Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 20: Problem 42

Tin forms compounds in the \(+2\) and \(+4\) oxidation states. Therefore, when tin reacts with fluorine, two products are possible. Write balanced equations for the production of the two tin halide compounds and name them.

Short Answer

Expert verified
The two balanced equations for the formation of tin halide compounds when tin reacts with fluorine are: 1. \( 2Sn + 2F2 \rightarrow 2SnF2 \) (Tin(II) fluoride) 2. \( Sn + 2F2 \rightarrow SnF4 \) (Tin(IV) fluoride)

Step by step solution

01

Determine the chemical formulas for the two tin halide compounds.

Tin has two possible oxidation states, +2 and +4, and fluorine has an oxidation state of -1. The first compound will have tin in a +2 oxidation state and the second compound will have tin in a +4 oxidation state. To balance the charges in the compounds, we use the following formulas: 1. Tin(+2) + Fluorine(-1) --> SnF2 2. Tin(+4) + Fluorine(-1) --> SnF4 Now we have the chemical formulas for the two tin halide compounds.
02

Write the balanced equations for the production of the tin halide compounds.

To write the balanced equations for the production of these compounds, we start with the unbalanced equation and then balance it according to the law of conservation of mass. Since there are only two reactants in each reaction (tin and fluorine), the balancing process is straightforward. 1. Unbalanced equation (first tin halide compound): Sn + F2 → SnF2 Balanced equation: 2Sn + 2F2 → 2SnF2 2. Unbalanced equation (second tin halide compound): Sn + F2 → SnF4 Balanced equation: Sn + 2F2 → SnF4 Now we have balanced equations for both reactions.
03

Name the tin halide compounds.

Now that we have written the balanced equations for the formation of the tin halide compounds, we can name them. The names for metallic compounds follow the pattern "metal name" + "halide name." + Roman numeral, to indicate the oxidation state of the metal if it forms multiple compounds. 1. First tin halide compound (SnF2): Name - Tin(II) fluoride 2. Second tin halide compound (SnF4): Name - Tin(IV) fluoride In summary, the two balanced equations for the formation of tin halide compounds are: 1. 2Sn + 2F2 → 2SnF2 (Tin(II) fluoride) 2. Sn + 2F2 → SnF4 (Tin(IV) fluoride)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Elemental boron is produced by reduction of boron oxide with magnesium to give boron and magnesium oxide. Write a balanced equation for this reaction.

Captain Kirk has set a trap for the Klingons who are threatening an innocent planet. He has sent small groups of fighter rockets to sites that are invisible to Klingon radar and put a decoy in the open. He calls this the "fishhook" strategy. Mr. Spock has sent a coded message to the chemists on the fighters to tell the ships what to do next. The outline of the message is Fill in the blanks of the message using the following clues. (1) Symbol of the halogen whose hydride has the second highest boiling point in the series of HX compounds that are hydrogen halides. (2) Symbol of the halogen that is the only hydrogen halide, \(\mathrm{HX}\), that is a weak acid in aqueous solution. (3) Symbol of the element whose existence on the sun was known before its existence on earth was discovered. (4) The Group \(5 \mathrm{~A}\) element in Table \(20.13\) that should have the most metallic character. (5) Symbol of the Group \(6 \mathrm{~A}\) element that, like selenium, is a semiconductor. (6) Symbol for the element known in rhombic and monoclinic forms. (7) Symbol for the element that exists as diatomic molecules in a yellow-green gas when not combined with another element. (8) Symbol for the most abundant element in and near the earth's crust. (9) Symbol for the element that seems to give some protection against cancer when a diet rich in this element is consumed. (10) Symbol for the smallest noble gas that forms compounds with fluorine having the general formula \(\mathrm{AF}_{2}\) and \(\mathrm{AF}_{4}\) (reverse the symbol and split the letters as shown). (11) Symbol for the toxic element that, like phosphorus and antimony, forms tetrameric molecules when uncombined with other elements (split the letters of the symbol as shown). (12) Symbol for the element that occurs as an inert component of air but is a very prominent part of fertilizers and explosives.

What is nitrogen fixation? Give some examples of nitrogen fixation.

There is evidence that radon reacts with fluorine to form compounds similar to those formed by xenon and fluorine. Predict the formulas of these \(\mathrm{RnF}_{x}\) compounds. Why is the chemistry of radon difficult to study?

The \(\mathrm{N}_{2} \mathrm{O}\) molecule is linear and polar. a. On the basis of this experimental evidence, which arrangement, NNO or NON, is correct? Explain your answer. b. On the basis of your answer to part a, write the Lewis structure of \(\mathrm{N}_{2} \mathrm{O}\) (including resonance forms). Give the formal charge on each atom and the hybridization of the central atom. c. How would the multiple bonding in $$: \mathrm{N} \equiv \mathrm{N}-\mathrm{O}$$ be described in terms of orbitals?
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Kinetics

Read Explanation

Chemical Analysis

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Chemical Reactions

Read Explanation

Physical Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free