Draw all the geometrical isomers of \(\left[\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2} \mathrm{BrCl}\right]^{+} .\) Which of these isomers also have an optical isomer? Draw the various isomers.

Short Answer

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The geometrical isomers of the complex ion \(\left[\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2}\mathrm{BrCl}\right]^{+}\) are: a) Trans isomer: NH_3 ligands are trans to each other, and the en ligand and the two halides (Br and Cl) are in a mer arrangement. b) Cis isomer: NH_3 ligands are cis to each other, and the en ligand and the two halides (Br and Cl) are in a fac arrangement. The cis isomer has an optical isomer (enantiomers), while the trans isomer does not have any optical isomers.

Step by step solution

01

Identify the type of isomerism and the ligands

The given complex ion is \(\left[\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2}\mathrm{BrCl}\right]^{+}\), which consists of one Cr(III) central metal ion bonded to one ethylenediamine (en) ligand, two ammonia (NH_3) ligands, and two different halides (Br and Cl). Since we are asked to find the geometrical isomers of the complex, we will be focusing on cis/trans or fac/mer isomerism, depending on the arrangement of ligands around the central metal ion.
02

Determine the structure and coordination number of the complex

Since there are six ligand sites, the complex has a coordination number of six and is octahedral in shape. The Cr(III) metal ion is at the center, surrounded by the ligands.
03

Identify the geometrical isomers

In this octahedral complex, we will examine the possible arrangements of the ligands, keeping in mind the following types of isomerism: 1. Cis/Trans isomerism: Occurs when two ligands of the same type are either on the same plane (cis) or are opposite to each other (trans) on the central metal ion. 2. Fac/Mer isomerism: Refers to the arrangement of three ligands of the same type in either a facial (fac) manner, where they occupy one triangular face of the octahedron, or in a meridional (mer) manner, where they occupy a plane that contains the metal ion. For the given complex ion, the geometrical isomers we need to consider are: 1. Cis or trans to the two NH_3 ligands. 2. Fac or mer for the arrangement of the en ligand and the two halides (Br and Cl). Considering the geometrical isomers, we can draw the following: a) Trans isomer: NH_3 ligands are trans to each other, and the en ligand and the two halides (Br and Cl) are in a mer arrangement. b) Cis isomer: NH_3 ligands are cis to each other, and the en ligand and the two halides (Br and Cl) are in a fac arrangement.
04

Determine if the geometrical isomers have optical isomers

To decide if the geometrical isomers have optical isomers, we need to check if the complex molecule has any plane of symmetry or center of symmetry. If a geometrical isomer has no plane or center of symmetry, then it will have an optical isomer (the molecule and its mirror image cannot be superimposed). a) Trans isomer: This isomer has a plane of symmetry, and thus, it does not have any optical isomers. b) Cis isomer: This isomer does not have a plane of symmetry or a center of symmetry, and thus, it has optical isomers (enantiomers). In conclusion, the cis isomer of the complex ion \(\left[\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2}\mathrm{BrCl}\right]^{+}\) has an optical isomer, while the trans isomer does not.

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Most popular questions from this chapter

a. In the absorption spectrum of the complex ion [Cr(NCS) \(\left._{6}\right]^{3-}\), there is a band corresponding to the absorption of a photon of light with an energy of \(1.75 \times 10^{4} \mathrm{~cm}^{-1}\). Given \(1 \mathrm{~cm}^{-1}=\) \(1.986 \times 10^{-23} \mathrm{~J}\), what is the wavelength of this photon? b. The \(\mathrm{Cr}-\mathrm{N}-\mathrm{C}\) bond angle in \(\left[\mathrm{Cr}(\mathrm{NCS})_{6}\right]^{3-}\) is predicted to be \(180^{\circ}\). What is the hybridization of the \(\mathrm{N}\) atom in the \(\mathrm{NCS}^{-}\) ligand when a Lewis acid-base reaction occurs between \(\mathrm{Cr}^{3+}\) and \(\mathrm{NCS}^{-}\) that would give a \(180^{\circ} \mathrm{Cr}-\mathrm{N}-\mathrm{C}\) bond angle? \(\left[\mathrm{Cr}(\mathrm{NCS})_{6}\right]^{3-}\) undergoes substitution by ethylenediammine (en) according to the equation \(\left[\mathrm{Cr}(\mathrm{NCS})_{6}\right]^{3-}+2 \mathrm{en} \longrightarrow\left[\mathrm{Cr}(\mathrm{NCS})_{2}(\mathrm{en})_{2}\right]^{+}+4 \mathrm{NCS}^{-}\) Does \(\left[\mathrm{Cr}(\mathrm{NCS})_{2}(\mathrm{en})_{2}\right]^{+}\) exhibit geometric isomerism? Does \(\left[\mathrm{Cr}(\mathrm{NCS})_{2}(\mathrm{en})_{2}\right]^{+}\) exhibit optical isomerism?

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