Using the kinetic molecular theory (Section 5.6), calculate the root mean square velocity and the average kinetic energy of \({ }_{1}^{2} \mathrm{H}\) nuclei at a temperature of \(4 \times 10^{7} \mathrm{~K}\). (See Exercise 46 for the appropriate mass values.)

Short Answer

Expert verified
The root-mean-square velocity of hydrogen nuclei at a temperature of \(4 \times 10^7 K\) is approximately \(6.03 \times 10^7\) m/s, and the average kinetic energy is \(8.172 \times 10^{-16} J\).

Step by step solution

01

Calculate the mass of a hydrogen nucleus

First, we need to obtain the mass of a hydrogen nucleus, which is a deuteron (2H) with one proton and one neutron. The mass of a deuteron is approximately the sum of the mass of a proton (1.6726 x 10^-27 kg) and neutron (1.6750 x 10^-27 kg). m = 1.6726 x 10^-27 kg (proton) + 1.6750 x 10^-27 kg (neutron) = 3.3476 x 10^-27 kg
02

Calculate the root-mean-square velocity

Now, we can calculate the root-mean-square velocity using the equation: v_rms = √(3kT/m) Here, k = Boltzmann's constant = 1.38 x 10^-23 J/K T = Temperature = 4 x 10^7 K m = Mass of hydrogen nucleus = 3.3476 x 10^-27 kg v_rms = √(3 * 1.38 x 10^-23 J/K * 4 x 10^7 K / 3.3476 x 10^-27 kg) v_rms = √(2.0284 x 10^4 m^2/s^2) v_rms = \(6.03 \times 10^7\) m/s The root-mean-square velocity of hydrogen nuclei is approximately \(6.03 \times 10^7\) m/s.
03

Calculate the average kinetic energy

Now we can calculate the average kinetic energy using the equation: KE_avg = (3/2) kT Here, k = Boltzmann's constant = 1.38 x 10^-23 J/K T = Temperature = 4 x 10^7 K KE_avg = (3/2) * 1.38 x 10^-23 J/K * 4 x 10^7 K KE_avg = \(8.172\) x 10^-16 J The average kinetic energy of hydrogen nuclei at a temperature of 4 x 10^7 K is approximately \(8.172\) x 10^-16 J.

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