Chapter 14: Problem 15
Can the \(\mathrm{pH}\) of a solution be negative? Explain.
Short Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 14: Problem 15
Can the \(\mathrm{pH}\) of a solution be negative? Explain.
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeA sample containing \(0.0500\) mole of \(\mathrm{Fe}_{2}\left(\mathrm{SO}_{4}\right)_{3}\) is dissolved in enough water to make \(1.00 \mathrm{~L}\) of solution. This solution contains hydrated \(\mathrm{SO}_{4}{ }^{2-}\) and \(\mathrm{Fe}^{3+}\) ions. The latter behaves as an acid: $$\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}(a q) \rightleftharpoons \mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{OH}^{2+}(a q)+\mathrm{H}^{+}(a q)$$ a. Calculate the expected osmotic pressure of this solution at \(25^{\circ} \mathrm{C}\) if the above dissociation is negligible. b. The actual osmotic pressure of the solution is \(6.73\) atm at \(25^{\circ} \mathrm{C}\). Calculate \(K_{\mathrm{a}}\) for the dissociation reaction of \(\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}{ }^{3+}\). (To do this calculation, you must assume that none of the ions go through the semipermeable membrane. Actually, this is not a great assumption for the tiny \(\mathrm{H}^{+}\) ion.)
A \(0.25-\mathrm{g}\) sample of lime \((\mathrm{CaO})\) is dissolved in enough water to make \(1500 \mathrm{~mL}\) of solution. Calculate the \(\mathrm{pH}\) of the solution.
Making use of the assumptions we ordinarily make in calculating the \(\mathrm{pH}\) of an aqueous solution of a weak acid, calculate the \(\mathrm{pH}\) of a \(1.0 \times 10^{-6}-M\) solution of hypobromous acid (HBrO, \(K_{\mathrm{a}}=2 \times 10^{-9}\) ). What is wrong with your answer? Why is it wrong? Without trying to solve the problem, explain what has to be included to solve the problem correctly.
Calculate the \(\mathrm{pH}\) of each of the following solutions. a. \(0.10 \mathrm{MCH}_{3} \mathrm{NH}_{3} \mathrm{Cl}\) b. \(0.050 M \mathrm{NaCN}\)
Calculate the percent dissociation for a \(0.22-M\) solution of chlorous acid \(\left(\mathrm{HClO}_{2}, K_{\mathrm{a}}=1.2 \times 10^{-2}\right)\)
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