Electrolysis of an alkaline earth metal chloride using a current of \(5.00 \mathrm{~A}\) for \(748 \mathrm{~s}\) deposits \(0.471 \mathrm{~g}\) of metal at the cathode. What is the identity of the alkaline earth metal chloride?

Short Answer

Expert verified
The identity of the alkaline earth metal chloride is Magnesium Chloride (MgCl2), with a molar mass of 24.3 g/mol.

Step by step solution

01

Calculate the moles of metal deposited

Given the mass of metal deposited, we can calculate the number of moles of metal deposited using the equation: Moles of metal = mass of metal / molar mass of metal We have the mass of the metal deposited, but we don't have the molar mass yet. We will use Faraday's laws of electrolysis to find the molar mass later.
02

Calculate the charge passed during electrolysis

We will calculate the charge passed during the electrolysis process using the equation: Charge passed (Q) = Current (I) x Time (t) Given that the current, I = 5.00 A and the time, t = 748 s, we can substitute these values and calculate the charge passed: Q = \(5.00 \mathrm{~A} \times 748 \mathrm{~s}\) Q = \(3740 \mathrm{~C}\)
03

Calculate the number of Faraday's

In order to find the molar mass of the metal, we first need to calculate the number of moles of electrons or Faraday's (F) passed during the electrolysis process. Knowing that one Faraday is equal to the charge on one mole of electrons, with a value of approximately 96485 C/mol, we can determine the number of moles of electrons by dividing the charge passed by the Faraday constant: Moles of electrons = Charge passed (Q) / Faraday constant (F) Moles of electrons = \(3740 \mathrm{~C}\) / \(96485 \mathrm{~C/mol}\) Moles of electrons = \(0.03873 \mathrm{~mol}\)
04

Determine the molar mass of the metal

Now that we have the number of moles of electrons, we can determine the molar mass of the metal using the relationship: Moles of metal = Moles of electrons / Ratio of electrons to metal ions (n) We know that the alkaline earth metals have a +2 charge (i.e., they need two moles of electrons to form one mole of metal ions). So, the ratio of electrons to metal ions, n = 2. We can now rearrange the relationship and solve for the molar mass of the metal: Molar mass of metal = mass of metal / (moles of electrons / n) Using the given mass of metal deposited, 0.471 g, and the calculated moles of electrons, 0.03873 mol, we find the molar mass: Molar mass of metal = \(0.471 \mathrm{~g}\) / (\(0.03873 \mathrm{~mol}\) / 2) Molar mass of metal = \(24.3 \mathrm{~g/mol}\)
05

Identify the alkaline earth metal chloride

Now that we have the molar mass of the metal, we can compare it to the known molar masses of alkaline earth metals to determine which metal is present in the chloride: 1. Beryllium (Be): 9.01 g/mol 2. Magnesium (Mg): 24.3 g/mol 3. Calcium (Ca): 40.1 g/mol 4. Strontium (Sr): 87.6 g/mol 5. Barium (Ba): 137.3 g/mol 6. Radium (Ra): 226.0 g/mol The molar mass we calculated (24.3 g/mol) is closest to the molar mass of Magnesium (Mg), so the identity of the alkaline earth metal chloride is Magnesium Chloride (MgCl2).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Laws of Electrolysis
Understanding Faraday’s laws of electrolysis is paramount when studying the process of extracting elements through electrochemical means. These foundational principles of electrolysis, attributed to scientist Michael Faraday, describe the quantitative relationship between the amount of substance liberated at an electrode and the amount of electrical charge passed through the electrolyte.

Faraday's first law states that the mass of a substance altered at an electrode during electrolysis is directly proportional to the quantity of electricity that passes through the electrolyte. Mathematically, we can represent this law as \( m = Q * (1/F) * (M/n) \) where \( m \) is the mass of the substance (in grams), \( Q \) is the total electric charge passed through the solution (in coulombs), \( F \) is Faraday's constant (approximately 96485 C/mol), \( M \) is the molar mass of the substance, and \( n \) is the number of moles of electrons required to produce one mole of the substance.

Faraday's second law further explicates that when the same quantity of electricity passes through several electrolytes, the mass of substances produced at the electrodes is proportional to their chemical equivalent weights. This principle is particularly useful in the stoichiometric calculation of electrolytic reactions, aiding in the determination of how many grams of a substance will be deposited based on a known current and time.
Molar Mass Calculation
The molar mass calculation is a vital skill in chemistry, particularly in electrolysis, where it helps identify substances involved in electrochemical reactions. It is the mass of 1 mole of a substance, usually expressed in grams per mole (g/mol).

In the context of electrolysis, knowing the molar mass allows us to link the mass of a substance deposited or liberated at an electrode to the quantity of electricity used. When an exercise involves the deposition of an alkaline earth metal through electrolysis, as in our example, the molar mass not only confirms the identity of the metal but also provides insights into the stoichiometry of the reaction taking place at the electrode.
Stoichiometry
Stoichiometry plays a crucial role in chemical reactions, including those involved in electrolysis. It is the part of chemistry that deals with the calculation of the reactants and products in a chemical reaction. For electrolysis, stoichiometry provides a means to establish the relationship between the electric charge used and the amount of substance deposited.

In our example problem, stoichiometry is used to determine the molar mass of the unknown metal. Given the known charge and Faraday's constant, we can calculate the moles of electrons that were required to deposit the metal. Knowing the charge of alkaline earth metals (which is generally +2), we can then apply stoichiometric calculations to relate the moles of electrons to the moles of metal deposited and ultimately identify the metal based on its molar mass.

This connection between stoichiometry and the fundamental laws of electrolysis illustrates the comprehensive approach required to solve complex chemistry problems. It reinforces the concept that chemical understanding is built upon the integration of multiple principles.

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Most popular questions from this chapter

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