Draw geometrical isomers of each of the following complex ions. a. \(\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}^{-}\) b. \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{I}_{2}{ }^{2+}\) c. \(\mathrm{Ir}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\) d. \(\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2} \mathrm{I}_{2}^{+}\)

Short Answer

Expert verified
The geometrical isomers for each complex ion are as follows: a. [Co(C2O4)2(H2O)2]^-: - cis isomer: the two water molecules are adjacent to each other - trans isomer: the two water molecules are opposite each other b. [Pt(NH3)4I2]^{2+}: - cis isomer: the two iodide ions are adjacent to each other - trans isomer: the two iodide ions are opposite each other c. [Ir(NH3)3Cl3]: - facial (fac) isomer: the three ammonia molecules are located in a facial arrangement - meridional (mer) isomer: the three ammonia molecules are located in a meridional arrangement d. [Cr(en)(NH3)2I2]^{+}: - cis isomer: the two ammonia molecules are adjacent to each other - trans isomer: the two ammonia molecules are opposite each other

Step by step solution

01

1. Identify the central metal ion and ligands in each complex ion

For each complex ion, identify the central metal ion and the ligands surrounding it. a. \(\mathrm{Co}\left(\mathrm{C}_{2}\mathrm{O}_{4}\right)_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}^{-}\) -> Central metal: Co, ligands: 2 oxalate ions (C2O4) and 2 water molecules (H2O) b. \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{I}_{2}{ }^{2+}\) -> Central metal: Pt, ligands: 4 ammonia molecules (NH3) and 2 iodide ions (I) c. \(\mathrm{Ir}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\) -> Central metal: Ir, ligands: 3 ammonia molecules (NH3) and 3 chloride ions (Cl) d. \(\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2}\mathrm{I}_{2}^{+}\) -> Central metal: Cr, ligands: 1 ethylenediamine (en) which acts as a bidentate ligand, 2 ammonia molecules (NH3), and 2 iodide ions (I)
02

2. Determine the coordination number and possible geometries

Based on the number of ligands, determine the coordination number (the number of ligand donor atoms coordinated to the metal ion) and the possible geometries for each complex ion: a. Co: coordination number 6 (octahedral) b. Pt: coordination number 6 (octahedral) c. Ir: coordination number 6 (octahedral) d. Cr: coordination number 6 (octahedral) Since all the complex ions have a coordination number of 6 and are octahedral, we need to draw the geometrical isomers for each complex ion considering the octahedral geometry.
03

3. Draw the geometrical isomers

For each complex ion, draw the geometrical isomers: a. [Co(C2O4)2(H2O)2]^-: - cis isomer: the two water molecules are adjacent to each other - trans isomer: the two water molecules are opposite each other b. [Pt(NH3)4I2]^{2+}: - cis isomer: the two iodide ions are adjacent to each other - trans isomer: the two iodide ions are opposite each other c. [Ir(NH3)3Cl3]: - facial (fac) isomer: the three ammonia molecules are located in a facial arrangement - meridional (mer) isomer: the three ammonia molecules are located in a meridional arrangement d. [Cr(en)(NH3)2I2]^{+}: - cis isomer: the two ammonia molecules are adjacent to each other - trans isomer: the two ammonia molecules are opposite each other

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordination Compounds
Coordination compounds, also known as coordination complexes, play a pivotal role in the realm of chemistry. They consist of a central metal atom or ion bonded to a surrounding array of molecules or anions, known as ligands. These ligands possess 'donor atoms' with lone pairs of electrons, and they form coordinate bonds with the metal atom or ion by donating these pairs.

The formation of these compounds is fascinating because it includes the interaction between the orbitals of the metal and the ligands, creating a unique arrangement that can greatly affect the properties of the compound. One interesting application is the use of coordination compounds in various industries, including pharmaceuticals and materials science.
Coordination Number
The coordination number is a term used to describe the number of points at which ligands are attached to the central atom or ion in a coordination compound. It is a critical factor in determining the geometry of the complex. For example, with a coordination number of six, an octahedral geometry is often observed. However, the coordination number doesn't just influence the shape; it can also impact the color, magnetism, and reactivity of the coordination compound. Understanding a complex's coordination number helps in predicting its physical and chemical properties, making it a key concept in inorganic chemistry.
Cis-Trans Isomerism
Cis-trans isomerism is a form of stereoisomerism that's particularly intriguing within coordination chemistry. This type of isomerism occurs when two identical or similar ligands are oriented differently around the central atom in an octahedral or square planar complex. In the 'cis' form, the like ligands are adjacent to each other, while in the 'trans' form, they are on opposite sides.

