Without using Fig. \(8.3\), predict the order of increasing electronegativity in each of the following groups of elements. a. \(\mathrm{C}, \mathrm{N}, \mathrm{O}\) c. \(\mathrm{Si}, \mathrm{Ge}, \mathrm{Sn}\) b. \(\mathrm{S}, \mathrm{Se}, \mathrm{Cl}\) d. Tl, S, Ge

Short Answer

Expert verified
The order of increasing electronegativity for each group of elements is as follows: a. C < N < O b. S < Se < Cl c. Sn < Ge < Si d. Tl < Ge < S

Step by step solution

01

a. C, N, O

In this group, the elements are found in the same period (Period 2), and we know electronegativity increases from left to right across a period. So, the order of increasing electronegativity in this group is: C < N < O.
02

b. S, Se, Cl

In this group, the elements are found in the same period (Period 3). Following the trend of electronegativity increasing across a period from left to right, the order of increasing electronegativity is: S < Se < Cl.
03

c. Si, Ge, Sn

In this group, the elements are found in the same group, Group 14, but in different periods (Si in Period 3, Ge in Period 4, and Sn in Period 5). Electronegativity decreases as we move down a group, so the order of increasing electronegativity is: Sn < Ge < Si.
04

d. Tl, S, Ge

In this group, the elements are found in different groups and periods. To determine the order of electronegativity, we will compare their positions in the periodic table. Tl (Period 6, Group 13) is below Ge (Period 4, Group 14), so its electronegativity should be lower. S (Period 3, Group 16) is above and to the right of Ge, so it should have a higher electronegativity. Therefore, the order of increasing electronegativity is: Tl < Ge < S.

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