What modification to the molecular orbital model was made from the experimental evidence that \(\mathrm{B}_{2}\) is paramagnetic?

Short Answer

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The modification to the molecular orbital model that accounts for the experimentally observed paramagnetic nature of \(\mathrm{B}_{2}\) is the introduction of non-bonding molecular orbitals (NBMOs). These orbitals do not contribute to bond formation but contain unpaired electrons responsible for the magnetic properties of molecules like \(\mathrm{B}_{2}\).

Step by step solution

01

Understanding the molecular orbital model

Molecular orbital theory (MO theory) is a method for describing the electronic structure of molecules. It assumes that electrons in a molecule are not confined to individual atoms but are rather distributed over the entire molecule in "molecular orbitals." These orbitals are formed by the combination of atomic orbitals from the individual atoms involved in the molecule formation.
02

Limitations of the molecular orbital model

The molecular orbital model sometimes fails to predict the magnetic behavior of molecules accurately. Paramagnetism is a form of magnetism where certain materials are attracted to an externally applied magnetic field. Paramagnetic materials have unpaired electrons in their molecular orbitals, which gives rise to their magnetic properties. In the case of \(\mathrm{B}_{2}\), the molecular orbital model incorrectly predicts it to be diamagnetic (having only paired electrons), which contradicts experimental evidence showing that it is in fact paramagnetic.
03

Modification to the molecular orbital model

To account for the paramagnetic nature of \(\mathrm{B}_{2}\) and similar molecules, a modification to the molecular orbital model was made with the introduction of the concept of "non-bonding orbitals" or "non-bonding molecular orbitals" (NBMOs). These orbitals do not contribute to the formation of molecular bonds, but they do contain unpaired electrons that are responsible for the observed magnetic properties.
04

Application to \(\mathrm{B}_{2}\)

In the case of \(\mathrm{B}_{2}\), the molecular orbital model originally predicted that all the electrons would be paired in bonding and antibonding orbitals, leading to a diamagnetic molecule. By introducing non-bonding orbitals into the model, we now have a more accurate representation of the electronic structure of \(\mathrm{B}_{2}\). The unpaired electrons in these non-bonding orbitals account for the experimentally observed paramagnetism.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Paramagnetism
Paramagnetism is an intriguing concept when it comes to exploring the magnetic properties of molecules. Substances that exhibit paramagnetism are characterized by their ability to be attracted into an external magnetic field. But what makes paramagnetic materials stand out?

It's all about the electrons and their spin. In paramagnetic materials, there are unpaired electrons present in the molecular orbitals. Each of these unpaired electrons has a magnetic dipole moment because of its spin. In the absence of an external magnetic field, the spins of the unpaired electrons are arranged randomly, and thus the material doesn't show any net magnetic moment. However, when an external magnetic field is applied, these magnetic moments align with the field, causing an attraction.

One crucial factor here is that the strength of paramagnetism is proportional to the number of unpaired electrons a substance has. For a molecule like \(\mathrm{B}_{2}\), the presence of unpaired electrons in its molecular orbitals is evidence of its paramagnetic nature, which is confirmed by its attraction to a magnetic field in laboratory experiments. This is contrary to diamagnetism, where molecules have all paired electrons and are slightly repelled by a magnetic field because they have no net magnetic moments.
Molecular Orbitals
Molecular orbitals are fundamental in the understanding of a molecule's behavior, extending beyond a mere collection of atoms. They emerge from the principle that within molecules, electrons aren't confined to individual atoms; instead, these electrons can delocalize and span across the entire molecule.

The creation of molecular orbitals can be visualized by the combination or overlap of atomic orbitals from the atoms that come together to form a molecule. When atoms bond, their atomic orbitals mix to create these new orbitals that encompass the entire molecule and govern the distribution of electrons. Molecular orbitals are classified into two types: bonding molecular orbitals, which are lower in energy and lead to molecular stability, and antibonding molecular orbitals, which are higher in energy and can destabilize a molecule if populated.

