You have the following reagents on hand: \begin{tabular}{|ll|} \hline Solids \(\left(\mathrm{p} \boldsymbol{K}_{\mathrm{a}}\right.\) of Acid Form Is Given) & Solutions \\ \hline Benzoic acid (4.19) & \(5.0 \mathrm{M} \mathrm{HCl}\) \\ Sodium acetate (4.74) & \(1.0 \mathrm{M}\) acetic acid (4.74) \\ Potassium fluoride (3.14) & \(2.6 \mathrm{M} \mathrm{NaOH}\) \\ Ammonium chloride (9.26) & \(1.0 \mathrm{M} \mathrm{HOCl}(7.46)\) \\ \hline \end{tabular} What combinations of reagents would you use to prepare buffers at the following \(\mathrm{pH}\) values? a. \(3.0\) b. \(4.0\) c. \(5.0\) d. \(7.0\) e. \(9.0\)

Short Answer

Expert verified
a. Potassium fluoride + 1.0 M acetic acid b. Benzoic acid + 5.0 M HCl, or Sodium acetate + 2.6 M NaOH c. Sodium acetate + 1.0 M acetic acid d. 1.0 M HOCl + ammonium chloride e. Ammonium chloride + 1.0 M HOCl, or Ammonium chloride + 2.6 M NaOH

Step by step solution

01

Review the Henderson-Hasselbalch equation

The Henderson-Hasselbalch equation is given by: \[pH = pKa + \log_{10}\left(\frac{[\mathrm{A}^-]}{[\mathrm{HA}]}\right)\] where: - \(pH\) is the desired pH value of the buffer solution - \(pKa\) is the acid dissociation constant of the weak acid - \([\mathrm{A}^-]\) is the concentration of the conjugate base of the weak acid - \([\mathrm{HA}]\) is the concentration of the weak acid We will use this equation to identify proper combinations of reagents for each given pH value.
02

Identify appropriate reagent combinations for each given pH value

For each pH value, we will look for a reagent pair whose pKa value is closest to the desired pH value. Once we have a pair, we can use the reagents to adjust the concentrations of \([\mathrm{A}^-]\) and \([\mathrm{HA}]\) to achieve the desired pH value. a. Desired pH: 3.0 The closest pKa value is 3.14 for potassium fluoride. We can combine potassium fluoride with a weak acid, such as 1.0 M acetic acid (4.74). b. Desired pH: 4.0 The closest pKa values are 4.19 for benzoic acid and 4.74 for sodium acetate. We can combine either benzoic acid or sodium acetate with a strong acid, such as 5.0 M HCl or a weak base, such as 2.6 M NaOH. c. Desired pH: 5.0 The closest pKa value is 4.74 for sodium acetate. We can combine sodium acetate with a weak acid, such as 1.0 M acetic acid (4.74). d. Desired pH: 7.0 The closest pKa value is 7.46 for 1.0 M HOCl. We can combine 1.0 M HOCl with a weak base, such as ammonium chloride (9.26). e. Desired pH: 9.0 The closest pKa value is 9.26 for ammonium chloride. We can combine ammonium chloride with a weak acid, such as 1.0 M HOCl (7.46), or a strong base, such as 2.6 M NaOH. By selecting appropriate reagents and adjusting their concentrations, we can prepare the desired buffer solutions at various pH values.

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Most popular questions from this chapter

Repeat the procedure in Exercise 55 , but for the titration of \(25.0 \mathrm{~mL}\) of \(0.100 M\) propanoic acid \(\left(\mathrm{HC}_{3} \mathrm{H}_{3} \mathrm{O}_{2}, K_{\mathrm{a}}=1.3 \times 10^{-5}\right)\) with \(0.100 \mathrm{M} \mathrm{NaOH}\).

In the titration of \(50.0 \mathrm{~mL}\) of \(1.0 \mathrm{M}\) methylamine, \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) \(\left(K_{\mathrm{b}}=4.4 \times 10^{-4}\right)\), with \(0.50 \mathrm{M} \mathrm{HCl}\), calculate the \(\mathrm{pH}\) under the following conditions. a. after \(50.0 \mathrm{~mL}\) of \(0.50 \mathrm{M} \mathrm{HCl}\) has been added b. at the stoichiometric point

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Consider a buffer solution where [weak acid] \(>\) [conjugate base]. How is the \(\mathrm{pH}\) of the solution related to the \(\mathrm{p} K_{\mathrm{a}}\) value of the weak acid? If [conjugate base] > [weak acid], how is pH related to \(\mathrm{P} K_{\mathrm{a}}\) ?

What are the major species in solution after \(\mathrm{NaHSO}_{4}\) is dissolved in water? What happens to the \(\mathrm{pH}\) of the solution as more \(\mathrm{NaHSO}_{4}\) is added? Why? Would the results vary if baking soda \(\left(\mathrm{NaHCO}_{3}\right)\) were used instead?

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