A certain buffer is made by dissolving \(\mathrm{NaHCO}_{3}\) and \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) in some water. Write equations to show how this buffer neutralizes added \(\mathrm{H}^{+}\) and \(\overline{\mathrm{OH}}^{-}\).

Short Answer

Expert verified
The buffer neutralizes added H⁺ and OH⁻ ions through the reactions: \[ HCO_3^- + H^+ \rightarrow H_2CO_3 \] and \[ CO_3^{2-} + OH^- \rightarrow HCO_3^- \]

Step by step solution

01

Write the dissociation equations for NaHCO₃ and Na₂CO₃.

When dissolved in water, NaHCO₃ and Na₂CO₃ dissociate as follows: For NaHCO₃: \[ NaHCO_3 \rightarrow Na^+ + HCO_3^- \] For Na₂CO₃: \[ Na_2CO_3 \rightarrow 2Na^+ + CO_3^{2-} \]
02

Identify the acidic and basic species in the buffer.

In the buffer solution, HCO₃⁻ acts as the acidic species, and CO₃²⁻ acts as the basic species.
03

Write the equation for neutralization of H⁺ ions by HCO₃⁻.

When H⁺ ions are added to the buffer solution, HCO₃⁻ will react with them to neutralize the H⁺ ions. The reaction can be represented as follows: \[ HCO_3^- + H^+ \rightarrow H_2CO_3 \]
04

Write the equation for the neutralization of OH⁻ ions by CO₃²⁻.

When OH⁻ ions are added to the buffer solution, CO₃²⁻ will react with them to neutralize the OH⁻ ions. The reaction can be represented as follows: \[ CO_3^{2-} + OH^- \rightarrow HCO_3^- \] With these equations, we have found how the buffer solution neutralizes both H⁺ and OH⁻ ions added to it.

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Most popular questions from this chapter

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