This seemingly small difference in spatial arrangement can lead to vastly varied properties, like solubility and reactivity. The classic example of cis-trans isomerism's importance is seen in the drug cisplatin, which is used in cancer treatment, whereas its trans isomer is ineffective in treating cancer.
Octahedral Complexes

Geometry and Ligand Arrangement

Octahedral complexes are six-coordinated structures forming an octahedron shape. The six ligands are symmetrically placed around the metal center at 90-degree angles from each other. This arrangement is one of the most common geometries in coordination chemistry and offers a perfect stage for the study of isomerism.

Geometrical Isomers

Given their symmetric property, octahedral complexes can give rise to geometrical isomers. The diverse spatial layouts of the ligands can result in compounds with distinct chemical properties despite having the same formula. These isomers include the cis and trans forms, as well as the less commonly discussed facial (fac) and meridional (mer) isomers, which refer to the arrangement of three identical ligands in these frameworks. Such isomerism plays a crucial role in the biological activity and chemical application of these compounds.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Name the following coordination compounds. a. \(\mathrm{Na}_{4}\left[\mathrm{Ni}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]\) b. \(\mathrm{K}_{2}\left[\mathrm{CoCl}_{4}\right]\) c. \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\) d. \(\left[\mathrm{Co}(\mathrm{en})_{2}(\mathrm{SCN}) \mathrm{Cl}\right] \mathrm{Cl}\)

The following statements discuss some coordination compounds. For each coordination compound, give the complex ion and the counterions, the electron configuration of the transition metal, and the geometry of the complex ion. a. \(\mathrm{CoCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) is a compound used in novelty devices that predict rain. b. During the developing process of black-and-white film, silver bromide is removed from photographic film by the fixer. The major component of the fixer is sodium thiosulfate. The equation for the reaction is: \(\begin{aligned} \mathrm{AgBr}(s)+2 \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}(a q) & \longrightarrow \\\& \quad\quad \mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}\right](a q)+\mathrm{NaBr}(a q) \end{aligned}\) c. In the production of printed circuit boards for the electronics industry, a thin layer of copper is laminated onto an insulating plastic board. Next, a circuit pattern made of a chemically resistant polymer is printed on the board. The unwanted copper is removed by chemical etching, and the protective polymer is finally removed by solvents. One etching reaction is: $$\mathrm{Cu}\left(\mathrm{NH}_{3}\right){ }_{4} \mathrm{Cl}_{2}(a q)+4 \mathrm{NH}_{3}(a q)+\mathrm{Cu}(s) \longrightarrow \\\ \mathrm{Cu}\left(\mathrm{NH}_{3}\right){ }_{4} \mathrm{Cl}(a q)$$

Draw all the geometrical isomers of \(\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2} \mathrm{BrCl}^{+} .\) Which of these isomers also have an optical isomer? Draw the various isomers.

Carbon monoxide is toxic because it binds more strongly to iron in hemoglobin (Hb) than does \(\mathrm{O}_{2}\). Consider the following reactions and approximate standard free energy changes: $$ \begin{aligned} \mathrm{Hb}+\mathrm{O}_{2} & \longrightarrow \mathrm{HbO}_{2} & \Delta G^{\circ} &=-70 \mathrm{~kJ} \\ \mathrm{Hb}+\mathrm{CO} \longrightarrow \mathrm{HbCO} & \Delta G^{\circ} &=-80 \mathrm{~kJ} \end{aligned} $$ Using these data, estimate the equilibrium constant value at \(25^{\circ} \mathrm{C}\) for the following reaction: $$ \mathrm{HbO}_{2}+\mathrm{CO} \rightleftharpoons \mathrm{HbCO}+\mathrm{O}_{2} $$

Rank the following complex ions in order of increasing wavelength of light absorbed. $$ \mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}, \mathrm{Co}(\mathrm{CN})_{6}^{3-}, \mathrm{CoI}_{6}^{3-}, \mathrm{Co}(\mathrm{en})_{3}^{3+} $$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free