Consider the following generic reaction: $$ \mathrm{Y}_{2}+2 \mathrm{XY} \longrightarrow 2 \mathrm{XY}_{2} $$ In a limiting reactant problem, a certain quantity of each reactant is given and you are usually asked to calculate the mass of product formed. If \(10.0 \mathrm{~g}\) of \(\mathrm{Y}_{2}\) is reacted with \(10.0 \mathrm{~g}\) of \(\mathrm{XY}\), outline two methods you could use to determine which reactant is limiting (runs out first) and thus determines the mass of product formed. A method sometimes used to solve limiting reactant problems is to assume each reactant is limiting and then calculate the mass of product formed from each given quantity of reactant. How does this method work in determining which reactant is limiting?

Short Answer

Expert verified
There are two methods to determine the limiting reactant: Method 1: Determine the moles of each reactant and compare their mole ratios: 1. Moles of Y2 = Mass of Y2 / MY2 2. Moles of XY = Mass of XY / MXY 3. Compare the ratios (Y2 moles)/1 : (XY moles)/2. The reactant with the smaller amount in the comparison is the limiting reactant. Method 2: Calculate the theoretical product mass from each reactant: 1. Assume each reactant is limiting separately and calculate the mass of XY2 formed for each. 2. Compare the masses of XY2 formed in both scenarios: XY2 mass from Y2 : XY2 mass from XY. The scenario with a smaller amount of product is the correct one, and the limiting reactant determines the maximum amount of product that can be formed in a reaction. The method that assumes each reactant is limiting is effective in determining the limiting reactant, as it allows us to identify the limiting reactant based on the outcome of the product formation.

Step by step solution

01

Method 1 - Determine Moles of Reactants and Compare Mole Ratio

First, we have to determine the moles of each reactant using the given masses and their molar masses. Assume the molar mass of Y2 is MY2 and the molar mass of XY is MXY. Moles of Y2 = Mass of Y2 / MY2 Moles of XY = Mass of XY / MXY Next, we have to compare the mole ratios of Y2 and XY with the mole ratios given in the balanced chemical equation. For every mole of Y2, two moles of XY are required for the reaction. So, we can divide the moles of Y2 by one and the moles of XY by two and compare: (Y2 moles)/1 : (XY moles)/2 The reactant with the smaller amount in the mole ratio comparison is the limiting reactant.
02

Method 2 - Calculate Theoretical Product Mass From Each Reactant

In this method, we assume each reactant is limiting separately and calculate the mass of the product XY2 formed when each reactant runs out: a) Assuming Y2 is limiting, we calculate the mass of XY2 formed using stoichiometry: Moles of Y2 = Mass of Y2 / MY2 XY2 mass from Y2 = Moles of Y2 * (2 * MXY2) b) Assuming XY is limiting, we calculate the mass of XY2 formed: Moles of XY = Mass of XY / MXY XY2 mass from XY = Moles of XY * (MXY2) Compare the mass of the product formed in both scenarios: XY2 mass from Y2 : XY2 mass from XY The scenario that gives a smaller amount of product is the correct one, because the limiting reactant determines the maximum amount of product that can be formed in a reaction.
03

Effectiveness of the Assumed Limiting Reactant Method

The method discussed in Method 2 where each reactant is assumed to be limiting separately is effective in determining the limiting reactant because by calculating the mass of the product formed in each scenario, it compares which reactant produces a lower amount of the product. Since the limiting reactant determines the maximum amount of product that can be formed, this approach allows us to identify the limiting reactant based on the outcome of the product formation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel rocket motors. The reaction is $$ \mathrm{Fe}_{2} \mathrm{O}_{3}(s)+2 \mathrm{Al}(s) \longrightarrow 2 \mathrm{Fe}(l)+\mathrm{Al}_{2} \mathrm{O}_{3}(s) $$ What masses of iron(III) oxide and aluminum must be used to produce \(15.0 \mathrm{~g}\) iron? What is the maximum mass of aluminum oxide that could be produced?

A given sample of a xenon fluoride compound contains molecules of the type \(\mathrm{XeF}_{n}\), where \(n\) is some whole number. Given that \(9.03 \times 10^{20}\) molecules of \(\mathrm{XeF}_{n}\) weigh \(0.368 \mathrm{~g}\), determine the value for \(n\) in the formula.

DDT, an insecticide harmful to fish, birds, and humans, is produced by the following reaction: $$ 2 \mathrm{C}_{6} \mathrm{H}_{3} \mathrm{Cl}+\mathrm{C}_{2} \mathrm{HOCl}_{3} \longrightarrow \mathrm{C}_{14} \mathrm{H}_{4} \mathrm{Cl}_{5}+\mathrm{H}_{2} \mathrm{O} $$ \(\begin{array}{ll}\text { orobenzenc chloral } & \mathrm{D}\end{array}\) In a government lab, \(1142 \mathrm{~g}\) of chlorobenzene is reacted with \(485 \mathrm{~g}\) of chloral. a. What mass of DDT is formed? b. Which reactant is limiting? Which is in excess? c. What mass of the excess reactant is left over? d. If the actual yield of DDT is \(200.0 \mathrm{~g}\), what is the percent yield?

A 2.25-g sample of scandium metal is reacted with excess hydrochloric acid to produce \(0.1502 \mathrm{~g}\) hydrogen gas. What is the formula of the scandium chloride produced in the reaction?

Hydrogen cyanide is produced industrially from the reaction of gaseous ammonia, oxygen, and methane: $$ 2 \mathrm{NH}_{3}(g)+3 \mathrm{O}_{2}(g)+2 \mathrm{CH}_{4}(g) \longrightarrow 2 \mathrm{HCN}(g)+6 \mathrm{H}_{2} \mathrm{O}(g) $$ If \(5.00 \times 10^{3} \mathrm{~kg}\) each of \(\mathrm{NH}_{3}, \mathrm{O}_{2}\), and \(\mathrm{CH}_{4}\) are reacted, what mass of \(\mathrm{HCN}\) and of \(\mathrm{H}_{2} \mathrm{O}\) will be produced, assuming \(100 \%\) yield?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free