Write the formula for each of the following compounds: a. chromium(VI) oxide b. disulfur dichloride c. nickel(II) fluoride d. potassium hydrogen phosphate e. aluminum nitride f. ammonia g. manganese(IV) sulfide h. sodium dichromate i. ammonium sulfite j. carbon tetraiodide

Short Answer

Expert verified
a. Cr2O6 b. S2Cl2 c. NiF2 d. K2HPO4 e. AlN f. NH3 g. MnS2 h. Na2Cr2O7 i. (NH4)2SO3 j. CI4

Step by step solution

01

a. Chromium(VI) oxide

Chromium has a charge of +6 (since it's mentioned with (VI) roman numeral), and oxygen has a charge of -2. To write the formula for chromium(VI) oxide, we need to balance the charges. The balanced formula for chromium(VI) oxide is Cr2O6.
02

b. Disulfur dichloride

In disulfur dichloride, there are 2 sulfur atoms and 2 chlorine atoms. The formula for disulfur dichloride is S2Cl2.
03

c. Nickel(II) fluoride

Nickel has a charge of +2 (since it's mentioned with (II) roman numeral), and fluoride has a charge of -1. To write the formula for nickel(II) fluoride, we need to balance the charges. The balanced formula for nickel(II) fluoride is NiF2.
04

d. Potassium hydrogen phosphate

Potassium has a charge of +1, hydrogen has a charge of +1, and the polyatomic ion phosphate (PO4) has a charge of -3. To write the formula for potassium hydrogen phosphate, we need to balance the charges. The balanced formula for potassium hydrogen phosphate is K2HPO4.
05

e. Aluminum nitride

Aluminum has a charge of +3, and nitrogen has a charge of -3. To write the formula for aluminum nitride, we need to balance the charges. The balanced formula for aluminum nitride is AlN.
06

f. Ammonia

Ammonia consists of one nitrogen atom and three hydrogen atoms. The formula for ammonia is NH3.
07

g. Manganese(IV) sulfide

Manganese has a charge of +4 (since it's mentioned with the (IV) roman numeral) and sulfur has a charge of -2. To write the formula for manganese(IV) sulfide, we need to balance the charges. The balanced formula for manganese(IV) sulfide is MnS2.
08

h. Sodium dichromate

Sodium has a charge of +1 and the polyatomic ion dichromate (Cr2O7) has a charge of -2. To write the formula for sodium dichromate, we need to balance the charges. The balanced formula for sodium dichromate is Na2Cr2O7.
09

i. Ammonium sulfite

The polyatomic ion ammonium (NH4) has a charge of +1, and the polyatomic ion sulfite (SO3) has a charge of -2. To write the formula for ammonium sulfite, we need to balance the charges. The balanced formula for ammonium sulfite is (NH4)2SO3.
10

j. Carbon tetraiodide

Carbon tetraiodide consists of one carbon atom and four iodine atoms. The formula for carbon tetraiodide is CI4.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a combustion reaction, \(46.0 \mathrm{~g}\) of ethanol reacts with \(96.0 \mathrm{~g}\) of oxygen to produce water and carbon dioxide. If \(54.0 \mathrm{~g}\) of water is produced, what mass of carbon dioxide is produced?

The designations IA through 8 A used for certain families of the periodic table are helpful for predicting the charges on ions in binary ionic compounds. In these compounds, the metals generally take on a positive charge equal to the family number, while the nonmetals take on a negative charge equal to the family number minus eight. Thus the compound between sodium and chlorine contains \(\mathrm{Na}^{+}\) ions and \(\mathrm{Cl}^{-}\) ions and has the formula \(\mathrm{NaCl}\). Predict the formula and the name of the binary compound formed from the following pairs of elements. a. \(\mathrm{Ca}\) and \(\mathrm{N}\) e. \(\mathrm{Ba}\) and \(\mathrm{I}\) b. \(\mathrm{K}\) and \(\mathrm{O}\) f. \(\mathrm{Al}\) and Se c. \(\mathrm{Rb}\) and \(\mathrm{F}\) g. Cs and P d. \(\mathrm{Mg}\) and \(\mathrm{S}\) h. In and \(\mathrm{Br}\)

Write the formula for each of the following compounds: a. sodium oxide h. copper(I) chloride b. sodium peroxide i. gallium arsenide c. potassium cyanide j. cadmium selenide d. copper(II) nitrate \(\mathbf{k}\). zinc sulfide e. selenium tetrabromide 1\. nitrous acid f. iodous acid \(\mathrm{m}\). diphosphorus pentoxide g. lead(IV) sulfide

Write the formula for each of the following compounds: a. zinc chloride d. aluminum sulfide b. \(\operatorname{tin}(\mathrm{IV})\) fluoride e. mercury(I) selenide c. calcium nitride f. silver iodide

In a reaction, \(34.0 \mathrm{~g}\) of chromium(III) oxide reacts with \(12.1 \mathrm{~g}\) of aluminum to produce chromium and aluminum oxide. If \(23.3 \mathrm{~g}\) of chromium is produced, what mass of aluminum oxide is produced?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free