An iron ore sample contains \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) plus other impurities. A 752 g sample of impure iron ore is heated with excess carbon, producing \(453 \mathrm{~g}\) of pure iron by the following reaction: $$ \mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{C}(s) \longrightarrow 2 \mathrm{Fe}(s)+3 \mathrm{CO}(\mathrm{g}) $$ What is the mass percent of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) in the impure iron ore sample? Assume that \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) is the only source of iron and that the reaction is \(100 \%\) efficient.

Short Answer

Expert verified
The mass percent of \(\mathrm{Fe}_{2}\mathrm{O}_{3}\) in the impure iron ore sample is approximately 86.1%.

Step by step solution

01

Calculate the molar mass of Fe₂O₃ and Fe

Using the periodic table, we find the molar mass of these elements and compounds: - Molar mass of \(\mathrm{Fe}\): \(55.85 \frac{\text{g}}{\text{mol}}\) - Molar mass of \(\mathrm{O}\): \(16.00 \frac{\text{g}}{\text{mol}}\) So, the molar mass of \(\mathrm{Fe}_{2}\mathrm{O}_{3}\) = \(2\times55.85 + 3\times16.00 = 159.70 \frac{\text{g}}{\text{mol}}\) Molar masses: - \(\mathrm{Fe}_{2}\mathrm{O}_{3}\): \(159.70 \frac{\text{g}}{\text{mol}}\) - \(\mathrm{Fe}\): \(55.85 \frac{\text{g}}{\text{mol}}\)
02

Calculate the number of moles of Fe obtained

Using the mass of Fe and its molar mass, calculate the number of moles of Fe obtained: Number of moles of Fe = \(\frac{453 \;\text{g}}{55.85 \;\frac{\text{g}}{\text{mol}}} \approx 8.11\;\text{moles}\)
03

Calculate the number of moles of Fe₂O₃ reacting

Using the stoichiometry of the reaction, we know that: \(1 \;\text{mol}\;\mathrm{Fe}_{2} \mathrm{O}_{3} \longrightarrow 2\; \text{mol}\; \mathrm{Fe}\) So, the number of moles of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) reacting is: \(8.11 \;\text{moles}\; \mathrm{Fe} \times \frac{1\; \text{mol}\; \mathrm{Fe}_{2} \mathrm{O}_{3}}{2\; \text{moles}\; \mathrm{Fe}} \approx 4.055\;\text{moles}\)
04

Calculate the mass of Fe₂O₃ reacting

Now, using the number of moles of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) and its molar mass, we can calculate the mass of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\): Mass of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) = \(4.055\;\text{moles} \times 159.70\;\frac{\text{g}}{\text{mol}} \approx 647.64\;\text{g}\)
05

