Write the dissociation reaction and the corresponding \(K_{\mathrm{a}}\) equilibrium expression for each of the following acids in water. a. HCN b. \(\mathrm{HOC}_{6} \mathrm{H}_{5}\) c. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}\)

Short Answer

Expert verified
a. Dissociation reaction of HCN: \[ \mathrm{HCN} \rightleftharpoons \mathrm{H}^+ + \mathrm{CN}^{-} \] \(K_a\) expression for HCN: \[ K_a = \frac{[\mathrm{H}^+] [\mathrm{CN}^{-}]} {[\mathrm{HCN}]} \] b. Dissociation reaction of \(\mathrm{HOC}_{6} \mathrm{H}_{5}\): \[ \mathrm{HOC}_{6} \mathrm{H}_{5} \rightleftharpoons \mathrm{H}^+ + \mathrm{OC}_{6} \mathrm{H}_{5}^{-} \] \(K_a\) expression for \(\mathrm{HOC}_{6} \mathrm{H}_{5}\): \[ K_a = \frac{[\mathrm{H}^+] [\mathrm{OC}_{6} \mathrm{H}_{5}^{-}]} {[\mathrm{HOC}_{6} \mathrm{H}_{5}]} \] c. Dissociation reaction of \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}\): \[ \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+} \rightleftharpoons \mathrm{H}^+ + \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2} \] \(K_a\) expression for \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}\): \[ K_a = \frac{[\mathrm{H}^+] [\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}]} {[\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}]} \]

Step by step solution

01

(a) Dissociation Reaction of HCN

The dissociation of HCN in water can be written as: \[ \mathrm{HCN} \rightleftharpoons \mathrm{H}^+ + \mathrm{CN}^{-} \]
02

(a) \(K_a\) Expression for HCN

The \(K_a\) expression for the dissociation of HCN can be written as: \[ K_a = \frac{[\mathrm{H}^+] [\mathrm{CN}^{-}]} {[\mathrm{HCN}]} \]
03

(b) Dissociation Reaction of \(\mathrm{HOC}_{6} \mathrm{H}_{5}\)

The dissociation of \(\mathrm{HOC}_{6} \mathrm{H}_{5}\) in water can be written as: \[ \mathrm{HOC}_{6} \mathrm{H}_{5} \rightleftharpoons \mathrm{H}^+ + \mathrm{OC}_{6} \mathrm{H}_{5}^{-} \]
04

(b) \(K_a\) Expression for \(\mathrm{HOC}_{6} \mathrm{H}_{5}\)

The \(K_a\) expression for the dissociation of \(\mathrm{HOC}_{6} \mathrm{H}_{5}\) can be written as: \[ K_a = \frac{[\mathrm{H}^+] [\mathrm{OC}_{6} \mathrm{H}_{5}^{-}]} {[\mathrm{HOC}_{6} \mathrm{H}_{5}]} \]
05

(c) Dissociation Reaction of \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}\)

The dissociation of \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}\) in water can be written as: \[ \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+} \rightleftharpoons \mathrm{H}^+ + \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2} \]
06

(c) \(K_a\) Expression for \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}\)

The \(K_a\) expression for the dissociation of \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}\) can be written as: \[ K_a = \frac{[\mathrm{H}^+] [\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}]} {[\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}]} \]

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