Elemental boron is produced by reduction of boron oxide with magnesium to give boron and magnesium oxide. Write a balanced equation for this reaction.

Short Answer

Expert verified
The balanced equation for the reaction between boron oxide (B2O3) and magnesium (Mg) to produce elemental boron (B) and magnesium oxide (MgO) is: \(B2O3 + 3Mg -> 2B + 3MgO\)

Step by step solution

01

Write the unbalanced equation

Write down the reactants and products as a chemical equation, using the standard notation for compounds and elements. B2O3 + Mg -> B + MgO
02

Determine the number of atoms for each element in the equation

Count the number of atoms for each element: Reactants side: - Boron (B): 2 atoms - Oxygen (O): 3 atoms - Magnesium (Mg): 1 atom Products side: - Boron (B): 1 atom - Oxygen (O): 1 atom - Magnesium (Mg): 1 atom
03

Select an element to balance first

We can start by balancing the boron atoms. On the reactants side, we have 2 B atoms, and on the products side, we have 1 B atom.
04

Balance the boron atoms

Since we have 2 boron atoms on the reactants side and only 1 on the products side, we will need to place a 2 in front of the elemental boron (B) on the products side. This will create 2 boron atoms on both sides of the equation: B2O3 + Mg -> 2B + MgO
05

Balance the magnesium and oxygen atoms

Now, let's balance the magnesium atoms. After placing a 2 in front of the elemental boron, the number of magnesium and oxygen atoms on both sides of the equation are: Reactants side: - Magnesium (Mg): 1 atom - Oxygen (O): 3 atoms Products side: - Magnesium (Mg): 1 atom - Oxygen (O): 1 atom To balance the oxygen atoms, we can place a 3 in front of the magnesium oxide (MgO) on the products side. This will give us 3 magnesium and 3 oxygen atoms. We also need to place a 3 in front of the magnesium (Mg) on the reactants side to balance the magnesium atoms: B2O3 + 3Mg -> 2B + 3MgO
06

Check if the equation is balanced

Now, let's check if the equation is balanced by counting the number of atoms for each element on both sides of the equation: Reactants side: - Boron (B): 2 atoms - Oxygen (O): 3 atoms - Magnesium (Mg): 3 atoms Products side: - Boron (B): 2 atoms - Oxygen (O): 3 atoms - Magnesium (Mg): 3 atoms Since the number of atoms for each element is the same on both sides of the equation, the equation is balanced: B2O3 + 3Mg -> 2B + 3MgO

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What will be the atomic number of the next alkali metal to be discovered? How would you expect the physical properties of the next alkali metal to compare with the properties of the other alkali metals summarized in Table \(20.4 ?\)

Lewis structures can be used to understand why some molecules react in certain ways. Write the Lewis structure for the reactants and products in the reactions described below. a. Nitrogen dioxide dimerizes to produce dinitrogen tetroxide. b. Boron trihydride accepts a pair of electrons from ammonia, forming \(\mathrm{BH}_{3} \mathrm{NH}_{3}\). Give a possible explanation for why these two reactions occur.

Lead forms compounds in the \(+2\) and \(+4\) oxidation states. All lead(II) halides are known (and are known to be ionic). Only \(\mathrm{PbF}_{4}\) and \(\mathrm{PbCl}_{4}\) are known among the possible lead(IV) halides. Presumably lead(IV) oxidizes bromide and iodide ions, producing the lead(II) halide and the free halogen: Suppose \(25.00 \mathrm{~g}\) of a lead(IV) halide reacts to form \(16.12 \mathrm{~g}\) of a lead(II) halide and the free halogen. Identify the halogen.

The three most stable oxides of carbon are carbon monoxide (CO), carbon dioxide \(\left(\mathrm{CO}_{2}\right)\), and carbon suboxide \(\left(\mathrm{C}_{3} \mathrm{O}_{2}\right)\). The space-filling models for these three compounds are For each oxide, draw the Lewis structure, predict the molecular structure, and describe the bonding (in terms of the hybrid orbitals for the carbon atoms).

Arsenic reacts with oxygen to form oxides that react with water in a manner analogous to that of the phosphorus oxides. Write balanced chemical equations describing the reaction of arsenic with oxygen and the reaction of the resulting oxide with water.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free