Bacterial digestion is an economical method of sewage treatment. The reaction \(5 \mathrm{CO}_{2}(g)+55 \mathrm{NH}_{4}^{+}(a q)+76 \mathrm{O}_{2}(g)\) \(\mathrm{C}_{5} \mathrm{H}_{7} \mathrm{O}_{2} \mathrm{~N}(s)+54 \mathrm{NO}_{2}^{-}(a q)+52 \mathrm{H}_{2} \mathrm{O}(l)+109 \mathrm{H}^{+}(a q)\)

Short Answer

Expert verified
In this bacterial digestion reaction, the balanced chemical equation given is: \(5 CO_2(g) + 55 NH_4^+(aq) + 76 O_2(g) \rightarrow C_5H_7O_2N(s)+ 54 NO_2^-(aq) + 52 H_2O(l) + 109 H^+(aq)\) To solve a related problem, follow these steps: 1. Identify known and unknown values in the problem. 2. Convert grams to moles or vice versa using molar masses. 3. Apply stoichiometry by using the stoichiometric coefficients in the balanced chemical equation to find the unknown values. 4. Convert the result back into grams if needed. 5. Check the answer for reasonableness and consistency with the given information and the balanced chemical equation.

Step by step solution

01

Understand the balanced chemical equation

In this bacterial digestion reaction, 5 molecules of carbon dioxide (\(CO_2\)), 55 ammonium ions (\(NH_4^+\)), and 76 molecules of oxygen (\(O_2\)) are consumed. On the other hand, one molecule of cellular material (\(C_5H_7O_2N\)), 54 nitrite ions (\(NO_2^-\)), 52 water molecules (\(H_2O\)), and 109 hydrogen ions (\(H^+\)) are produced.
02

Identify the known and unknown values

Suppose we are given a certain quantity of one or more reactants or products and asked to determine the quantity of another reactant or product in the reaction. First, identify the given information in the problem and determine what you need to find.
03

Convert moles to grams and grams to moles

When converting the given quantities from grams to moles or vice versa, use the molar mass of each involved substance. For example, if you are given the mass of \(O_2\) in grams, divide it by the molar mass of \(O_2\) (32 g/mol) to find the moles of \(O_2\). Similarly, if you have the moles of \(NH_4^+\) and need to find the mass in grams, multiply it by the molar mass of \(NH_4^+\) (18.04 g/mol).
04

Use stoichiometry to find the unknown values

Apply stoichiometry to determine the amount of other reactants or products based on the given information. For instance, if you know the moles of \(NH_4^+\), you can determine the moles of \(NO_2^-\) by using the stoichiometric coefficient: moles of \(NO_2^-\) = (moles of \(NH_4^+\) × 54) / 55 Once you have the moles of the unknown substance, you can convert it into grams by multiplying it by the molar mass of the substance.
05

Check your answer

Make sure your answer is reasonable in the context of the problem. Double-check the calculations and units to ensure they are consistent with the balanced chemical equation and with the given information.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balanced Chemical Equations
Understanding balanced chemical equations is essential in the field of stoichiometry. A balanced chemical equation accurately represents the conservation of mass in a chemical reaction. It means that the number of atoms of each element in the reactants side is equal to the number of atoms of that element in the products side.

For the bacterial digestion equation, the balancing act looks like this: for every five molecules of carbon dioxide ((CO_2)), 55 ammonium ions ((NH_4^+)), and 76 molecules of oxygen ((O_2)) consumed, the bacteria produce one molecule of cellular material ((C_5H_7O_2N)), 54 nitrite ions ((NO_2^-)), 52 water molecules ((H_2O)), and 109 hydrogen ions ((H^+)). Balancing is critical because without it, stoichiometric calculations would not yield accurate and meaningful results.
Molar Mass Conversions
Molar mass conversions are a cornerstone of chemical calculations, allowing us to transition between the mass of a substance and the number of moles. The molar mass is the weight of one mole of a substance, typically expressed in grams per mole (g/mol).

In our exercise, to go from the mass of a reactant like oxygen to its molar equivalent, we divide the mass by oxygen's molar mass (32 g/mol). Conversely, if we've determined the number of moles of ammonium ions needed, we can find the mass required by multiplying by the molar mass of (NH_4^+), which is 18.04 g/mol. Mastering these conversions is key to performing accurate stoichiometric calculations.
Stoichiometric Calculations
Stoichiometric calculations are the mathematical methods we use to quantify the relationships in a balanced chemical equation. They enable us to predict the amount of reactants required to form a certain amount of product or vice versa.

For example, in a bacterial digestion scenario, if we know the amount of ammonium ions ((NH_4^+)) involved, we can calculate the corresponding amount of nitrite ions ((NO_2^-)) formed using the stoichiometric coefficients from the balanced equation. The coefficients tell us that for every 55 moles of (NH_4^+), 54 moles of (NO_2^-) are produced. Through these calculations, we can deduce the precise ratios and make practical predictions about the outcomes of the chemical reaction.
Chemical Reaction Quantification
Chemical reaction quantification involves determining the extent to which a chemical reaction has proceeded. This encompasses identifying the limiting reactant, calculating the theoretical yield, and possibly determining the reaction's percent yield.

In our exercise concerning bacterial digestion, if we are given a certain amount of (CO_2), (NH_4^+), and (O_2), we can use the balanced equation to ascertain how much (C_5H_7O_2N), (NO_2^-), and other products would be generated under ideal conditions. This is where the practical application of stoichiometry comes alive, enabling us to predict and measure the actual efficiency of bacterial digestion in treating sewage.

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Most popular questions from this chapter

A given sample of a xenon fluoride compound contains molecules of the type \(\mathrm{XeF}_{n}\), where \(n\) is some whole number. Given that \(9.03 \times 10^{20}\) molecules of \(\mathrm{XeF}_{n}\) weigh \(0.368 \mathrm{~g}\), determine the value for \(n\) in the formula.

Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel rocket motors. The reaction is $$ \mathrm{Fe}_{2} \mathrm{O}_{3}(s)+2 \mathrm{Al}(s) \longrightarrow 2 \mathrm{Fe}(l)+\mathrm{Al}_{2} \mathrm{O}_{3}(s) $$ What masses of iron(III) oxide and aluminum must be used to produce \(15.0 \mathrm{~g}\) iron? What is the maximum mass of aluminum oxide that could be produced?

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Glass is a mixture of several compounds, but a major constituent of most glass is calcium silicate, \(\mathrm{CaSiO}_{3}\). Glass can be etched by treatment with hydrofluoric acid; HF attacks the calcium silicate of the glass, producing gaseous and water-soluble products (which can be removed by washing the glass). For example, the volumetric glassware in chemistry laboratories is often graduated by using this process. Balance the following equation for the reaction of hydrofluoric acid with calcium silicate. $$ \mathrm{CaSiO}_{3}(s)+\mathrm{HF}(a q) \longrightarrow \mathrm{CaF}_{2}(a q)+\mathrm{SiF}_{4}(g)+\mathrm{H}_{2} \mathrm{O}(l) $$

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