Cobalt fluoride crystallizes in a closest packed array of fluoride ions with the cobalt ions filling one-half of the octahedral holes. What is the formula of this compound?

Short Answer

Expert verified
The formula of the compound formed between cobalt and fluoride ions in a closest packed array, with cobalt ions occupying half of the octahedral holes, is CoF₂.

Step by step solution

01

Understand octahedral holes in a close-packed structure

In a close-packed array, there are two types of voids (empty spaces) between adjacent atoms or ions: tetrahedral and octahedral holes. Octahedral holes are larger voids surrounded by six ions in an octahedral arrangement.
02

Determine the number of octahedral holes in a closest-packed structure

In a close-packed array, the number of octahedral holes is equal to the number of ions in the packing. For instance, if there are 'n' fluoride ions forming the close-packed array, there will be 'n' octahedral holes.
03

Calculate the number of cobalt ions in the compound

The problem states that half of the octahedral holes are filled with cobalt ions. Therefore, the number of cobalt ions in the structure will be half the number of octahedral holes. If there are 'n' fluoride ions in the packing, there will be n/2 cobalt ions.
04

Find the formula of the compound

Now that we know the ratio of fluoride and cobalt ions in the structure, we can write the empirical formula of the compound. To do this, we will denote the number of cobalt ions as 'Co' and the number of fluoride ions as 'F': Co : F = (n/2) : n To find the simplest whole number ratio, we can multiply both sides by 2: 2Co : 2F = n : 2n So, the formula of the compound is CoF₂.

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