Chapter 16: Problem 86
The equilibrium constant for the following reaction is }\\\ 1.0 \times 10^{23}\\\ \mathrm{Cr}^{3+}(a q)+\mathrm{H}_{2} \mathrm{EDTA}^{2-}(a q) \rightleftharpoons \operatorname{CrEDTA}^{-}(a q)+2 \mathrm{H}^{+}(a q) \end{array} $$ EDTA is used as a complexing agent in chemical analysis. Solutions of EDTA, usually containing the disodium salt \(\mathrm{Na}_{2} \mathrm{H}_{2} \mathrm{EDTA}\), are used to treat heavy metal poisoning. Calculate \(\left[\mathrm{Cr}^{3+}\right]\) at equilibrium in a solution originally \(0.0010 \mathrm{M}\) in \(\mathrm{Cr}^{3+}\) and \(0.050 \mathrm{M}\) in \(\mathrm{H}_{2} \mathrm{EDTA}^{2-}\) and buffered at \(\mathrm{pH}=6.00 .\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.