a. Using the free energy profile for a simple one-step reaction, show that at
equilibrium \(K=k_{\mathrm{f}} / k_{\mathrm{r}}\), where \(k_{\mathrm{f}}\) and
\(k_{\mathrm{r}}\) are the rate constants for the forward and reverse reactions.
Hint: Use the relationship \(\Delta G^{\circ}=-R T \ln (K)\) and represent
\(k_{\mathrm{f}}\) and \(k_{\mathrm{r}}\) using the Arrhenius equation \(\left(k=A
e^{-E_{\mathrm{a}} / R T}\right) .\)
b. Why is the following statement false? "A catalyst can increase the rate of
a forward reaction but not the rate of
the reverse reaction."