Write the reaction and the corresponding \(K_{\mathrm{b}}\) equilibrium expression for each of the following substances acting as bases in water. a. \(\mathrm{NH}_{3}\) b. \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{~N}\)

Short Answer

Expert verified
a. The reaction of \(\mathrm{NH}_3\) as a base in water and its corresponding \(K_\mathrm{b}\) expression are: \[ \mathrm{NH}_{3\,(aq)} + \mathrm{H}_{2 \mathrm{O}_{(l)}} \rightleftharpoons \mathrm{NH}_{4}^{+}_{(aq)} + \mathrm{OH}^{-}_{(aq)} \] \[K_b = \frac{[\mathrm{NH}_{4}^{+}][\mathrm{OH}^{-}]}{[\mathrm{NH}_3]}\] b. The reaction of \(\mathrm{C}_{5}\mathrm{H}_{5}\mathrm{N}\) as a base in water and its corresponding \(K_\mathrm{b}\) expression are: \[ \mathrm{C}_{5}\mathrm{H}_{5}\mathrm{N}_{(aq)} + \mathrm{H}_{2}\mathrm{O}_{(l)} \rightleftharpoons \mathrm{C}_{5}\mathrm{H}_{5}\mathrm{NH}^{+}_{(aq)} + \mathrm{OH}^{-}_{(aq)} \] \[K_b = \frac{[\mathrm{C}_{5}\mathrm{H}_{5}\mathrm{NH}^{+}][\mathrm{OH}^{-}]}{[\mathrm{C}_{5}\mathrm{H}_{5}\mathrm{N}]}\]

Step by step solution

01

Write the chemical reaction of NH3 with water

NH3 acts as a base and accepts a proton from water, forming the ammonium ion (\(\mathrm{NH}_{4}^{+}\)) and hydroxide ion (\(\mathrm{OH}^{-}\)). \[ \mathrm{NH}_{3\,(aq)} + \mathrm{H}_{2 \mathrm{O}_{(l)}} \rightleftharpoons \mathrm{NH}_{4}^{+}_{(aq)} + \mathrm{OH}^{-}_{(aq)} \]
02

Write the Kb equilibrium expression for NH3

The \(K_{\mathrm{b}}\) equilibrium expression for this reaction is: \[K_b = \frac{[\mathrm{NH}_{4}^{+}][\mathrm{OH}^{-}]}{[\mathrm{NH}_3]}\] #b. C5H5N acting as a base in water#
03

Write the chemical reaction of C5H5N with water

\(\mathrm{C}_{5}\mathrm{H}_{5}\mathrm{N}\) (pyridine) acts as a base and accepts a proton from water, forming the protonated pyridine cation (\(\mathrm{C}_{5}\mathrm{H}_{5}\mathrm{N}\mathrm{H}^{+}\)) and a hydroxide ion (\(\mathrm{OH}^{-}\)). \[ \mathrm{C}_{5}\mathrm{H}_{5}\mathrm{N}_{(aq)} + \mathrm{H}_{2}\mathrm{O}_{(l)} \rightleftharpoons \mathrm{C}_{5}\mathrm{H}_{5}\mathrm{NH}^{+}_{(aq)} + \mathrm{OH}^{-}_{(aq)} \]
04

Write the Kb equilibrium expression for C5H5N

The \(K_{\mathrm{b}}\) equilibrium expression for this reaction is: \[K_b = \frac{[\mathrm{C}_{5}\mathrm{H}_{5}\mathrm{NH}^{+}][\mathrm{OH}^{-}]}{[\mathrm{C}_{5}\mathrm{H}_{5}\mathrm{N}]}\]

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Most popular questions from this chapter

Rank the following \(0.10 M\) solutions in order of increasing \(\mathrm{pH}\). a. HI, HF, NaF, NaI b. \(\mathrm{NH}_{4} \mathrm{Br}, \mathrm{HBr}, \mathrm{KBr}, \mathrm{NH}_{3}\) c. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{NO}_{3}, \mathrm{NaNO}_{3}, \mathrm{NaOH}, \mathrm{HOC}_{6} \mathrm{H}_{5}, \mathrm{KOC}_{6} \mathrm{H}_{5}\), \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}, \mathrm{HNO}_{3}\)

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What mass of \(\mathrm{KOH}\) is necessary to prepare \(800.0 \mathrm{~mL}\) of a solution having a \(\mathrm{pH}=11.56\) ?

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