Calculate the mass percent of Fe₂O₃ in the impure iron ore sample

Finally, use the mass of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) and the mass of the impure iron ore sample to calculate the mass percent of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\): Mass percent of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) = \(\frac{647.64\; \text{g}}{752\; \text{g}} \times 100\% \approx 86.1\%\) The mass percent of \(\mathrm{Fe}_{2}\mathrm{O}_{3}\) in the impure iron ore sample is approximately 86.1%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Stoichiometry
Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in a chemical reaction. It allows chemists to calculate the amounts of substances needed or produced in a chemical reaction. For example, the balanced equation \[ \mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{C}(s) \longrightarrow 2 \mathrm{Fe}(s)+3 \mathrm{CO}(\mathrm{g}) \] indicates that one mole of iron(III) oxide reacts with three moles of carbon to produce two moles of iron and three moles of carbon monoxide. The coefficients in the balanced equation are essential for stoichiometric calculations as they represent the molar ratios of the substances involved.
Molar Mass
Molar mass is a fundamental concept in stoichiometry. It is the mass of one mole of a substance, usually expressed in grams per mole (g/mol), and it allows for the conversion between the mass of a substance and the number of moles. The molar mass is calculated by summing the atomic masses of all the atoms in a molecule. For instance, the molar mass of Fe₂O₃ is found by adding together the atomic masses of two iron atoms and three oxygen atoms, resulting in \[ 2 \times 55.85 + 3 \times 16.00 = 159.70 \frac{\text{g}}{\text{mol}} \]. Knowing the molar mass is crucial when determining the mass percent composition of a compound in a mixture, as seen in the iron ore sample problem.
Chemical Reaction Balancing
Balancing chemical equations is a vital skill in chemistry. It ensures that the law of conservation of mass is respected, meaning the number of atoms for each element is the same on the reactant side as on the product side of a chemical reaction. A balanced chemical equation provides the mole ratios necessary to perform stoichiometric calculations. The given reaction \[ \mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{C}(s) \longrightarrow 2 \mathrm{Fe}(s)+3 \mathrm{CO}(\mathrm{g}) \] is already balanced, with the reactants and products having a stoichiometric ratio of 1:3:2:3 respectively. These ratios are used to calculate how much reactant is needed to produce a certain amount of product or vice versa.
The Mole Concept
The mole concept is the cornerstone of stoichiometry, which provides a method for counting the number of atoms, molecules, or formula units in a sample of matter. One mole is defined as the amount of substance that contains as many entities as there are atoms in 12 grams of pure carbon-12, which is approximately \(6.022 \times 10^{23}\) entities (Avogadro's number). Using moles, we can relate the mass of a substance to the number of particles it contains. In the iron ore problem, by converting the mass of iron produced to moles, \[ \text{Number of moles of Fe} = \frac{453 \;\text{g}}{55.85 \;\frac{\text{g}}{\text{mol}}} \approx 8.11\;\text{moles} \], we can use the mole ratio from the balanced equation to find out how many moles of Fe₂O₃ were used, and then, by using the molar mass of Fe₂O₃, arrive at the mass of Fe₂O₃ in the sample.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The compound adrenaline contains \(56.79 \%\) C, \(6.56 \% \mathrm{H}\). \(28.37 \%\) O, and \(8.28 \%\) N by mass. What is the empirical formula for adrenaline?

Chloral hydrate \(\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}_{3} \mathrm{O}_{2}\right)\) is a drug formerly used as a sedative and hypnotic. It is the compound used to make "Mickey Finns" in detective stories. a. Calculate the molar mass of chloral hydrate. b. What amount (moles) of \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}_{3} \mathrm{O}_{2}\) molecules are in \(500.0 \mathrm{~g}\) chloral hydrate? c. What is the mass in grams of \(2.0 \times 10^{-2}\) mol chloral hydrate? d. What number of chlorine atoms are in \(5.0 \mathrm{~g}\) chloral hydrate? e. What mass of chloral hydrate would contain \(1.0 \mathrm{~g} \mathrm{Cl} ?\) \(\mathbf{f}\). What is the mass of exactly 500 molecules of chloral hydrate?

Determine the molecular formula of a compound that contains \(26.7 \% \mathrm{P}, 12.1 \% \mathrm{~N}\), and \(61.2 \% \mathrm{Cl}\), and has a molar mass of \(580 \mathrm{~g} / \mathrm{mol}\).

Many homes in rural America are heated by propane gas, a compound that contains only carbon and hydrogen. Complete combustion of a sample of propane produced \(2.641 \mathrm{~g}\) of carbon dioxide and \(1.442 \mathrm{~g}\) of water as the only products. Find the empirical formula of propane.

An element \(\mathrm{X}\) forms both a dichloride \(\left(\mathrm{XCl}_{2}\right)\) and a tetrachloride \(\left(\mathrm{XCl}_{4}\right) .\) Treatment of \(10.00 \mathrm{~g} \mathrm{XCl}_{2}\) with excess chlorine forms \(12.55 \mathrm{~g} \mathrm{XCl}_{4}\). Calculate the atomic mass of \(\mathrm{X}\), and identify \(\underline{X}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free