The Group 5 A elements can form molecules or ions that involve three, five, or six covalent bonds; \(\mathrm{NH}_{3}, \mathrm{AsCl}_{5}\), and \(\mathrm{PF}_{6}^{-}\) are examples. Draw the Lewis structure for each of these substances, and predict the molecular structure and hybridization for each. Why doesn't \(\mathrm{NF}_{5}\) or \(\mathrm{NCl}_{6}^{-}\) form?

Short Answer

Expert verified
The Lewis structures, molecular structures, and hybridizations for NH₃, AsCl₅, and PF₆⁻ are as follows: 1. NH₃: Lewis structure: N with 3 single bonds to H atoms and 1 lone pair. Molecular structure: Trigonal pyramidal. Hybridization: sp³. 2. AsCl₅: Lewis structure: As with 5 single bonds to Cl atoms. Molecular structure: Trigonal bipyramidal. Hybridization: sp³d. 3. PF₆⁻: Lewis structure: P with 6 single bonds to F atoms. Molecular structure: Octahedral. Hybridization: sp³d². NF₅ and NCl₆⁻ do not form because nitrogen's 2p orbitals cannot accommodate enough electrons for the required number of bonds and due to steric hindrance from the larger Cl atoms.

Step by step solution

01

NH₃ (Ammonia)

1. Calculate the total number of valence electrons: N has 5 valence electrons and H has 1 valence electron. Since there are 3 H atoms, the total number of valence electrons is 5 + (3 × 1) = 8. 2. Draw the Lewis structure: Place N in the center, and bond each H to N with a single bond. N will have 1 lone pair of electrons remaining. H | H - N | H 3. Determine the molecular structure and hybridization: As there are 3 bonded atom groups and 1 lone pair, the electron pair geometry is tetrahedral. Due to the presence of a lone pair, the molecular structure is trigonal pyramidal. Hybridization is sp³.
02

AsCl₅ (Arsenic pentafluoride)

1. Calculate the total number of valence electrons: As has 5 valence electrons and Cl has 7 valence electrons. Since there are 5 Cl atoms, the total number of valence electrons is 5 + (5 × 7) = 40. 2. Draw the Lewis structure: Place As in the center, and bond each Cl to As with a single bond. Cl - As - Cl | _ _ | Cl - - Cl | Cl 3. Determine the molecular structure and hybridization: As there are 5 bonded atom groups and no lone pairs, the electron pair geometry and molecular structure are trigonal bipyramidal. Hybridization is sp³d.
03

PF₆⁻ (Hexafluorophosphate)

1. Calculate the total number of valence electrons: P has 5 valence electrons and F has 7 valence electrons. Since there are 6 F atoms, the total number of valence electrons is 5 + (6 × 7) + 1 (due to the negative charge) = 48. 2. Draw the Lewis structure: Place P in the center, and bond each F to P with a single bond. F | F - P - F _|_| F F | F 3. Determine the molecular structure and hybridization: As there are 6 bonded atom groups and no lone pairs, the electron pair geometry and molecular structure are octahedral. Hybridization is sp³d².
04

Explaining why NF₅ and NCl₆⁻ do not form

NF₅ cannot form because nitrogen has only 5 valence electrons. For 5 single bonds with F, it would need 10 electrons, which would require borrowing more electrons than it can accommodate in its 2p orbitals. NCl₆⁻ cannot form because nitrogen has only 5 valence electrons, and for 6 single bonds with Cl, it would need 12 electrons. This would also require borrowing more electrons than it can accommodate in its 2p orbitals. Additionally, the bulky size of the Cl atoms may create repulsive forces, preventing them from forming such a structure.

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Most popular questions from this chapter

In each of the following pairs of substances, one is stable and known, and the other is unstable. For each pair, choose the stable substance, and explain why the other is unstable. a. \(\mathrm{NF}_{5}\) or \(\mathrm{PF}_{5}\) b. \(\mathrm{AsF}_{5}\) or \(\mathrm{AsI}_{5}\) c. \(\mathrm{NF}_{3}\) or \(\mathrm{NBr}_{3}\)

Phosphate buffers are important in regulating the \(\mathrm{pH}\) of intracellular fluids at \(\mathrm{pH}\) values generally between \(7.1\) and \(7.2\). What is the concentration ratio of \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) to \(\mathrm{HPO}_{4}^{2-}\) in intracellular fluid at \(\mathrm{pH}=7.15 ?\) \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}(a q) \rightleftharpoons \mathrm{HPO}_{4}^{2-}(a q)+\mathrm{H}^{+}(a q) \quad K_{\mathrm{a}}=6.2 \times 10^{-8}\) Why is a buffer composed of \(\mathrm{H}_{3} \mathrm{PO}_{4}\) and \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) ineffective in buffering the \(\mathrm{pH}\) of intracellular fluid? \(\mathrm{H}_{3} \mathrm{PO}_{4}(a q) \rightleftharpoons \mathrm{H}_{2} \mathrm{PO}_{4}^{-}(a q)+\mathrm{H}^{+}(a q) \quad K_{\mathrm{a}}=7.5 \times 10^{-3}\)

Thallium and indium form \(+1\) and \(+3\) oxidation states when in compounds. Predict the formulas of the possible compounds between thallium and oxygen and between indium and chlorine. Name the compounds.

Halogens form a variety of covalent compounds with each other. For example, chlorine and fluorine form the compounds CIF, \(\mathrm{ClF}_{3}\), and \(\mathrm{ClF}_{5}\). Predict the molecular structure (including bond angles) for each of these three compounds. Would you expect \(\mathrm{FCl}_{3}\) to be a stable compound? Explain.

a. Many biochemical reactions that occur in cells require relatively high concentrations of potassium ion \(\left(\mathrm{K}^{+}\right) .\) The concentration of \(\mathrm{K}^{+}\) in muscle cells is about \(0.15 \mathrm{M}\). The concentration of \(\mathrm{K}^{+}\) in blood plasma is about \(0.0050 M\). The high internal concentration in cells is maintained by pumping \(\mathrm{K}^{+}\) from the plasma. How much work must be done to transport \(1.0 \mathrm{~mol} \mathrm{~K}^{+}\) from the blood to the inside of a muscle cell at \(37^{\circ} \mathrm{C}\) (normal body temperature)? b. When \(1.0 \mathrm{~mol} \mathrm{~K}^{+}\) is transferred from blood to the cells, do any other ions have to be transported? Why or why not? c. Cells use the hydrolysis of adenosine triphosphate, abbreviated ATP, as a source of energy. Symbolically, this reaction can be represented as $$\operatorname{ATP}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{ADP}(a q)+\mathrm{H}_{2} \mathrm{PO}_{4}^{-}(a q)$$ where ADP represents adenosine diphosphate. For this reaction at \(37^{\circ} \mathrm{C}, K=1.7 \times 10^{5}\). How many moles of ATP must be hydrolyzed to provide the energy for the transport of \(1.0 \mathrm{~mol}\) \(\mathrm{K}^{+}\) ? Assume standard conditions for the ATP hydrolysis reaction.

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