It takes \(208.4 \mathrm{~kJ}\) of energy to remove 1 mole of electrons from an atom on the surface of rubidium metal. How much energy does it take to remove a single electron from an atom on the surface of solid rubidium? What is the maximum wavelength of light capable of doing this?

Short Answer

Expert verified
Energy per electron = \( \frac{208.4 \times 10^3 \text{J}}{6.022 \times 10^{23}} \) = \( 3.46 \times 10^{-19} \text{J} \) #tag_title#Step 2: Find the maximum wavelength of light capable of removing the electron#tag_content# Next, we will use Planck's equation to find the maximum wavelength of light capable of removing the electron: \(E = h \frac{c}{\lambda}\) where: - E is the energy per electron (\(3.46 \times 10^{-19} \text{J}\)) - h is the Planck's constant (\(6.63 \times 10^{-34} \text{Js}\)) - c is the speed of light (\(3.00 \times 10^8 \text{m/s}\)) - \(\lambda\) is the wavelength in meters. We need to find \(\lambda\): \(\lambda = \frac{hc}{E}\) Plugging in the values: \(\lambda = \frac{(6.63 \times 10^{-34} \text{Js})(3.00 \times 10^8 \text{m/s})}{3.46 \times 10^{-19} \text{J}}\) Now, let's calculate the maximum wavelength.

Step by step solution

01

Calculate the energy required to remove a single electron

First, we need to find the energy required to remove a single electron from an atom on the surface of solid rubidium. We are given the energy needed to remove 1 mole of electrons, which is \(208.4 \, \text{kJ/mol}\). As we know, one mole contains Avogadro's number of particles, which is approximately \(6.022 \times 10^{23}\) particles. We can use this number to find the energy required to remove one electron: Energy per electron = \( \frac{Energy\, per\, mole}{Avogadro's\, number} \) Energy per electron = \( \frac{208.4 \times 10^3 \text{J}}{6.022 \times 10^{23}} \) Now, let's calculate the energy per electron.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Required to Remove an Electron
Understanding the energy required to remove an electron from an atom is critical in the study of atomic structure and photoelectron spectroscopy. The process of removing an electron from an atom is known as ionization. The energy required to remove one electron is called the ionization energy.

The ionization energy can vary depending on the element and the state of the electron within the atom. In the case of rubidium metal, the exercise provided us with the energy needed to ionize a mole of electrons, which is 208.4 kJ/mol. This amount of energy refers to the collective energy needed to remove all electrons in a mole of rubidium atoms.

To find out how much energy it takes to remove just a single electron, we use Avogadro's number (\(6.022 \times 10^{23}\) particles/mol), which represents the number of particles in a mole. By dividing the provided energy per mole by Avogadro's number, we can pinpoint the energy required for a single electron. This meticulous calculation unravels the sheer magnitude of Avogadro's number and the tiny amount of energy to detach a single electron.
Avogadro's Number
Avogadro's number is a fundamental constant in chemistry often used when dealing with quantities in the microscopic world. It represents the number of units (atoms, molecules, ions, etc.) in one mole of a substance and is approximately equal to \(6.022 \times 10^{23}\) units/mol.

When working with atoms or molecules on the macroscopic scale, such as in chemical reactions or when measuring substances in a lab, dealing with individual particles is impractical. Avogadro's number allows scientists to translate between the microscopic world of atoms and the macroscopic world of grams and liters. It also plays a crucial role in calculations involving the energy per particle, as seen in our problem where it helps in converting the energy required for a mole of electrons to the energy required for a single electron.
Maximum Wavelength of Light
The maximum wavelength of light capable of ionizing an atom pertains to the threshold wavelength beyond which a photon has insufficient energy to eject an electron. This concept is rooted in the photoelectric effect, where electrons are emitted from materials when exposed to light.

According to quantum theory, light behaves both as a wave and as a particle. When considering its particle nature, light consists of photons, and each photon carries energy based on its frequency (\(E=h \times f\) where h is Planck's constant and f is the frequency). The relationship between the wavelength (\textlambda) and frequency (given that \textlambda \times f = c, where c is the speed of light) implies that photons of long wavelengths carry less energy.

The maximum wavelength of light that can ionize an atom correlates inversely with the minimum photon energy needed to remove an electron. To calculate this wavelength, we would use the energy per electron that we previously calculated and apply Planck's equation to solve for the wavelength. This relationship is pivotal in understanding the interaction between light and matter, especially in spectroscopy where it helps in determining the energy levels within an atom.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In defining the sizes of orbitals, why must we use an arbitrary value, such as \(90 \%\) of the probability of finding an electron in that region?

Give the maximum number of electrons in an atom that can have these quantum numbers: a. \(n=4\) b. \(n=5, m_{\ell}=+1\) c. \(n=5, m_{s}=+\frac{1}{2}\) d. \(n=3, \ell=2\) e. \(n=2, \ell=1\)

One bit of evidence that the quantum mechanical model is "correct" lies in the magnetic properties of matter. Atoms with unpaired electrons are attracted by magnetic fields and thus are said to exhibit paramagnetism. The degree to which this effect is observed is directly related to the number of unpaired electrons present in the atom. Consider the ground-state electron configurations for \(\mathrm{Li}, \mathrm{N}, \mathrm{Ni}, \mathrm{Te}, \mathrm{Ba}\), and \(\mathrm{Hg} .\) Which of these atoms would be expected to be paramagnetic, and how many unpaired electrons are present in each paramagnetic atom?

An ion having a \(4+\) charge and a mass of \(49.9\) amu has 2 electrons with principal quantum number \(n=1,8\) electrons with \(n=2\), and 10 electrons with \(n=3 .\) Supply as many of the properties for the ion as possible from the information given. (Hint: In forming ions for this species, the \(4 s\) electrons are lost before the \(3 d\) electrons.) a. the atomic number b. total number of \(s\) electrons c. total number of \(p\) electrons d. total number of \(d\) electrons e. the number of neutrons in the nucleus f. the ground-state electron configuration of the neutral atom

Calculate the velocities of electrons with de Broglie wavelengths of \(1.0 \times 10^{2} \mathrm{~nm}\) and \(1.0 \mathrm{~nm}\), respectively.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free