between \(\mathrm{p} K_{\mathrm{a}}\) and \(\mathrm{p} K_{\mathrm{b}}\) for a conjugate acid-base pair. \((\mathrm{p} K=-\log K .)\)

Short Answer

Expert verified
The relationship between the acidity constant \(pK_a\) and the basicity constant \(pK_b\) for a conjugate acid-base pair is: \(pK_a + pK_b = pK_w\).

Step by step solution

01

Write expression for \(K_a\) and \(K_b\)

For the acid dissociation reaction: \[HA + H_2O \rightleftharpoons H_3O^+ + A^-\] The acidity constant, \(K_a\), is defined as: \[K_a = \frac{[H_3O^+][A^-]}{[HA]}\] Similarly, for the base dissociation reaction: \[A^- + H_2O \rightleftharpoons HA + OH^-\] The basicity constant, \(K_b\), is defined as: \[K_b = \frac{[HA][OH^-]}{[A^-]}\] Step 2: Write the expression for \(pK_a\) and \(pK_b\)
02

Write expression for \(pK_a\) and \(pK_b\)

The \(pK_a\) and \(pK_b\) are the negative logarithm of \(K_a\) and \(K_b\) respectively. We have: \[pK_a = -\log{K_a}\] \[pK_b = -\log{K_b}\] Step 3: Use the relationship between \(K_a\), \(K_b\), and \(K_w\)
03

Use the relationship between \(K_a\), \(K_b\), and \(K_w\)

The relationship between \(K_a\), \(K_b\), and the auto-ionization constant of water (\(K_w = [H_3O^+][OH^-]\)) is given by: \[K_a \cdot K_b = K_w\] Step 4: Write the relationship between \(pK_a\) and \(pK_b\)
04

Write the relationship between \(pK_a\) and \(pK_b\)

Taking the logarithm of the relation \(K_a \cdot K_b = K_w\), we get: \[\log{K_a} + \log{K_b} = \log{K_w}\] Now, multiply the whole equation by -1: \[-\log{K_a} - \log{K_b} = -\log{K_w}\] Finally, substituting the expressions for \(pK_a\) and \(pK_b\): \[pK_a + pK_b = pK_w\] Therefore, the relationship between the acidity constant \(pK_a\) and the basicity constant \(pK_b\) for a conjugate acid-base pair is: \[pK_a + pK_b = pK_w\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A solution is prepared by adding \(50.0 \mathrm{~mL}\) concentrated hydrochloric acid and \(20.0 \mathrm{~mL}\) concentrated nitric acid to \(300 \mathrm{~mL}\) water. More water is added until the final volume is \(1.00 \mathrm{~L}\). Calculate \(\left[\mathrm{H}^{+}\right],\left[\mathrm{OH}^{-}\right]\), and the \(\mathrm{pH}\) for this solution. [Hint: Concentrated HCl is \(38 \%\) HCl (by mass) and has a density of \(1.19\) \(\mathrm{g} / \mathrm{mL} ;\) concentrated \(\mathrm{HNO}_{3}\) is \(70 . \% \mathrm{HNO}_{3}\) (by mass) and has a density of \(1.42 \mathrm{~g} / \mathrm{mL} .\) ]

Calculate \(\left[\mathrm{OH}^{-}\right], \mathrm{pOH}\), and \(\mathrm{pH}\) for each of the following. a. \(0.00040 \mathrm{M} \mathrm{Ca}(\mathrm{OH})_{2}\) b. a solution containing \(25 \mathrm{~g}\) KOH per liter c. a solution containing \(150.0 \mathrm{~g} \mathrm{NaOH}\) per liter

Hemoglobin (abbreviated \(\mathrm{Hb}\) ) is a protein that is responsible for the transport of oxygen in the blood of mammals. Each hemoglobin molecule contains four iron atoms that are the binding sites for \(\mathrm{O}_{2}\) molecules. The oxygen binding is pH-dependent. The relevant equilibrium reaction is $$\mathrm{HbH}_{4}^{4+}(a q)+4 \mathrm{O}_{2}(g) \rightleftharpoons \mathrm{Hb}\left(\mathrm{O}_{2}\right)_{4}(a q)+4 \mathrm{H}^{+}(a q)$$ Use Le Châtelier's principle to answer the following. a. What form of hemoglobin, \(\mathrm{HbH}_{4}{ }^{4+}\) or \(\mathrm{Hb}\left(\mathrm{O}_{2}\right)_{4}\), is favored in the lungs? What form is favored in the cells? b. When a person hyperventilates, the concentration of \(\mathrm{CO}_{2}\) in the blood is decreased. How does this affect the oxygenbinding equilibrium? How does breathing into a paper bag help to counteract this effect? (See Exercise 148.) c. When a person has suffered a cardiac arrest, injection of a sodium bicarbonate solution is given. Why is this necessary?

Papaverine hydrochloride (abbreviated papH \(^{+} \mathrm{Cl}^{-} ;\) molar mass \(=\) \(378.85 \mathrm{~g} / \mathrm{mol}\) ) is a drug that belongs to a group of medicines called vasodilators, which cause blood vessels to expand, thereby increasing blood flow. This drug is the conjugate acid of the weak base papaverine (abbreviated pap; \(K_{\mathrm{b}}=8.33 \times 10^{-9}\) at \(35.0^{\circ} \mathrm{C}\) ). Calculate the \(\mathrm{pH}\) of a \(30.0 \mathrm{mg} / \mathrm{mL}\) aqueous dose of papH \(^{+} \mathrm{Cl}^{-}\) prepared at \(35.0^{\circ} \mathrm{C} . K_{\mathrm{w}}\) at \(35.0^{\circ} \mathrm{C}\) is \(2.1 \times 10^{-14}\).

Will the following oxides give acidic, basic, or neutral solutions when dissolved in water? Write reactions to justify your answers. a. \(\mathrm{Li}_{2} \mathrm{O}\) b. \(\mathrm{CO}_{2}\) c. \(\mathrm{SrO}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free