The oxyanion of nitrogen in which it has the highest oxidation state is the nitrate ion \(\left(\mathrm{NO}_{3}^{-}\right)\). The corresponding oxyanion of phosphorus is \(\mathrm{PO}_{4}^{3-}\). The \(\mathrm{NO}_{4}{ }^{3-}\) ion is known but not very stable. The \(\mathrm{PO}_{3}^{-}\) ion is not known. Account for these differences in terms of the bonding in the four anions.

Short Answer

Expert verified
The stability of the nitrate (NO₃⁻) and phosphate (PO₄³⁻) ions is attributed to their maximum oxidation states, resonance, and strong bonding. The less stable NO₄³⁻ ion suffers from the violation of the octet rule and a higher energy state of nitrogen, which destabilizes it. Meanwhile, the absence of the PO₃⁻ ion results from the weaker ability of phosphorus to stabilize this configuration through resonance and its reduced oxidation state, as well the influence of strong electron-donating groups.

Step by step solution

01

Recall the electronegativity and oxidation states of nitrogen and phosphorus

Nitrogen and phosphorus belong to Group 15 of the periodic table, with nitrogen having a higher electronegativity compared to phosphorus (3.04 vs 2.19). This means that nitrogen attracts electrons more strongly than phosphorus, resulting in a larger oxidation state range for nitrogen (-3 to +5) than phosphorus (-3 to +5).
02

Examine the bonding in nitrate ion (NO₃⁻)

The nitrate ion (NO₃⁻) has nitrogen as its central atom, with an oxidation state of +5 (maximum). The Lewis structure of NO₃⁻ reveals three N-O bonds with one double bond and one negative formal charge on each of the three oxygen atoms. Resonance in the structure makes the electrons in the double bond to be delocalized over the three bonds leading to the formation of partial double bonds, strengthening the bonding, and ensuring stability of the ion.
03

Examine the bonding in phosphate ion (PO₄³⁻)

The phosphate ion (PO₄³⁻) has phosphorus as its central atom, with an oxidation state of +5 (maximum). The Lewis structure of PO₄³⁻ shows four P-O bonds, each with a double bond character due to the presence of three negative charges on oxygen atoms. The distribution of charges across the oxygens allows for resonance and the formation of partial double bonds, improving stability.
04

Compare bonding in less stable NO₄³⁻ ion

The less stable NO₄³⁻ ion has nitrogen as its central atom in the highest oxidation state, +5. The Lewis structure of NO₄³⁻ reveals four N-O bonds and corresponds to N double bonding with four oxygen atoms, which would require nitrogen to make use of its lone pair. However, this arrangement breaks the octet rule, leading to instability due to the higher energy state of the nitrogen atom. This arrangement also does not provide resonance structures to stabilize the ion.
05

Discuss the absence of PO₃⁻ ion

The PO₃⁻ ion is not known, it would feature phosphorus as its central atom in the +3 oxidation state. This ion would require a Lewis structure with three P-O bonds, which is similar to the bonding in NO₃⁻. However, the lower electronegativity of phosphorus compared to nitrogen makes it less capable of stabilizing this ion through resonance and partial double bonding. Furthermore, the reduced oxidation state would make it difficult for phosphorus to hold on to the three negative charges on the oxygen atoms in the presence of strong electron-donating groups that could easily reduce phosphorus to a lower oxidation state.
06

Conclusion

The stability of the nitrate (NO₃⁻) and phosphate (PO₄³⁻) ions is mainly due to their maximum oxidation states, resonance, and strong bonding. The less stable NO₄³⁻ ion is attributed to the violation of the octet rule, and higher nitrogen energy state. The absence of the PO₃⁻ ion can be explained by the weaker ability of phosphorus to stabilize this configuration through resonance, reduced oxidation state, and the influence of strong electron-donating groups.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
Understanding the concept of oxidation states is crucial when exploring the stability of oxyanions. An element's oxidation state indicates the degree of oxidation or loss of electrons it has undergone when forming a compound or ion. In oxyanions like nitrate (NO_{3}^{-}) and phosphate (PO_{4}^{3-}), the central atoms nitrogen and phosphorus have their highest oxidation states, +5.

This higher oxidation state correlates with a greater number of bonds to oxygen atoms, which typically have a negative charge. In the case of nitrate, the central nitrogen forms bonds with three oxygen atoms, while in phosphate, it forms bonds with four. The high oxidation state also suggests a significant transfer of electron density from the central atom to the surrounding oxygens, contributing to the stability of the ions. In contrast, the instability of nitrate (NO_{4}^{3-}) is partly due to its central nitrogen atom being unable to maintain this higher oxidation state stably across four bonds.

A deeper dive into Lewis structures will shed more light on the significance of electron distribution in these ions.
Lewis Structures
The notation of Lewis structures plays a pivotal role in visualizing the bonding and electron distribution within a molecule or ion. For oxyanions, these diagrams offer a snapshot of where the electrons are and how they are shared between atoms. In the Lewis structure of an ion like NO_{3}^{-}, for example, nitrogen is represented at the center with three oxygen atoms surrounding it. Each oxygen atom has a negative formal charge, and the nitrogen has a positive charge, equaling the overall negative charge of the ion.

The dative bonds indicated by the Lewis structure help to explain the even distribution of electrons, which is further elaborated upon by resonance in chemistry. Notably, for the less stable NO_{4}^{3-} ion, its Lewis structure would break the octet rule because nitrogen cannot accommodate more than eight electrons in its valence shell. This leads to an unfavorable high energy state which contributes to the ion's instability. In contrast, the Lewis structure of PO_{4}^{3-} respects the octet rule and shows more stable electron configuration.
Resonance in Chemistry
The stability of oxyanions is greatly influenced by the concept of resonance in chemistry. Resonance refers to the delocalization of electrons across different parts of a molecule or ion. In structures where resonance occurs, such as the NO_{3}^{-} ion, the actual electronic distribution is a hybrid of all possible resonance structures. These structures distribute the charge more evenly across the molecule, leading to a lower overall energy state and resulting in a more stable species. For NO_{3}^{-}, this means that the double bond character is shared among the three nitrogen-oxygen bonds, rather than being localized to just one bond.

The absence of resonance in the NO_{4}^{3-} ion contributes to its instability since the charge and the double bond character cannot be similarly distributed. Furthermore, resonance allows for the effective delocalization of negative charges across the oxygen atoms, as is observed in the PO_{4}^{3-} ion. In contrast, the theoretical PO_{3}^{-} ion, which does not exist in nature, would lack the stabilizing influence of extensive resonance due to the lower electronegativity of phosphorus, explaining its absence.

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Most popular questions from this chapter

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