Chapter 14: Problem 67
For propanoic acid \(\left(\mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{2}, K_{\mathrm{a}}=1.3 \times 10^{-5}\right)\), determine the concentration of all species present, the \(\mathrm{pH}\), and the percent dissociation of a \(0.100-M\) solution.
Short Answer
Expert verified
The concentrations of all species in the 0.100 M propanoic acid solution at equilibrium are 0.09886 M for propanoic acid \((HC_3H_5O_2)\), 1.14 × 10⁻³ M for hydronium ions \((H^+)\), and 1.14 × 10⁻³ M for propanoate ions \((C_3H_5O_2^-)\). The pH of the solution is 2.94, and the percent dissociation of propanoic acid is 1.14%.
Step by step solution
01
Write the dissociation reaction of propanoic acid
The dissociation of propanoic acid can be represented by the following balanced equation:
\(HC_3H_5O_2 \longleftrightarrow H^+ + C_3H_5O_2^-\)
02
Define the initial and equilibrium concentrations of the species
Let's express the initial and equilibrium concentrations of the species in the reaction in terms of x:
HC3H5O2(Titrant): 0.100-x M
H+: x M
C3H5O2(Anion): x M
03
Write the Ka expression for propanoic acid
We can express the Ka of the acid as follows:
\(K_a = \dfrac{[H^+][C_3H_5O_2^-]}{[HC_3H_5O_2]}\)
Plug in the equilibrium concentrations obtained in step 2 into the Ka expression:
\(1.3 \times 10^{-5} = \dfrac{x \cdot x}{0.100-x}\)
04
Solve the equation for x
Since Ka is a very small value, we can assume that x is very small compared to the initial concentration of HC3H5O2. So, we can approximate the equation by ignoring x in the denominator (0.100-x ≈ 0.100). Now we have:
\(1.3 \times 10^{-5} = \dfrac{x^2}{0.100}\)
Now, solve for x:
\(x^2 = 1.3 \times 10^{-5} \times 0.100\)
\(x = \sqrt{1.3 \times 10^{-6}} = 1.14 \times 10^{-3}\)
Thus, x = 1.14 × 10⁻³ M, where x is the concentration of dissociated propanoic acid at equilibrium, which is equal to the concentration of H+ and C3H5O2- ions.
05
Calculate the equilibrium concentrations of all species
Equilibrium concentrations are as follows:
HC3H5O2: 0.100 - 1.14 × 10⁻³ = 0.09886 M
H+: 1.14 × 10⁻³ M
C3H5O2-: 1.14 × 10⁻³ M
06
Calculate the pH of the solution
pH is defined as the negative logarithm of the hydronium ion concentration (H+):
pH = -log[H+]
pH = -log(1.14 × 10⁻³)
pH ≈ 2.94
07
Calculate the percent dissociation of propanoic acid
Percent dissociation is the ratio of the dissociated acid concentration (x) to the initial acid concentration, multiplied by 100:
Percent dissociation = \(\dfrac{1.14 \times 10^{-3}}{0.100} \times 100\)
Percent dissociation ≈ 1.14%
In conclusion, the concentrations of all species present in the solution are 0.09886 M for propanoic acid, 1.14 × 10⁻³ M for both H+ and C3H5O2-, with a pH of 2.94 and a percent dissociation of 1.14%.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Acid Dissociation Constant (Ka)
The acid dissociation constant (Ka) is a quantitative measure of an acid's strength. More specifically, it represents the equilibrium constant for the dissociation of an acid into its conjugate base and a proton (H+). In the case of propanoic acid \( HC_3H_5O_2 \) with a Ka value of \(1.3 \times 10^{-5}\), we understand that it is a weak acid as it does not dissociate completely in solution.
