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Chapter 5: Problem 35

Freon-12 \(\left(\mathrm{CF}_{2} \mathrm{Cl}_{2}\right)\) is commonly used as the refrigerant in central home air conditioners. The system is initially charged to a pressure of \(4.8 \mathrm{~atm}\). Express this pressure in each of the following units \((1 \mathrm{~atm}=14.7 \mathrm{psi}) .\) a. \(\mathrm{mm} \mathrm{Hg}\) c. \(\mathrm{Pa}\) b. torr d. psi

Short Answer

Expert verified
The pressure of Freon-12 in the air conditioner system, given as 4.8 atm, can be converted to other units as follows: a. 3648 mm Hg b. 3648 torr c. 486360 Pa d. 70.56 psi

Step by step solution

01

Convert pressure from atm to mm Hg

To convert the pressure from atm to mm Hg, we will use the conversion factor: \(1 \mathrm{~atm} = 760 \mathrm{~mm} \mathrm{Hg}\) Now, we will multiply the given pressure (4.8 atm) by the conversion factor: \(4.8 \mathrm{~atm} \times \frac{760 \mathrm{~mm} \mathrm{Hg}}{1 \mathrm{~atm}} = 3648 \mathrm{~mm} \mathrm{Hg}\) Therefore, the pressure in mm Hg is 3648 mm Hg.
02

Convert pressure from atm to Pa

To convert the pressure from atm to Pa, we will use the conversion factor: \(1 \mathrm{~atm} = 101325 \mathrm{~Pa}\) Now, we will multiply the given pressure (4.8 atm) by the conversion factor: \(4.8 \mathrm{~atm} \times \frac{101325 \mathrm{~Pa}}{1 \mathrm{~atm}} = 486360 \mathrm{~Pa}\) Therefore, the pressure in Pa is 486360 Pa.
03

Convert pressure from atm to torr

Converting the pressure to torr is the same as converting it to mm Hg, as: \(1 \mathrm{~torr} = 1 \mathrm{~mm} \mathrm{Hg}\) From Step 1, we already know that the pressure in mm Hg is 3648 mm Hg. Thus, the pressure in torr is also 3648 torr.
04

Convert pressure from atm to psi

To convert the pressure from atm to psi, we will use the given conversion factor: \(1 \mathrm{~atm} = 14.7 \mathrm{~psi}\) Now, we will multiply the given pressure (4.8 atm) by the conversion factor: \(4.8 \mathrm{~atm} \times \frac{14.7 \mathrm{~psi}}{1 \mathrm{~atm}} = 70.56 \mathrm{~psi}\) Therefore, the pressure in psi is 70.56 psi. In conclusion, we have converted the given pressure of Freon-12 into the other units as follows: a. 3648 mm Hg b. 3648 torr c. 486360 Pa d. 70.56 psi

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Most popular questions from this chapter

From the values in Table \(5.3\) for the van der Waals constant \(a\) for the gases \(\mathrm{H}_{2}, \mathrm{CO}_{2}, \mathrm{~N}_{2}\), and \(\mathrm{CH}_{4}\), predict which of these gas molecules show the strongest intermolecular attractions.

A mixture of cyclopropane and oxygen is sometimes used as a general anesthetic. Consider a balloon filled with an anesthetic mixture of cyclopropane and oxygen at \(170 .\) torr and 570 . torr. respectively. Calculate the ratio of the moles \(\mathrm{O}_{2}\) to moles cyclopropane in this mixture.

In the "Méthode Champenoise," grape juice is fermented in a wine bottle to produce sparkling wine. The reaction is $$ \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(a q) \longrightarrow 2 \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{OH}(a q)+2 \mathrm{CO}_{2}(g) $$ Fermentation of \(750 . \mathrm{mL}\) grape juice (density \(=1.0 \mathrm{~g} / \mathrm{cm}^{3}\) ) is allowed to take place in a bottle with a total volume of \(825 \mathrm{~mL}\) until \(12 \%\) by volume is ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{OH}\right)\). Assuming that the \(\mathrm{CO}_{2}\) is insoluble in \(\mathrm{H}_{2} \mathrm{O}\) (actually, a wrong assumption), what would be the pressure of \(\mathrm{CO}_{2}\) inside the wine bottle at \(25^{\circ} \mathrm{C}\) ? (The density of ethanol is \(0.79 \mathrm{~g} / \mathrm{cm}^{3}\).)

A container is filled with an ideal gas to a pressure of \(40.0\) atm at \(0^{\circ} \mathrm{C}\). a. What will be the pressure in the container if it is heated to \(45^{\circ} \mathrm{C}\) ? b. At what temperature would the pressure be \(1.50 \times 10^{2}\) atm? c. At what temperature would the pressure be \(25.0 \mathrm{~atm} ?\)

A 20.0-L stainless steel container at \(25^{\circ} \mathrm{C}\) was charged with \(2.00\) atm of hydrogen gas and \(3.00 \mathrm{~atm}\) of oxygen gas. A spark ignited the mixture, producing water. What is the pressure in the tank at \(25^{\circ} \mathrm{C}\) ? If the same experiment were performed, but the temperature was \(125^{\circ} \mathrm{C}\) instead of \(25^{\circ} \mathrm{C}\), what would be the pressure in the tank?
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