Almost all metals in nature are found as ionic compounds in ores instead of being in the pure state. Why? What must be done to a sample of ore to obtain a metal substance that has desirable properties?

Short Answer

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Metals in nature are found as ionic compounds in ores because they tend to lose electrons and form positively charged ions, combining with non-metals which gain electrons to create negatively charged ions. The formation of these ionic compounds makes ores valuable for metal extraction. To obtain a metal with desirable properties from an ore, a process called metallurgy is performed, involving concentration of the ore, reduction of the metal from its compound state, and refining to remove impurities. The specific methods used depend on the type of metal, its reactivity, and the ore itself.

Step by step solution

01

Understanding Ionic Compounds and Ores

Metals are found as ionic compounds in ores because they have a strong tendency to lose electrons and form positively charged ions (cations). Non-metal elements, on the other hand, have a strong tendency to gain electrons and form negatively charged ions (anions). When metals and non-metals combine, they form ionic compounds due to the transfer of electrons from metals to non-metals. An ore is a naturally occurring solid material from which a metal or valuable mineral can be extracted profitably. Ores contain minerals, which are composed of ionic compounds.
02

Extracting Metals from Ores

To obtain a metal substance with desirable properties from an ore, a process called metallurgy is performed. Metallurgy involves multiple steps, such as: 1. Concentration of the ore: This process aims to remove impurities and gangue (unwanted minerals) from the ore. Methods such as hydraulic washing, froth flotation, and magnetic separation can be used to concentrate the ore. 2. Reduction of the metal: After the concentration, the metal must be reduced from its compound state (like an oxide) to its elemental state. The reduction process can be achieved through chemical reactions or electrolysis. For example, in the case of iron, its oxide is reduced using carbon as a reducing agent. 3. Refining of the metal: After reduction, the metal might still contain some impurities. To obtain a pure sample of metal, the impurities must be removed. Refining methods include liquation, distillation, electrolytic refining, and zone refining. The specific methods used in the extraction process depend on the type of metal, its reactivity, and the type of ore. By undergoing this process, a metal can be extracted from its ore, and its desirable properties can be obtained.

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Most popular questions from this chapter

The following statements discuss some coordination compounds. For each coordination compound, give the complex ion and the counterions, the electron configuration of the transition metal, and the geometry of the complex ion. a. \(\mathrm{CoCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) is a compound used in novelty devices that predict rain. b. During the developing process of black-and-white film, silver bromide is removed from photographic film by the fixer. The major component of the fixer is sodium thiosulfate. The equation for the reaction is: \(\begin{aligned} \mathrm{AgBr}(s)+2 \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}(a q) & \longrightarrow \\\& \quad\quad \mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}\right](a q)+\mathrm{NaBr}(a q) \end{aligned}\) c. In the production of printed circuit boards for the electronics industry, a thin layer of copper is laminated onto an insulating plastic board. Next, a circuit pattern made of a chemically resistant polymer is printed on the board. The unwanted copper is removed by chemical etching, and the protective polymer is finally removed by solvents. One etching reaction is: $$\mathrm{Cu}\left(\mathrm{NH}_{3}\right){ }_{4} \mathrm{Cl}_{2}(a q)+4 \mathrm{NH}_{3}(a q)+\mathrm{Cu}(s) \longrightarrow \\\ \mathrm{Cu}\left(\mathrm{NH}_{3}\right){ }_{4} \mathrm{Cl}(a q)$$

Name the following coordination compounds. a. \(\mathrm{Na}_{4}\left[\mathrm{Ni}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]\) b. \(\mathrm{K}_{2}\left[\mathrm{CoCl}_{4}\right]\) c. \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\) d. \(\left[\mathrm{Co}(\mathrm{en})_{2}(\mathrm{SCN}) \mathrm{Cl}\right] \mathrm{Cl}\)

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The following table indicates the number of unpaired electrons in the crystal field diagrams for some complexes. Complete the table by classifying each species as weak field, strong field, or insufficient information. $$ \begin{array}{|lcc|} \hline \text { Species } & \begin{array}{l} \text { Unpaired } \\ \text { Electrons } \end{array} & \text { Classification } \\ \hline \mathrm{Fe}(\mathrm{CNS})_{6}{ }^{4-} & 0 & \\ \mathrm{CoCl}_{4}^{2-} & 3 & \\ \mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}{ }^{3+} & 5 & \\ \mathrm{Fe}(\mathrm{CN})_{6}{ }^{4-} & 0 & \\ \hline \end{array} $$

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