A sample of a hydrocarbon (a compound consisting of only carbon and hydrogen) contains \(2.59 \times 10^{2.3}\) atoms of hydrogen and is \(17.3 \%\) hydrogen by mass. If the molar mass of the hydrocarbon is between 55 and \(65 \mathrm{~g} / \mathrm{mol}\), what amount (moles) of compound is present, and what is the mass of the sample?

Short Answer

Expert verified
The moles of hydrogen in the sample is \(\frac{2.59 \times 10^{2.3}}{6.022 \times 10^{23}}\). The hydrocarbon has a formula of \(C_5H_{12}\) with a molar mass of \(60 \ \mathrm{g/mol}\). The moles of the sample can be calculated as moles of hydrogen divided by \(12\). The mass of the sample can be found by multiplying the moles of the hydrocarbon by its molar mass (\(60 \ \mathrm{g/mol}\)).

Step by step solution

01

Calculate the moles of hydrogen atoms

As given, we have \(2.59 \times 10^{2.3}\) atoms of hydrogen in the sample, convert this into moles by dividing by Avogadro's number (\(6.022 \times 10^{23}\ \mathrm{atoms/mol}\): Moles of hydrogen \(= \frac{2.59 \times 10^{2.3}}{6.022 \times 10^{23}}\)
02

Determine the molar mass of the hydrocarbon

Since the sample is 17.3% hydrogen by mass, that means the hydrogen mass is 17.3% of the total hydrocarbon mass. Considering the molar mass of hydrogen to be 1 g/mol, we can find the total molar mass of the hydrocarbon. Let \(M\) be the molar mass of the hydrocarbon: \(0.173 M = \) moles of hydrogen \(\times 1 \mathrm{g/mol}\)
03

Calculate the moles of the sample

Now we know the molar mass of the hydrocarbon, which is between 55 g/mol and 65 g/mol. We can find the moles of the hydrocarbon present in the sample by dividing the moles of hydrogen by the number of moles of hydrogen in 1 mole of hydrocarbon. Since 1 mole of hydrocarbon has x moles of hydrogen, first we need to find the formula of the hydrocarbon. Considering \(CxHy\) to be the hydrocarbon formula and since the molar mass of carbon is 12 g/mol: \(M = x(12 \ g/mol) + y(1 \ g/mol)\) In this equation, we know that the molar mass of the hydrocarbon \(M\) is between 55 and 65 g/mol. We can use this information to check different values for x and y to find suitable whole numbers for a hydrocarbon formula that lie within the given molar mass range. Also, as the molar ratio of hydrogen to carbon is \(y/x\), we can write: \(0.173 M = \frac{y}{x} \times 1\) Combining the two equations, we can find the values of x and y: \(M = 12x + y\) \(0.173(12x + y) = \frac{y}{x}\) We can find x = 5, y = 12 and M = 60 g/mol to be a solution that fulfills the given conditions. Now, since the molar mass of the hydrocarbon is 60 g/mol and there are 12 moles of hydrogen in one mole of hydrocarbon, we can calculate the moles of the sample as follows: Moles of the sample = moles of hydrogen / 12
04

Calculate the mass of the sample

To find the mass of the sample, we can multiply the moles of the hydrocarbon by its molar mass: Mass of the sample = moles of the sample × molar mass of hydrocarbon Putting these steps together, we can calculate the amount (moles) and mass of the hydrocarbon sample.

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