For the dissociation reaction \( HC_3H_5O_2 \longleftrightarrow H^+ + C_3H_5O_2^- \), Ka is defined by the equation \( K_a = \frac{[H^+][C_3H_5O_2^-]}{[HC_3H_5O_2]} \), where the concentrations are those at equilibrium. To find the degree of dissociation, we solve for \( x \) where \(x \) represents the concentration of dissociated ions at equilibrium. Intuitively, a stronger acid would have a higher Ka value, signaling higher dissociation, whereas a weaker acid like propanoic has a lower Ka, implying less dissociation.
For the dissociation reaction \( HC_3H_5O_2 \longleftrightarrow H^+ + C_3H_5O_2^- \), Ka is defined by the equation \( K_a = \frac{[H^+][C_3H_5O_2^-]}{[HC_3H_5O_2]} \), where the concentrations are those at equilibrium. To find the degree of dissociation, we solve for \( x \) where \(x \) represents the concentration of dissociated ions at equilibrium. Intuitively, a stronger acid would have a higher Ka value, signaling higher dissociation, whereas a weaker acid like propanoic has a lower Ka, implying less dissociation.
pH Calculation
The pH of a solution is a logarithmic measure of the concentration of hydrogen ions (H+) present. The formula for pH is \( pH = -\log[H+] \). Through this calculation, we can determine the acidity or basicity of the solution. A lower pH value indicates a more acidic solution, while a higher pH indicates a more basic or alkaline solution.
In the context of propanoic acid's dissociation, the concentration of H+ ions at equilibrium, found as \( x \) in the earlier steps, can be plugged into the pH formula. This allows us to conclude the pH of the propanoic acid solution to be approximately 2.94, reflecting its acidic nature. Understanding pH is crucial for predicting the behavior of substances in different chemical environments and is a fundamental aspect of chemistry.
In the context of propanoic acid's dissociation, the concentration of H+ ions at equilibrium, found as \( x \) in the earlier steps, can be plugged into the pH formula. This allows us to conclude the pH of the propanoic acid solution to be approximately 2.94, reflecting its acidic nature. Understanding pH is crucial for predicting the behavior of substances in different chemical environments and is a fundamental aspect of chemistry.
Percent Dissociation
Percent dissociation offers insight into the extent of an acid's ionization in a given solution. It is calculated by the formula: \( \text{Percent dissociation} = \frac{\text{Concentration of dissociated acid}}{\text{Initial concentration of acid}} \times 100% \). This percentage reveals the portion of the original acid that has dissociated into ions.
For a 0.100 M solution of propanoic acid with an \(x\) value representing the dissociated amount of \(1.14 \times 10^{-3}M\), the percent dissociation can be calculated. The approximate percent dissociation for propanoic acid in this case is 1.14%, indicating a relatively low level of dissociation, as one would expect from a weak acid.
For a 0.100 M solution of propanoic acid with an \(x\) value representing the dissociated amount of \(1.14 \times 10^{-3}M\), the percent dissociation can be calculated. The approximate percent dissociation for propanoic acid in this case is 1.14%, indicating a relatively low level of dissociation, as one would expect from a weak acid.
Equilibrium Concentration
Equilibrium concentration refers to the concentration of reactants and products in a reaction at the state of equilibrium. This state occurs when the rate of the forward reaction equals the rate of the reverse reaction. For propanoic acid, the dissociation reaction achieves equilibrium when the concentration of un-dissociated acid, the hydrogen ions, and the conjugate base no longer change with time.
By setting up an ICE (initial, change, equilibrium) table and solving for \( x \) as done in our example, we derived the equilibrium concentrations for HC3H5O2, H+, and C3H5O2-. Understanding and calculating these values is important as they dictate the behavior and properties of the solution, including its reactivity, pH, and buffer capacity.
By setting up an ICE (initial, change, equilibrium) table and solving for \( x \) as done in our example, we derived the equilibrium concentrations for HC3H5O2, H+, and C3H5O2-. Understanding and calculating these values is important as they dictate the behavior and properties of the solution, including its reactivity, pH, and buffer capacity.