Chapter 15: Problem 14
Acid-base indicators mark the end point of titrations by "magically" turning a different color. Explain the "magic" behind acid-base indicators.
Chapter 15: Problem 14
Acid-base indicators mark the end point of titrations by "magically" turning a different color. Explain the "magic" behind acid-base indicators.
All the tools & learning materials you need for study success - in one app.
Get started for freeConsider the titration of \(40.0 \mathrm{~mL}\) of \(0.200 \mathrm{M} \mathrm{HClO}_{4}\) by \(0.100\) \(M\) KOH. Calculate the \(\mathrm{pH}\) of the resulting solution after the following volumes of KOH have been added. a. \(0.0 \mathrm{~mL}\) d. \(80.0 \mathrm{~mL}\) b. \(10.0 \mathrm{~mL}\) e. \(100.0 \mathrm{~mL}\) c. \(40.0 \mathrm{~mL}\)
Which of the following mixtures would result in a buffered solution when \(1.0 \mathrm{~L}\) of each of the two solutions are mixed? a. \(0.2 \mathrm{M} \mathrm{HNO}_{\mathrm{z}}\) and \(0.4 \mathrm{M} \mathrm{NaNO}_{3}\) b. \(0.2 \mathrm{M} \mathrm{HNO}_{3}\) and \(0.4 \mathrm{M} \mathrm{HF}\) c. \(0.2 \mathrm{M} \mathrm{HNO}_{3}\) and \(0.4 \mathrm{M} \mathrm{NaF}\) d. \(0.2 \mathrm{M} \mathrm{HNO}_{3}\) and \(0.4 \mathrm{M} \mathrm{NaOH}\)
Consider a solution containing \(0.10 M\) ethylamine \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}\right.\) ), \(0.20 \mathrm{M} \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{NH}_{3}^{+}\), and \(0.20 \mathrm{M} \mathrm{Cl}^{-}\) a. Calculate the \(\mathrm{pH}\) of this solution. b. Calculate the \(\mathrm{pH}\) after \(0.050 \mathrm{~mol} \mathrm{KOH}(s)\) is added to \(1.00 \mathrm{~L}\) of this solution. (Ignore any volume changes.)
A \(225-\mathrm{mg}\) sample of a diprotic acid is dissolved in enough water to make \(250 . \mathrm{mL}\) of solution. The \(\mathrm{pH}\) of this solution is \(2.06\). A \(6.9 \times 10^{-3} M\) solution of calcium hydroxide is prepared. Enough of the calcium hydroxide solution is added to the solution of the acid to reach the second equivalence point. The \(\mathrm{pH}\) at the second equivalence point (as determined by a pH meter) is \(7.96 .\) The first dissociation constant for the acid \(\left(K_{\Delta}\right)\) is \(5.90 \times\) \(10^{-2}\). Assume that the volumes of the solutions are additive, that all solutions are at \(25^{\circ} \mathrm{C}\), and that \(K_{a_{1}}\) is at least 1000 times greater than \(K_{a_{2}}\). a. Calculate the molar mass of the acid. b. Calculate the second dissociation constant for the acid \(\left(K_{\mathrm{a}}\right)\).
Consider a buffer solution where [weak acid] \(>\) [conjugate base]. How is the \(\mathrm{pH}\) of the solution related to the \(\mathrm{p} K_{\mathrm{a}}\) value of the weak acid? If [conjugate base] > [weak acid], how is pH related to \(\mathrm{P} K_{\mathrm{a}}\) ?
What do you think about this solution?
We value your feedback to improve our textbook solutions.