The arrangement and occupancy of electrons within these molecular orbitals dictate the molecule's chemical and physical properties, such as its reactivity, color, and magnetic behavior. For example, the molecular orbital configuration explains why oxygen (\(O_2\)) is paramagnetic while nitrogen (\(N_2\)) is diamagnetic.
Bonding and Antibonding Orbitals
Diving deeper into the intricacies of molecular orbitals, we have to talk about the two pivotal kinds: bonding and antibonding orbitals. A bonding molecular orbital is formed when the wave functions of two atomic orbitals combine constructively, enhancing the electron density between the nuclei of the bonding atoms. This increased electron density leads to a stable bond formation, resulting in the molecule's structure being held together more firmly.

Bonding Orbitals:

Electrons in these orbitals effectively glue the atoms together and are located in regions that lead to an attractive interaction between the nuclei and the electron cloud.

Antibonding Orbitals:

In contrast, an antibonding molecular orbital arises when the wave functions combine destructively, which reduces the electron density between the atoms and can lead to repulsion. These orbitals have a node, a region of zero electron density, situated between the nuclei, resulting in instability if electrons are present.

The molecular stability is largely determined by the balance between the number of electrons occupying bonding and antibonding orbitals. Bonding orbitals are energetically favorable, while antibonding orbitals, if occupied, can counteract the stability provided by the bonding orbitals. In molecules like \(\mathrm{B}_{2}\), understanding the distribution of electrons among bonding, antibonding, and non-bonding orbitals is crucial to correct predictions of their magnetic properties and bond strength.

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Most popular questions from this chapter

Biacetyl and acetoin are added to margarine to make it taste more like butter. Complete the Lewis structures, predict values for all \(\mathrm{C}-\mathrm{C}-\mathrm{O}\) bond angles, and give the hybridization of the carbon atoms in these two compounds. Must the four carbon atoms and two oxygen atoms in biacetyl lie the same plane? How many \(\sigma\) bonds and how many \(\pi\) bonds are there in biacetyl and acetoin?

Compare and contrast bonding molecular orbitals with antibonding molecular orbitals.

Describe the bonding in \(\mathrm{NO}^{+}, \mathrm{NO}^{-}\), and NO using both the localized electron and molecular orbital models. Account for any discrepancies between the two models.

Carbon monoxide (CO) forms bonds to a variety of metals and metal ions. Its ability to bond to iron in hemoglobin is the reason that \(\mathrm{CO}\) is so toxic. The bond carbon monoxide forms to metals is through the carbon atom: \(\mathrm{M}-\mathrm{C} \equiv \mathrm{O}\) a. On the basis of electronegativities, would you expect the carbon atom or the oxygen atom to form bonds to metals? b. Assign formal charges to the atoms in CO. Which atom would you expect to bond to a metal on this basis? c. In the MO model, bonding MOs place more electron density near the more electronegative atom. (See the HF molecule in Figs. \(9.42\) and \(9.43 .\) Antibonding MOs place more electron density near the less electronegative atom in the diatomic molecule. Use the MO model to predict which atom of carbon monoxide should form bonds to metals.

A flask containing gaseous \(\mathrm{N}_{2}\) is irradiated with \(25-\mathrm{nm}\) light. a. Using the following information, indicate what species can form in the flask during irradiation. $$ \begin{aligned} \mathrm{N}_{2}(g) & \longrightarrow 2 \mathrm{~N}(g) & \Delta H &=941 \mathrm{~kJ} / \mathrm{mol} \\ \mathrm{N}_{2}(g) & \longrightarrow \mathrm{N}_{2}^{+}(g)+\mathrm{e}^{-} & \Delta H &=1501 \mathrm{~kJ} / \mathrm{mol} \\ \mathrm{N}(g) & \longrightarrow \mathrm{N}^{+}(g)+\mathrm{e}^{-} & \Delta H &=1402 \mathrm{~kJ} / \mathrm{mol} \end{aligned} $$ b. What range of wavelengths will produce atomic nitrogen in the flask but will not produce any ions? c. Explain why the first ionization energy of \(\mathrm{N}_{2}(1501 \mathrm{~kJ} / \mathrm{mol})\) is greater than the first ionization energy of atomic nitrogen \((1402 \mathrm{~kJ} / \mathrm{mol})\).

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