Many cereals are made with high moisture content so that the cereal can be formed into various shapes before it is dried. A cereal product containing \(58 \% \mathrm{H}_{2} \mathrm{O}\) by mass is produced at the rate of \(1000 . \mathrm{kg} / \mathrm{h} .\) What mass of water must be evaporated per hour if the final product contains only \(20 . \%\) water?

#tag_title#Step 2: Calculate the final mass of water#tag_content#Now, let's find the mass of water in the final cereal product. The mass percentage is given as 20%. We will multiply the mass percentage by the total mass of the cereal product: Mass of water finally = (Percentage of water finally) x (Total mass of cereal product) \(Mass\,of\,water\,finally = 0.20 \times 1000\, kg\) #tag_title#Step 3: Calculate the mass of water evaporated#tag_content#To find the mass of water evaporated per hour, we subtract the final mass of water from the initial mass of water: Mass of water evaporated = Mass of water initially - Mass of water finally #tag_title#Answer#tag_content#\(Mass\,of\,water\,evaporated = (0.58 \times 1000\, kg) - (0.20 \times 1000\, kg) = 380\, kg/h\)